Contents
- Introduction
- Types of errors in VBA
- Syntax Error
- Compile Error
- Run Time Errors
- Possible reasons for the “Expected: end of statement” error
Introduction
Every programming language has its own grammar and vocabulary — technically known as syntax. Having a mastery of any language implies that you have a sound knowledge of its syntax.
As a beginner in VBA, you might be confronted with frustrating errors like the “Expected: end of statement” error. Be rest assured, no matter how experienced you’re with VBA coding, errors are always going to be a part of it.
The difference between a novice and an expert VBA programmer is that the expert programmers know how to effectively handle and use errors. This article will help you better understand the error above.
Types of errors in VBA
There are three types of errors in VBA: syntax errors, compile errors, and runtime errors.
Syntax Error
A syntax error, as you can guess from the name, occurs when VBA finds something wrong with the syntax in your code. When you type a line of code, VBA checks if the syntax is correct.
As soon as you hit enter, if VBA finds that something is missing in the syntax, it instantly shows a message with some text that can help you understand the missing part, as you can see in the screenshot below:
Note: You need to enable the ‘Auto Syntax Check’ in the VBA option for the error dialog box to appear when there is an error. If not, VBA will only highlight the line without showing the error dialog box. The gif below shows you how to enable the error dialog box in VBA.
Compile Error
Compile errors occur when something is missing that is needed for the code to run. For example, in the code below, as soon as you run the code, it will show an error.
Note the difference between the syntax error and the compile error. The syntax error occurs even before you run the code and the font of the problematic line turns to red. The compile error occurs when you try to run the code and VBA identifies that something is missing.
Run Time Errors
Runtime errors are those that occur when the code is running. Run time errors will occur only when all the syntax and compile errors have been taken care of. They are not due to errors in the code itself, but rather due to factors external to the code — like a wrong input by the user, or an object that is not existing.
For example, if you run code that is supposed to activate an Excel worksheet, but that worksheet is unavailable (either deleted or its name changed), your code would give you a runtime error.
Unlike with the two previous errors, when a runtime error occurs, the message in the Run-time error dialog box is a little more explicit because it explains the problem and that can help you correct it.
Coming back to our specific error (“Expected: end of statement”), let’s write and run some code that will generate the error.
Step 1: Open the Visual Basic Editor and create a new module as seen in the gif below.
Step 2: Write or copy and paste the following code:
Sub GenerateError() Dim i As Integer = 5 End Sub
Before you even run the code, you will have the following result:
The error comes from the fact that two statements have been written in one line instead of two. The code should be:
Line 1: Dim i As Integer
Line 2: i = 5
Possible reasons for the “Expected: end of statement” error
From the types of errors in VBA described above, you must have guessed that the “Expected: end of statement” error is a syntax error. As such, the possible reasons for the error are as varied as the number of mistakes that you can make while writing a line of code.
Without being exhaustive, below is a list of possible reasons for that error:
1) Writing two statements in one line (see the example above)
How to fix: Check to see if two different statements have inadvertently been put on the same line then send the second statement to a new line.
2) Absence of parentheses
How to fix: Make sure you have parentheses (both open and close) where necessary.
3) Absence of white space
How to fix: Any identifier that is immediately followed by a &
, like name&
and affiliation&
, is interpreted as a Long variable, so the lack of whitespace in front of the concatenation operator (&) is causing a parse error. To solve the problem, you just need to put a space between the variables and the concatenation operator. Instead of writing name&
, write name &
.
Nechaevvs Пользователь Сообщений: 6 |
Добрый день! Прикрепленные файлы
|
Слэн Пользователь Сообщений: 5192 |
внутри кавычек кавычки нужно удваивать |
Nechaevvs Пользователь Сообщений: 6 |
Это большой шаг вперед для меня =) |
Nechaevvs Пользователь Сообщений: 6 |
Upd, при указании двойных кавычек внутри кавычек ошибка «Compile error: Expected: end of statement» — ушла. Прикрепленные файлы
|
RAN Пользователь Сообщений: 7081 |
Вы пишете «Formula =» |
Nechaevvs Пользователь Сообщений: 6 |
#6 22.07.2016 18:05:32 Спасибо огромное. |
I have the following calcScores function written:
Function calcScores(category As String) As Integer
Dim count As Integer
count = 0
For Each Ctl In UserForm1.Controls
If Ctl.Tag = category And TypeName(Ctl) = "CheckBox" Then
Dim box As MSForms.CheckBox
Set box = Ctl
If box.Value = True Then
count = count + 1
End If
End If
Next
calcScores = count
End Function
This function takes a tag named «category» as a string and then checks the form for all check boxes with that tag and counts the ones that are checked. I know it works and counts the right number, because I have slightly edited it to output it’s value to a label on the form instead of returning it.
