I’m trying to write a script that will vol up radio in the background
#!/bin/sh
for (( i = 80 ; i <= 101; i++ ))
do
amixer cset numid=1 i$% sleep 60;
done
But i have problem:
alarmclock-vol.sh: 3: alarmclock-vol.sh: Syntax error: Bad for loop variable
asked May 20, 2015 at 18:51
5
The for (( expr ; expr ; expr )) syntax is not available in sh. Switch to bash or ksh93 if you want to use that syntax. Otherwise, the equivalent for sh is:
#!/bin/sh
i=80
while [ "$i" -le 101 ]; do
amixer cset numid=1 "$i%"
sleep 60
i=$(( i + 1 ))
done
answered May 20, 2015 at 18:54
geirhageirha
5,6171 gold badge29 silver badges35 bronze badges
1
use bash instead of sh
bash alarmclock-vol
Sven Eberth
3,02712 gold badges23 silver badges28 bronze badges
answered May 30, 2021 at 14:22
try using
#!/usr/bin/bash
instead of
#!/bin/bash
answered Sep 26, 2021 at 4:15
1
Another way you can achieve this is by giving the file execution permission. Below are the commands:
Instead of sh filename.sh
Do this:
chmod +x filename.sh
./filename.sh
You can see in this 
for the same code that didn’t run with sh but runs after giving execution permission.
The shell script that I used here is:
#!/bin/bash
for ((i = 1; i <= 10 ; i++));
do
echo $i
done
answered Jul 6, 2022 at 3:54
When I’m using for like
for i in 1 2 3 4 5
then my file contains #!/bin/sh at the top.
But when I’m using
for(( i = 0; i<=5; i++))
then it is showing error
Syntax error: Bad for loop variable
and running properly when I remove shebang. Please tell me the reason behind this.
asked Jan 6, 2014 at 11:56
for(( i = 0; i<=5; i++)) is Bash specific and doesn’t work with plain Bourne shell (/bin/sh).
If you remove the shebang the script is run by your current shell (which likely is Bash) so it works.
Replace #!/bin/sh with #!/bin/bash to make the shebang work.
answered Jan 6, 2014 at 12:05
Florian DieschFlorian Diesch
84.6k17 gold badges223 silver badges214 bronze badges
3
I have solved this problem by using ./ instead of sh command.
For an example if you put sh test.sh instead just make your command as ./test.sh And most probably problem will be solved.
answered Nov 21, 2016 at 18:12
for(( i = 0; i<=5; i++))
for this type of loop only runs on Bash shell. so, if you want to run this, then try this command :
$bash filename.sh
I think It will work fine. and see this one also.
answered Mar 27, 2017 at 11:15
Sudip DasSudip Das
3002 silver badges10 bronze badges
Try this out may be this could solve your problem
#!/bin/bash
j=0
for (( i=1; i <= 5; i++ ))
do
echo "the loop is runing $i time: and value of j is $j"
j=`expr $j + 1`
done
answered Jan 16, 2014 at 11:55
smn_onrockssmn_onrocks
5265 silver badges14 bronze badges
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- script.sh: 1: Syntax error: Bad for loop variable
-
script.sh: 1: Syntax error: Bad for loop variable
Code:
for (( i = 0; i <= 4; i++ )) do echo $i done
-
Re: script.sh: 1: Syntax error: Bad for loop variable
/bin/sh is a symlink to dash, not bash.is a bash-ism, not recognized by dash.
So try either
PHP Code:
#!/bin/bash
for (( i = 0; i <= 4; i++ ))
do
echo $i
done
or
PHP Code:
#!/bin/shfor i in $(seq 0 4)
do
echo $i
done
-
Re: script.sh: 1: Syntax error: Bad for loop variable
Code:
for i in {0..4} do echo $i done
-
Re: script.sh: 1: Syntax error: Bad for loop variable
PHP Code:
#!/bin/bash
for (( i = 0; i <= 4; i++ ))
do
echo $i
done
PHP Code:
script.sh: 2: Syntax error: Bad for loop variable
-
Re: script.sh: 1: Syntax error: Bad for loop variable
Originally Posted by ghostdog74
Code:
for i in {0..4} do echo $i doneNot trying to use «for i in» syntex ,but the «for (( ))» syntex.
-
Re: script.sh: 1: Syntax error: Bad for loop variable
Originally Posted by colau
PHP Code:
#!/bin/bash
for (( i = 0; i <= 4; i++ ))
do
echo $i
done
PHP Code:
script.sh: 2: Syntax error: Bad for loop variable
After ./script.sh
After sh script.shPHP Code:
script.sh: 2: Syntax error: Bad for loop variable
-
Re: script.sh: 1: Syntax error: Bad for loop variable
Originally Posted by unutbu
/bin/sh is a symlink to dash, not bash.
is a bash-ism, not recognized by dash.
So try either
PHP Code:
#!/bin/bash
for (( i = 0; i <= 4; i++ ))
do
echo $i
done
or
PHP Code:
#!/bin/sh
for i in $(seq 0 4)
do
echo $i
done
Thank you.
Originally Posted by ghostdog74
