Codeforces compilation error

• 2 years ago, # ^ | +20 thanks for replying after 6 years

  • 2 years ago, # ^ | +8 Am still looking at comments though after 6 years haha

    • 21 month(s) ago, # ^ | 0 When u are submitting try to see which programming language is set.

      • 21 month(s) ago, # ^ | 0 The it liked MS C++, but I wanted to stick with GNU C++, so I refactored my code. I still got wrong answers afterward, but finally got an accepted answer at Submission #8759965 — Codeforces

        • 4 months ago, # ^ | 0 Did you get to solve the previous problem I ised -‘0’and it is giving compiler error

#include <iostream>
#include <stdio.h>
#include <algorithm>
using namespace std;
#define ll long long int
struct points{
ll a;
ll b;
};
int cos(points x , points y)
{
    return x.b<y.b;
}
int main()
{
   ll n,r,avg,i,j,k;
   points pt[100005];
   cin>>n>>r>>avg;
   for(i=0;i<n;i++)
   {
       cin>>pt[i].a>>pt[i].b;
   }
   sort(pt,pt+n,cos);
   ll sum=avg*n;
   for(i=0;i<n;i++)sum-=pt[i].a;
   if(sum<=0)cout<<"0n";
   else
   {

   ll ans=0;
   for(i=0;i<n;i++)
   {
       if(sum==0)break;
       else
       {
           if(sum>r-pt[i].a)
           {
               ans=ans+pt[i].b*(r-pt[i].a);
               sum=sum-(r-pt[i].a);
           }
           else
           {
               ans=ans+sum*pt[i].b;
               sum-=sum;
           }
       }
   }
   cout<<ans<<endl;
   }
    return 0;
}

4

A and B are preparing themselves for programming contests.

B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.

Initially, the compiler displayed n compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix some mistake and then another one mistake.

However, despite the fact that B is sure that he corrected the two errors, he can not understand exactly what compilation errors disappeared — the compiler of the language which B uses shows errors in the new order every time! B is sure that unlike many other programming languages, compilation errors for his programming language do not depend on each other, that is, if you correct one error, the set of other error does not change.

Can you help B find out exactly what two errors he corrected?

Input

The first line of the input contains integer n (3 ≤ n ≤ 10⁵) — the initial number of compilation errors.

The second line contains n space-separated integers a₁, a₂, …, a_n (1 ≤ a_i ≤ 10⁹) — the errors the compiler displayed for the first time.

The third line contains n - 1 space-separated integers b₁, b₂, …, b_n - 1 — the errors displayed at the second compilation. It is guaranteed that the sequence in the third line contains all numbers of the second string except for exactly one.

The fourth line contains n - 2 space-separated integers с₁, с₂, …, с_n - 2 — the errors displayed at the third compilation. It is guaranteed that the sequence in the fourth line contains all numbers of the third line except for exactly one.

Output

Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively.

Sample test(s)

5
1 5 8 123 7
123 7 5 1
5 1 7

6
1 4 3 3 5 7
3 7 5 4 3
4 3 7 5

Note

In the first test sample B first corrects the error number 8, then the error number 123.

In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step.

This topic is actually done last week. Today, I just encountered it, I wrote it.

When you write on Sunday, use sort, scanning methods, easy to think. This approach is JS, gives each set, and a set of and a set of sums is the answer.

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstring>
 4 #include <algorithm>
 5 using namespace std;
 6 
 7 int main()
 8 {
 9     int n, read;
10     int sum1, sum2, sum3;
11     sum1 = sum2 = sum3 = 0;
12     scanf("%d", &n);
13     for(int i = 0; i < n; i++)
14     {
15         scanf("%d", &read);
16         sum1 += read;
17     }
18 
19     for(int i = 0; i < n-1; i++)
20     {
21         scanf("%d", &read);
22         sum2 += read;
23     }
24     cout << sum1 - sum2 << endl;
25 
26     for(int i = 0; i < n-2; i++)
27     {
28         scanf("%d", &read);
29         sum3 += read;
30     }
31 
32     cout << sum2 - sum3 << endl;
33     return 0;
34 }

Следующий код работает нормально, пока я использую его в своем приложении блоков кода. Однако при решении проблемы «Четные шансы» в Codeforces путем отправки того же кода я получаю ошибку компиляции.

Ошибка: недопустимое преобразование из ‘void *’ в ‘long long int *’ [-fpermissive]

Я новичок в программировании на C. Итак, пожалуйста, помогите мне, как я могу исправить этот мой код.

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main(){
long long *arr, n, k, i, n1, n2, m;
scanf("%I64d%I64d", &n, &k);
arr=malloc(sizeof(long long)*n);
    n1=1;n2=2;
for(i=0;i<=n/2&&n1<=n;i++){
    arr[i]=n1;
    n1+=2;
    }
if(n%2!=0) m=n/2+1;
else m=n/2;
for(i=m;i<=n&&n2<=n;i++){
    arr[i]=n2;
    n2+=2;
    }
printf("%I64d", arr[k-1]);
free(arr);

return 0;
}

В кодовых блоках вы должны компилировать его как файл c. Но в Codeforces код компилируется как cpp.

arr=malloc(sizeof(long long)*n);

Когда вы компилируете эту строку на C, malloc выдаст указатель void*, который будет автоматически преобразован в long long*

Но в случае cpp явное преобразование должно выполняться. Чтобы запустить код в cpp:

arr = (long long*)malloc(sizeof(long long) * n);

Это сработает. Прочтите эту статью для получения разъяснений.