Error in unapply variables must be unique and of type name

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в моем коде дельта является величиной, изменяющейся с определенным шагом в зависимости от числа итераций N

restart; Digits := 21; alpha := 0.1e-1; delta1 := -0.1e-1; delta2 := 0.2e-1; N := 1000; epsilon := 1/100; delta3 := -0.12e-1; delta4 := delta2; N1 := 1000;

M := []; Mg := []; Ml := []; Mh := [];

for i from 0 to N do

delta := delta1+(delta2-delta1)*i/N; y1 := 3+delta;

f := -(y1^2+alpha^2+2*alpha^2/y1)*y7^2+4*alpha*y7*y8/y1+(1-2/y1)*y8^2-1;

d := (alpha^2-y1^3)*y7^2 -2*alpha*y7*y8 +y8^2 -3*alpha*epsilon*(y1^2+alpha^2)*y7^2/y1^2+3*epsilon*(y1^2+2*alpha^2)*y7*y8/y1^2-3*alpha*epsilon*y8^2/y1^2+alpha*epsilon*(3*y1^2+alpha^2)*(y1^3-alpha^2)*y7^4/y1^3-alpha*epsilon*(1-2/y1)*y8^4/y1^3+epsilon*(y1^6-3*y1^5-3*alpha^2*y1^3+9*alpha^2*y1^2+4*alpha^4)*y7^3*y8/y1^3+alpha*epsilon*(3*y1^3-11*y1^2-6*alpha^2+2*alpha^2/y1)*y7^2*y8^2/y1^3+epsilon*(4*alpha^2-4*alpha^2/y1-y1^3+3*y1^2)*y7*y8^3/y1^3;

s := RootFinding[Isolate]({d, f}, [y7, y8]);

L := [];

for j to nops(s) do if `and`(rhs(s[j, 1]) >= 0, rhs(s[j, 2]) >= 0) then L := [op(L), s[j]] end if end do;

if nops(L) = 0 then h := [] else h := L[1];

for k to nops(L)-1 do if rhs(L[k+1, 2]) >= rhs(h[2]) then h := L[k+1] end if end do end if; h;

if nops(L) = 0 then hl := [] else hl := L[1];

for j to nops(L)-1 do if rhs(L[j+1, 2]) <= rhs(hl[2]) then hl := L[j+1] end if end do end if; hl;

if nops(h) > 0 then M := [op(M), [delta, rhs(h[1])]] end if;

if nops(hl) > 0 then Ml := [op(Ml), [delta, rhs(hl[1])]] end if end do;

for i from 0 to N1 do delta := delta3+(delta4-delta3)*i/N1; y1 := 3+delta;

f := -(y1^2+alpha^2+2*alpha^2/y1)*y7^2+4*alpha*y7*y8/y1+(1-2/y1)*y8^2-1;

d1 := (alpha^2-y1^3)*y7^2 -2*alpha*y7*y8 +y8^2 -3*alpha*epsilon*(y1^2+alpha^2)*y7^2/y1^2+3*epsilon*(y1^2+2*alpha^2)*y7*y8/y1^2-3*alpha*epsilon*y8^2/y1^2;

d2 := (alpha^2-y1^3)*y7^2-2*alpha*y7*y8+y8^2; sg := RootFinding[Isolate]({d2, f}, [y7, y8]);

Lg := [];

for j to nops(sg) do if `and`(rhs(sg[j, 1]) >= 0, rhs(sg[j, 2]) >= 0) then Lg := [op(Lg), sg[j]] end if end do;

if nops(Lg) = 0 then hg := [] else hg := Lg[1];

for k to nops(Lg)-1 do if rhs(Lg[k+1, 2]) >= rhs(hg[2]) then hg := Lg[k+1] end if end do end if; hg;

if nops(hg) > 0 then Mg := [op(Mg), [delta, rhs(hg[1])]] end if end do:

g := unapply(CurveFitting[Spline](M, delta, degree = 1), delta)

Error, (in unapply) variables must be unique and of type name


plot(piecewise(`and`(-0.116e-1 < delta, delta < -0.769e-2), M, `and`(-0.769e-2 < delta, delta < -0.56e-2), «, `and`(-0.56e-2 < delta, delta < 0), M), delta=-0,012..-0,0002,, scaling = constrained, thickness = 2, discont = true)

Error, (in plot) invalid arguments

от того что я обозначу дельту другой буквой ничего не изменится … или я что-то не так понял?

Check out the language spec, section 8 on pattern matching:

Syntax:
Pattern ::= Pattern1 { ‘|’ Pattern1 }
Pattern1 ::= varid ‘:’ TypePat
| ‘_’ ‘:’ TypePat
| Pattern2
Pattern2 ::= varid [‘@’ Pattern3]
| Pattern3
Pattern3 ::= SimplePattern
| SimplePattern {id [nl] SimplePattern}
SimplePattern ::= ‘_’
| varid                                                 // <- 2)
| Literal
| StableId
| StableId ‘(’ [Patterns] ‘)’                           // <- 1)
| StableId ‘(’ [Patterns ‘,’] [varid ‘@’] ‘_’ ‘*’ ‘)’
| ‘(’ [Patterns] ‘)’
| XmlPattern
Patterns ::= Pattern {‘,’ Patterns}

MatchLess(x) is identified as a SimplePattern (1), and the expression between parentheses, according to the above, is identified via Patterns -> Pattern -> Pattern1 -> Pattern2 -> Pattern3 -> SimplePattern -> varid (2). This variable pattern is described as:

A variable pattern x is a simple identifier which starts with a lower
case letter. It matches any value, and binds the variable name to that
value. The type of x is the expected type of the pattern as given from
outside.

In your example, unapply is called on i, and the result is bound to x.