When I try to call it in another function like this:
Function sortScores()
Dim scores(0 to 5) as Integer
scores(0) = calcScores "rChk"
**CODE CONTINUES**
End Function
I get an error that says «Expected: End of Statement» as soon as I leave the line that assigns the function’s return to scores(0). calcScores is assigned before sortScores, and was succesfully called in a sub before using the same syntax.
Any idea what the error could be?
Return to VBA Code Examples
This tutorial will explain what a VBA Compile Error means and how it occurs.
Before running your code, the VBA Editor compiles the code. This basically means that VBA examines your code to make sure that all the requirements are there to run it correctly – it will check that all the variables are declared (if you use Option Explicit which you should!), check that all the procedures are declared, check the loops and if statements etc. By compiling the code, VBA helps to minimize any runtime errors occurring.
(See our Error Handling Guide for more information about VBA Errors)
Undeclared Variables
If you do not declare variables, but your Option Explicit is switched on at the top of your module, and then you run the macro, a compile error will occur.
If you click OK, the relevant procedure will go into debug mode.
Alternatively, before you run your code, you can force a compilation of the code.
In the Menu, select Debug > Compile Project.
The compiler will find any compile errors and highlight the first one it finds accordingly.
Undeclared Procedures
If you code refers to a procedure that does not exist, you will also get a compile error.
For example:
Sub CallProcedure()
'some code here then
Call NextProcedure
End Sub
However, if the procedure – NextProcedure does not exist, then a compile error will occur.
Incorrect Coding – Expected End of Statement
If you create a loop using For..Each..Next or With..End With and forget to and the Next or the End With… you will also get a compile error.
Sub CompileError()
Dim wb As Workbook
Dim ws As Worksheet
For Each ws In wb
MsgBox ws.Name
End Sub
The same will happen with an If statement if the End If is omitted!
Missing References
If you are using an Object Library that is not part of Excel, but you are using the objects from the library in your variable declaration, you will also receive a compile error.
This can be solved by either Late Binding – declaring the variables are Objects; or by adding the relevant Object Library to the Project.
In the Menu, select Tools > References and add the relevant object library to your project.
VBA Coding Made Easy
Stop searching for VBA code online. Learn more about AutoMacro — A VBA Code Builder that allows beginners to code procedures from scratch with minimal coding knowledge and with many time-saving features for all users!
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description | title | ms.date | f1_keywords | helpviewer_keywords | ms.assetid | ||
---|---|---|---|---|---|---|---|
Learn more about: BC30205: End of statement expected |
End of statement expected |
07/20/2015 |
|
BC30205 |
53c7f825-a737-4b76-a1fa-f67745b8bd40 |
The statement is syntactically complete, but an additional programming element follows the element that completes the statement. A line terminator is required at the end of every statement.
A line terminator divides the characters of a Visual Basic source file into lines. Examples of line terminators are the Unicode carriage return character (&HD), the Unicode linefeed character (&HA), and the Unicode carriage return character followed by the Unicode linefeed character. For more information about line terminators, see the Visual Basic Language Specification.
Error ID: BC30205
To correct this error
-
Check to see if two different statements have inadvertently been put on the same line.
-
Insert a line terminator after the element that completes the statement.
See also
- How to: Break and Combine Statements in Code
- Statements
“End of statement expected” is a common error that appears when using Python. When you are trying to write something like this, you’ll see “end of statement expected”, as the syntax looks very strange.
So, how to solve end of statement expected python error? This article is all about the syntax of Python statements. We are going to learn when to use a statement and when not to use it.
