An error occurred while running the simulation and the simulation was terminated

ошибка при моделировании в simulink входного потока для CPM модулятора Complex signal mismatch. Output port 1 of ‘mod1/Convert 2-D to 1-D1’ is a signal of numeric type complex. However, it is driving a signal of numeric type real Component:Simulink | Category:Model error Complex signal mismatch. Input port 1 of ‘mod1/CPM Modulator Baseband’ expects a […]

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  4. An error occurred while running the simulation and the simulation was terminated, Caused by: No differential equations found. Specify differential equations by using symbolic functions. please help regarding this issue.
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ошибка при моделировании в simulink входного потока для CPM модулятора

Complex signal mismatch. Output port 1 of ‘mod1/Convert 2-D to 1-D1’ is a signal of numeric type complex. However, it is driving a signal of numeric type real

Component:Simulink | Category:Model error

Complex signal mismatch. Input port 1 of ‘mod1/CPM Modulator Baseband’ expects a signal of numeric type real. However, it is driven by a signal of numeric type complex

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Спасибо за два ваших поста, но было бы неплохо помимо лога ошибки добавить какое-нибудь описание или задать вопрос.

p.s. В сообщении об ошибке черным по белому написано, что у вас происходят ошибки типизации. В первом сообщении написано что «port 1″ блока » mod1/Convert 2-D to 1-D1″ является комплексным сигналом однако управляется вещественным. А блок » CPM Modulator Baseband» ожидает вещественный сигнал, а ему передается комплексный.

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Спасибо за два ваших поста, но было бы неплохо помимо лога ошибки добавить какое-нибудь описание или задать вопрос.

p.s. В сообщении об ошибке черным по белому написано, что у вас происходят ошибки типизации. В первом сообщении написано что «port 1″ блока » mod1/Convert 2-D to 1-D1″ является комплексным сигналом однако управляется вещественным. А блок » CPM Modulator Baseband» ожидает вещественный сигнал, а ему передается комплексный.

Simulation 1 Clear

01:09 PM Elapsed: 0.938 sec

An error occurred while running the simulation and the simulation was terminated

Error in ‘mod1/CPM

Baseband’: When the ‘Input type’ parameter is set to ‘Integer’, inputs must be odd integers between -(M-1) and M-1 inclusive.

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An error occurred while running the simulation and the simulation was terminated, Caused by: No differential equations found. Specify differential equations by using symbolic functions. please help regarding this issue.

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  • No differential equations found. Specify differential equations by using symbolic functions.
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An error occurred while running the simulation and the simulation was terminated due to singularities in my Simulink model?

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  • Derivative of state ‘1’ in block ‘ pmsm_ini_dc_bus/PID Controller/Integrator/Continuous/Integrator ‘ at time 11.00046 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances)
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  • Block ‘BlockName’ outputs ‘NaN’ for element x of output port x at major time step 0
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Error on Simulink simulation

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An error occurred while running the simulation and the simulation was terminated Caused by:

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I keep getting the error below:

Continuous state ‘1’ of ‘untitled/Battery/Model/Current filter’ at time 0.00010049124961226976 is not finite. Simulink will terminate the simulation. There may be a singularity in the solution. Check the model ‘untitled’ for errors. Try reducing the fixed step size or tighten the error tolerances for variable-step solvers.

The image of the model is as below:

https://i.stack.imgur.com/zkCBl.png

https://i.stack.imgur.com/mVzr6.png

https://i.stack.imgur.com/2cDOW.png

beaker's user avatar

beaker

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asked Sep 6, 2021 at 21:17

Jibola's user avatar

1

I would need more information, but have you tried changing the solver parameters?
Usually with block from sympowersystems (or similar) I have better numeric performance using a stiff solver, like ode23tb.
To do so, go to your Model Settings (Ctrl + E), go to Solver, Select Variable Step Solver and in the droplist select ode23tb.

answered Sep 7, 2021 at 4:16

Manuel Merino's user avatar

1

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I have faced difficulty to write differential equation in Matlab function block. I have read many answers from here and also watched many lectures regarding this and I end up with some knowledge that I have implemented here. Please take a look and suggest me what should I do?

My objective is to implement following expression.

Basically following one is my model and the error is in Matlab function block.

Below one is the matlab function code that I have used.

function y = fun(u,Yb,e,b)
coder.extrinsic('function_code');
y = 2;
y = function_code (u,Yb,e,b);

Below one is the code for function_code

function b = function_code(u,Yb,e,b)
b0 = 5;
syms b t k
if b0>=4
    for k=1:20
    ode = diff(b,k) == Yb * u * e; 
    cond = b(1) == 2;   %if written b(0)-showing error
    b = dsolve(ode,cond);
    end





  



                       
  





elseif b0 == 4 && diff(b,t)*sign(b)>=0
    for k=1:20
    ode = diff(b,k) == Yb * u * e;
    cond = b(1) == 2;
    b = dsolve(ode,cond);
    end
else
    b = (0);
end
end

While running the silulation, It is showing error like…

An error occurred while running the simulation and the simulation was terminated

Caused by:

  • No differential equations found. Specify differential equations by using symbolic functions.

Please help me. I shall be highly obliged to you.

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assert() поддерживает настраиваемые сообщения об ошибках:

assert(cond,msg) выдает ошибку и отображает сообщение об ошибке, msg, если cond is false.

assert(cond,msg,A1,...,An) отображает сообщение об ошибке, которое содержит символы преобразования форматирования, такие как те, которые используются с функцией MATLAB® sprintf, если cond является false. Каждый символ преобразования в msg преобразуется в одно из значений A1,...,An.

assert(cond,msgID,msg) выдает ошибку, отображает сообщение об ошибке, msg и включает идентификатор ошибки для исключения, если cond является false. Идентификатор позволяет различать ошибки и контролировать, что происходит, когда MATLAB сталкивается с ошибками.

assert(cond,msgID,msg,A1,...,An) содержит идентификатор ошибки в исключении и отображает отформатированное сообщение об ошибке.

Поскольку у вас есть доступ к запускаемым скриптам, вы можете обновить их, чтобы включить подробные сообщения об ошибках.

Например:

>> assert((2+2) == 5)
Assertion failed.

против

>> assert((2+2) == 5, 'The rules of The Universe still hold')
Some rules of The Universe still hold

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$begingroup$

I am doing robotic arm simulation in Matlab Simulink but get the error. How I can resolve this.

enter image description here

My model given below.
enter image description here

Other details:
1. image of coordinates with world coordinates.
2. 6 DOF joint setting
enter image description here
enter image description here

asked Mar 2, 2017 at 6:04

Naseeb Gill's user avatar

Naseeb GillNaseeb Gill

3751 gold badge4 silver badges18 bronze badges

$endgroup$

5

$begingroup$

You cane find a detailed explanation on how to set the joint actuation types here. It seems that you need to set the torques as automatically computed, otherwise these are set to zero.

Furthermore, as it seems, the robot only moves in the x-y plane, but there is a z offset wrt the world coordinate system. Please make sure that this is handled correctly (you can use the same offset before the 6dof joint or you can allow for z axis movement)

answered Mar 5, 2017 at 7:54

50k4's user avatar

50k450k4

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$endgroup$

4

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