Error in port widths or dimensions матлаб

Hi, I am getting error like"Error in port widths or dimensions. Output port 1 of 'Furutroo/Compensator/y' is a one dimensional vector with 4 elements." I am using state-space block with single i/p ...

Kaustubha Govind

Your input to the State-Space block has a dimension of 1×4, but B has dimensions 2×2 — this doesn’t make sense because you can’t multiple a 2×2 matrix with a 1×4 vector. Your input must be a vector of 2 elements as Guy suggested.

Guy Rouleau

I don’t know where the 4 comes from in your error message, but your B and D matrices have 2 columns, so your system should have 2 inputs.

Try leaving unconnected or grounded lines where the error is and display the signal width (from the format menu). this should help understanding what’s going on.

java python

I have a simulink model of UAV model which ran fine in 2010b and 2012a model in my school’s computer. But when run exact same block in 2012b, it guves me the error message ,»Error in port widths or dimensions. Output port 1 of ….» . In the bottom window, it says «Error in port widths or dimensions. Input port 1 of ‘sldSim/sldDynamics/MATLAB Fcn’ has 17 elements. This port does not accept the dimensions (or orientation) specified by the input signal.»

I don’t see any non-uniformity with the dimensions. Even if there was a problem why would it run in previous versions ? Does 2012b simulink has any bugs ? Please help me .

Md Rakibul

I have similar problem but not related to input/matrix size. One of my file works in my workplace MATLAB but does not work in my personal laptop. it gives «Error in port widths or dimensions. Output port 1 of ‘ueki1/control+robot/robot/f1/Invm*(tau-C-g)’ has 3 elements. This port does not accept the dimensions (or orientation) specified by the output signal.» But I know there are no errors in dimensions. Previously I solved this problem by removing extra sign in summation block. Lets say you added 3 inputs in summation block. Then you decided to remove one input but kept the summation block as +++ instead of ++ which gives problem in dimension. It worked last time. But this time still been trying to look in the file for the same issue. But did not find anything like that. Any Idea please GUY or Kausthuba?

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The Matlab function named C generates a matrix with 3×3 dimension. I have to product it with the vector 1×3 made with the mux of sources n_x, n_y, n_z.

enter image description here

However, running this model causes two errors:

Error in port widths or dimensions. Invalid dimension has been
specified for input port 2 of ‘untitled/Product’.

Error in port widths or dimensions. Output port 1 of ‘untitled/C’ is a
[3×3] matrix.

Could you please explain me what’s wrong with it?

asked Apr 27, 2019 at 9:46

luckystrrrike's user avatar

The problem is solved. All I had to do is to swap the production block inputs and set the Matrix* value in «Multiplication» property in the block settings.

enter image description here

answered Apr 27, 2019 at 10:25

luckystrrrike's user avatar

1

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Semenov asked . 2021-09-28

I need to make DCT image compression in Simulink. Image size by default has 3 dimensions, so I used reshape tool to remove the third dimension. Color Space Conversion tool only accepts 3 dimensional images, so I used reshape again.

When I try to run the simulation, I get two following errors:

Error in port widths or dimensions. ‘Input Port 1‘ of ‘untitled/Reshape1‘ has 786432 elements. This port does not accept the dimensions (or orientation) specified by the input signal.

I thought reshape was supposed to accept any matrix as an input.

simulink , reshape , dct ,error , image compression

Prashant Kumar answered . 2023-02-09 14:01:19

The purpose of Simulink’s Reshape block and MATLAB’s reshape command is only to «reinterpret» the dimensions (aka size) of the signal/variable. The number of elements is not changed. The values as they would appear in the «flat memory» of the computer would also be unchanged.

Your usage doesn’t fit the reshape behavior. Your input to the first reshape block has this many elements.

inputNumel = prod([512,512,3])
inputNumel =
      786432

Your desired output has this 1/3 as many elements.

outputNumel = prod([512,512])
outputNumel =
      262144

Since you are trying to change then number of elements, the reshape block is throwing an error.

One approach to solve this is to put the following code into a MATLAB Function block

function [Y,Cb,Cr] = splitData(u)
      Y = u(:,:,1);
      Cb = u(:,:,2);
      Cf = u(:,:,3);
end

But there is probably a simpler way to achieve your high level goal using capabilities of Image Processing Toolbox.

Not satisfied with the answer ?? ASK NOW

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Port Dimensions error, embedded Matlab/constant block

Port Dimensions error, embedded Matlab/constant block

(OP)

8 Jun 09 06:38

Hi,

I hope you can help.  I am trying to set up a test of an imbedded Matlab function I have produced.  I have it set up with a series of constant blocks that get their values from an initialisation script.

Whenever I run it, I get the following error:

??? Error using ==> sim
—> Error reported by S-function ‘sf_sfun’ in ‘initTest/chebyInit/chebyInit/ SFunction ‘:
Errors occurred during parsing of Embedded MATLAB function ‘chebyInit/chebyInit'(#161).
—> Error in port widths or dimensions.  Output port 1 of
‘initTest/chebyInit/chebyInit/chebyTcOrderVec’ is a one dimensional vector with 1 elements.

ChebyTcOrderVec is an input port which gets its values from a constant block of the same name and which I would expect to be a 1 dimensional vectore with one element as it just takes in an integer value.

The code for the set up is below, I’m not sure how helpful it will be.  All the variables in the script below are then used as constant values from constant blocks. If you need any more information please do let me know as I am stumped and would really appreciate some assistance.  Thanks, Robyn

%% Set up Case Specific Values

        chebyTcSegStart = 19;
        chebyTcSegEnd = 210;
        chebyTcOrderSca = 7;
        chebyTcOrderVec = 7;
        tSwitch = 20.1;
        orderMax = 9;

%% Profile 2

% Define the second set of conditions:
% Definition of the arbitary axis:
u2 = [3 0 1];
u2 = u2/norm(u2);
u2 = u2′;

%deffinition of the angle (a)
t2 = -1:0.01:1200;
a2 = sin(t2/100);

s2 = cos(a2/2);
u2 = u2* sin(a2/2);

qhist_B = [s2; u2];
qhist_B = qhist_B’;

% segStart_B = 200;
% segEnd_B = 1000;

% generate the coefficients
coeff1 =compute_chebychev_coef_v2(t2,qhist_B,1,chebyTcOrderSca+1,chebyTcSegStart,chebyTcSegEnd);
coeff2 =compute_chebychev_coef_v2(t2,qhist_B,2,chebyTcOrderVec+1,chebyTcSegStart,chebyTcSegEnd);
coeff3 =compute_chebychev_coef_v2(t2,qhist_B,3,chebyTcOrderVec+1,chebyTcSegStart,chebyTcSegEnd);
coeff4 =compute_chebychev_coef_v2(t2,qhist_B,4,chebyTcOrderVec+1,chebyTcSegStart,chebyTcSegEnd);

%Define the input values for profile 2
chebyTcCoefSca = coeff1;
chebyTcCoefVec = [coeff2, coeff3, coeff4];

%% run Init Block
sim initTest

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