We will also discuss some statements that should be avoided. We will go through several examples to understand the statement syntax.
What is End of Statement Error?
When you are writing Python, there are different types of statements that could appear on your machine. The first statement we will look at is the “end-of-statement” error.
What this means is that a programmer misspelled some keywords in their code and thus ended up with this error when trying to run it as an interpreter.
Let’s see more about what exactly happens here: The computer can tell which parts of the program came from human and which are the keywords of Python.
The IF-statement, for example , is a keyword and is always written this way on every line by an experienced programmer so that it becomes obvious that a function came from human.
But then there comes another person who does not know everything about computer or programming language he/she would write “else” instead of elseIf.
How To Solve End Of Statement Expected Python Error?
This is the syntax of a Python statement called “if”. The following word tells you that this test will happen at the end.
Now, let’s take another example: function name def and class are keywords in Python. When we put these statements, they must be written as keywords with ending punctuation such as , or . If you misspell any part of those declarations then what happens?
The answer lies on how exactly your code ends up with “Basic Syntax Error”. It always depends on how we punctuate this keyword definitions, misspellings etc.
This is all about syntax and syntax errors are usually related to spelling when the real error might be in a previous statement of function/code.
Examples: If you want to write an IF-statement, then you need two consecutive lineds with word “if” like so: def my_loops(x): if x % 2 == 1: # doer elif x % 4 == 3 : # loop statement else: print(“Cannot be a drawn number”)
If you misspell this as follows “my loops function” then Python can tell that one of your keywords was not declared properly or somehow.
It will give error message like so when running the code at interpreter level:- ERROR trying to load /usr/local/python2634-67R /python.exe: ELLECould not load /usr/local/python2634-67R/python.exe message and the error will look like so below whenever you try to run your code:- Traceback (most recent call last):
File “save2rst1” , line 8, in <module> … invalid syntax ERROR trying to import my_Loops errors are neither good nor bad things when they occur while coding because they tell us about an error in our code.
They are good because they take place where you don’t want them to occur i.e the compiler level and not while executing a program on your computer, so everything work fine!
There are a several cause that can make these issue complicated. For example:
The source code is written in following way:- def my_loops(x): if x % 2==1 : # doer elif x % 4 == 3 : # loop statement else print(“Cannot be a drawn number”)
The error message that comes on your screen would look like this below when you run the program at interpreter level. ERROR trying to load /usr/local/python2634-67. However now we will show you some simple way to solve the errors.
Solution-1
This error is pretty simple; it’s telling you that the code currently has a problem at that point – therefore it should not be executed.
When you see this, you will have to work out what the issue with your program is before continuing or moving on to another section of the book (if needed).
The easiest way to do this is restarting Python 3.6 from your terminal window and typing in:
python3 Python Version 3 .6 .0b5 -a python : 2>&1 1 > & 1
This tells us where the error was and allows us to take a step back and see what the problem is that has caused this error.
After restarting your interpreter you will notice that Python 3 version 2 is no longer invoked, therefore you can attempt to run your code in python3 or any other of its versions (pip install –upgrade works just fine)
Hopefully the issue lies within one of those two commands rather than within our main if block. If it’s mainly due to the if statement, check and double-check the code that you think may be causing it. Often it’s not a big deal at all – for example like this:
if x != 1 : y = 2 print(“It is impossible”) else : print(“[#] Success!”) Once Java SE 8u131 has been installed on your machine you will have to take care of any dependency issues with Visual Studio because until then… “Note : Before installing Visual Studio 2015, check whether it and the other components are supported by your system.
Solution-2
To Solve ‘End of statement expected’ in pycharm Error Try print with parenthesis in Python3 i.e. print(x) instead of print x
If you work on Django, Microsoft Word, Apache server or any terminal application that accepts input and outputs the appended output as command line then do not worry a lot about this error message cause it has one simple solution to debug.
Type a output at the Python interpreter and you will see if there is any valid source code on your computer that can be used as solution of whether this error occurs or not.
If no such thing exists then it means the “ProgrammingError” mention in your log messages issues has likely been stuck without user options to solve but don’t panic, try typing something out more readable like (x=1) instead of print x, same way as if you were in a debugging scenario here is your solution.
First and foremost, figure out how the error happens so that if you re-enter the same code with different options but no fatal errors occur then it won’t trigger this error again during program execution, which means we have to look at where these invalid characters appear from within Vim (if possible), i.e.:
=> vim ~/ProgrSource/MonitorMonit OrFileLogger.py
=> vim ~/ProgrSource/MonitorMonitOrFileLogger.py~
or edit or insert into Vim with the :e command, and look for lines that contain a litany of invalid characters like: ‘ddaa’ or any other such cases which are commonly seen in indentation-related error messages when users run their web based applications through default Python shell (i.e.: ” VirtualEnv”) and don’t use their preferred “Source Map”.
Once you obtain this necessary information that indicates the exact point of failure, do not move on to re-run your application by entering command again but instead look up at Vim error window through which vim:fix gave out suggestion as shown below. Once ” Vim” is highlighted and you hit the tab key to activate input of a prefix command then:
=> vim GoGoato!.py~nDZQqhfJwd I9YrMUt60HgkbRpK1Cmv12THW4 If you don’t see any error message yet but instead get an interactive prompt (“>”) that would give me: Traceback (most recent call last): File “GoGoato!.py”, line 9, in <module> main()
=> vim GoGoato!.py
<main>’DZQqhfJwd I9YrMUt60HgkbRpK1Cmv12THW4 :: no match for ‘::’,.! found You will notice that this error has a working solution by using the Vim command which is given below. Alternatively, you can use Vim’s built-in fixup script which is: :fixWild
But this command won’t help if the error occurs inside a sequence of characters that are commonly used for indentation like “::” or such other cases in online development workshop when users run their web application through default Python shell (i.e.: ” VirtualEnv”).
We need to isolate these type specific errors from our code and then send only the proper ones to vim:fix that wouldn’t be altered by other unwanted character sequences. That’s the reason why we are looking for a way in which to get rid of “::” as first step toward our solution —
Type commands at cam–> (Insert Mode) screen Get command history with up arrow and typing some common indentation characters like ‘{‘ or ‘}’. Try inserting those characters amond your code Now see the “” or ”
This is the error that :fixWild can’t handle. Let us apply this fix with Vim command ‘undo’ to remove all unwanted character sequences like below: <0aq>gogoato!^/PQoHakF2VLCIyNenl +wv66YhCps8q9KDZtMkr+RKo I anticipate whether there are some common break.
Solution-3
End of statement expected is supposed to be at the end of the line. Python is a dynamically typed and interpreted high-level programming language.
To paraphrase probably the most famous Python versus Java quote: it’s all about the paradigm, not about what language you use.
With this in mind, I’ve decided to write some examples that show how easy it is to work with variables of different types when dealing with lists of strings or even other sets of variable types that can contain strings as well these variable types can be inline/constant variables (class constants).
One was trying to pass an array which contained string data into a function where something else needs to happen. Since this was an array of strings I used a list instead as you see below.
Python is /o7m9i/1,2 While executing this code there are following errors: raise RuntimeError(“Something went wrong with {!r}”, e)
Frequently Asked Questions
End of Statement Expected Error : What to Do?
This can happen for different reasons. Just make sure that variable names is good and final, not self-testable (which means variables should be used with correct types). Version: python 2.7 and above Avoiding Most Common Pitfalls.
How Do I End a Statement in PyCharm?
Go to Run/Debug configuration and click on the error marker or red cross. Change “Close the current pane” for “Display inline fixups”. Program terminated by an uncaught exception.
Please submit a bug report efile languages from sys ImportError: No module named ‘sys’ . It seems it caused because of importing modules as if they
What Does Expected Mean in Python?
The expected usage form indicates that the code should be executed with exactly one error. That is, it is not needed to type “raise” at the end of all variable declarations.
What Does Expected Mean in Python?
Using the “expected” variable error marker can be a great help, because it lets PyCharm find all errors that are not caught by the try/except block.
While some of them might not produce any or solely occur in this context they will still clearly show up and provide warnings – without confusion Of course raising an exception is also considered allowed.
What Is Expected-Error In Python Statement?
In Python, an expected error is a compiler warning or exception you might encounter while coding. This can result from incorrect syntax, misspelled keywords, or ambiguity in your code. When you encounter an expected error, it can be frustrating because you don’t know how to fix the issue. However, a few tips will help you resolve the problem.
Final Thought
The Python language is a high-level dynamic programming language that can be used to quickly write and execute code. The Python interpreter is dynamically typed and interprets each program in a way which makes it easy to adapt to the context of its use.
This allows the developer to define functions or procedures without specifying how they should behave or what type of data they should expect.
The result is a flexible and robust programming environment that can be used for many types of programming. I hope now you understand how to solve end of statement expected python error.
-
#2
Maybe this?
Cells(4, 34).Formula = «=IF(G4=»»no data»»,0,AG4*AE4*-1)»
-
#3
perfect.
Thanks a lot
marco
-
#4
perfect.
Thanks a lot
marco
No problem.
By the way, Welcome to the MrExcel board!
-
#5
Hi there,
I’m new to MrExcel and I have a similar challenge!
I have written the following code and receive a ‘Compile error: Expected end of statement’ message too…
Range(«L22»).Select
If ActiveCell.Formula = «True» Then
ActiveSheet.Outline.ShowLevels RowLevels:=1
Else ActiveCell.Formula = «False» Then
ActiveSheet.Outline.ShowLevels RowLevels:=2
End If
End Sub
Any assistance would be greatly appreciated.
Cheers
-
#6
«Else» does not require a «Then» statement. Else means — if you get here do this. Remove the «ActiveCell.Formula = «False» Then» and you should be good.
-
#7
Hi,
I am trying to build a formula in VBA bu getting the same error on the following line:
rng3.Formula=»=IF(AY»&j&»=»»Failed»»,1,0)»
Here, rng3 is a defined range, and j is an integer to pick row number.
Can you please help.
RoryA
MrExcel MVP, Moderator
-
#8
You are missing spaces:
Code:
rng3.Formula = "=IF(AY" & j & "=""Failed"",1,0)"
-
#9
You are missing spaces:
Code:
rng3.Formula = "=IF(AY" & j & "=""Failed"",1,0)"
That was a pretty silly mistake.
Thanks.
-
#10
I’m trying to set a formula in a spesific field
‘This code insert the formula
Dim Formula As String
Formula = _
«=COUNTA(F2:F25000)»
Range(«R2»).Formula = Formula
‘This code not inset the formula [Runtime Error 1404 «Application-Deffined or Objet-Deffined error]
Dim Formula As String
Formula = «=IF(AND(C2=»»,A2<>»»CC»»,A2<>»»PF»»,A2<>»»PU»»,A2<>»»40″»),16,A2)»
Range(«P2»).Formula = Formula
any know why?
Thanks.
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-
Question
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Hi All,
I’m trying to adapt my query sql to use in vba & my brain is closing down. I keep getting the compile error: Expected: End of statement. The last time I encountered this message I was able to figure out the quotes but this is a different syntax using
Dlookup in the sql string.Can someone help me past this brain blockage (can’t see the wood for the trees comes to mind)
Here is the code string
strSQL = «UPDATE [tblResultsImported] » _
strSQL = strSQL & «SET tblResultsImported.CouplesInClass = DLookUp(«CountOfClass»,»qryImportClassCount»,»class = ‘» & [class] & «‘»);»
Answers
-
Either remove the _ continuation from the first row, or make it all one continuation; and remember that each open quote will require a matching close quote. The » before CountOfClass is being read as the closing quote for the one before SET.
Try
strSQL = «UPDATE [tblResultsImported] SET tblResultsImported.CouplesInClass = » _
& «DLookUp(«»CountOfClass»»,»»qryImportClassCount»»,»»class = ‘»» & [class] & «»‘»»);»using the fact that you can include a doublequote in a doublequote delimited string by using a doubled doublequote (a fine example of doubletalk!)
John W. Vinson/MVP
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Marked as answer by
Thursday, September 23, 2010 5:08 AM
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Marked as answer by