Error ng0201 no provider for ngcontrol found in nodeinjector

ROHIT HARI Asks: Loop clipping image by featurecollections of a vector in Earth Engine and exporting all TIFF
Below is my code. When I run this code I get the error:

Line 27: data.map is not a function

var data =ee.ImageCollection('COPERNICUS/S2_SR_HARMONIZED')
                  .filterDate('2022-01-01', '2022-12-30')
                  // Pre-filter to get less cloudy granules.
                  .filter(ee.Filter.lt('CLOUDY_PIXEL_PERCENTAGE',20))
                  .select('B4', 'B3', 'B2', 'B8')
                  .mean()
                  ;
print(data)

//Map.addLayer(data,{min:0,max:3000, bands:['B4', 'B3', 'B2']},'layer')
var aoi= ee.FeatureCollection(table2).geometry();
var attribute = 'id'


var loop = function(image){
 var output = aoi.map(function(geom){
   var name = geom.get(attribute)
   var clip= image.clip(geom);
   var finalname = ee.String(name)
   return clip.set('name', finalname).set('system:footprint', geom);
  })
  return output
};
print(loop)
var outputd = data.map(loop).flatten()
var size = outputd.size().getInfo();
var outputlist = outputd.toList(size);

for (var i=0; i<size; i++) {
  var image = ee.Image(outputlist.get(i));
  var name = image.get('name').getInfo();
  Export.image.toDrive({
    image:image, 
    description:name, 
    folder: 'FOLDER', 
    fileNamePrefix: name, 
    region: image.aoi().getInfo(), 
    scale:10
  })
}

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MJM Asks: Iterating SAGA Split Features Layer tool across files in directory using python
I have a few thousand polygon shapefiles in a folder that I would like the SAGA Split Features Layer tool to perform its operation on. The operation and parameters are the same for every polygon, but just can’t get it to iterate across the files. Below is the result I want.

====>

# split twp grids into 4
from qgis.core import QgsProcessingAlgorithm
import glob
import os

inpath = "C:\GIS Data\ab_grids\twp_polygons"
outpath = "C:\GIS Data\ab_grids\twp2_2"

input_files = glob.glob(os.path.join(inpath, "*.shp"))

for input_file in input_files:

    output_file = os.path.join(outpath, os.path.basename(input_file))
    
    processing.run("saga:splitfeatureslayer", 
    {'SHAPES': input_files,
    'CUTS':'TEMPORARY_OUTPUT',
    'EXTENT':output_file,
    'NX':2,
    'NY':2,
    'METHOD':0}
    )

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Arpit Aggarwal Asks: Change background color of highlighted feature layer ArcGIS JavaScript
I have a feature layer and I am highlighting the feature of the feature layers on click. It is working fine.

Now what I want is, I want to change the background color / fill some color in that highlighted polygon feature.

Here is the code where I am highlighting the feature:

let highlight;
let highlightIds = [];

view.whenLayerView(districtLayer).then(function(layerView){
    view.on("click", (event) => {
        const params = {
            location: event.mapPoint
        };
        locator.locationToAddress(serviceUrl, params).then(function(response) { // Show the address found
            
            const district = response.attributes.Subregion;

            // remove all highlights first
            if(highlight) {
                highlight.remove();
            }

            // check if district is already highlighted
            let district_id = districtIds.indexOf(district) + 1;
            if(highlightIds.includes(district_id)){
                highlightIds.splice(highlightIds.indexOf(district_id), 1);
            }else{
                highlightIds.push(district_id);
            }

            // hightlight only the selected districts
            highlight = layerView.highlight(highlightIds);

            // code here to fill background color

        }, function(err) { // Show no address found
            console.log("No address found.", evt.mapPoint);
        });
    });
});

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Shootforthemoon Asks: Genetic Engineering Methods: An Overview of Key Approaches, Effectiveness, Costs, and Spectrum of Action
I am seeking a comprehensive list of the main or most noteworthy methods used in genetic engineering, in particular at the gene level. The focus should be on their effectiveness, costs (in terms of money and time), and spectrum of action (types of cells that can be successfully modified).

It is not necessary to explain the mechanisms in detail but instead accompany the list with key considerations in these areas. If available, kindly include references for data.

Thank you for your contribution!

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Tarushi Asks: Is there a reaction involving alkene formation from diazomethane?
I need help regarding the following question…

I identified some of the compounds as follows:

I’m confused about the formation of (G) from (H). Is there a way of preparing an alkene from another alkene by reacting it with diazomethane? Or have a recognised (G) incorrectly?

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Jam War Asks: Would it be possible in physics that ant-man shrinks by creating a warp bubble shell to shrink relatively to the universe but not actually change size
Would this be possible in physics and if not is there any other thing that could shrink antman from a relative point of view

(Would changing reference frames work?)

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nodumbquestions Asks: In QM, does an algebra containing the Hamiltonian always evolve into itself?
Let $mathcal{A}$ be an algebra of operators on a Hilbert space $mathcal{H}$, and suppose it contains the Hamiltonian: $Hinmathcal{H}$. The Heisenberg evolution for any $hat{O}inmathcal{A}$ is $$tag{1} hat{O}(t)=e^{-itH}hat{O}(0)e^{itH}.$$

All three terms on the RHS are in $mathcal{A}$, and so $hat{O}(t)inmathcal{A}$ for all $t$. That is, time evolution maps $mathcal{A}$ into itself.

The above seems correct, but a particle moving on a line seems to provide a counterexample. Let $mathcal{H}=L^2(mathbb{R})$, with position and momentum operators $hat{x},hat{p}$. Take the Hamiltonian $H=hat{p}$. Finally, let $$tag{2}mathcal{A}={f(hat{x}):ftext{ is smooth },supp(f)subseteq (0,1)} oplus span(hat{p}).$$

To see that (2) is closed under the bracket, use $$tag{3}[f(hat{x}),hat{p}]=f'(hat{x})$$ and note that if $supp(f)subseteq (0,1)$ then $supp(f’)subseteq (0,1)$.

Now, since $hat{p}inmathcal{A}$, we expect $mathcal{A}$ to evolve into itself. But this is not true. We have begin{align} tag{4}f(hat{x})(t) &= f(hat{x}(t)) \ tag{5} &= f(e^{-ithat{p}} hat{x}(0) e^{ithat{p}}) \ tag{6}&= f(hat{x}(0)+tI ) end{align} where $I$ in the last line is the identity operator.

After unit time, any $f$ initially with support in $(0,1)$ evolves to have support outside $(0,1)$. Hence $mathcal{A}$ doesn’t evolve into itself.

Where was my mistake? Is there an issue with operators being unbounded? Note that in order to vanish outside $(0,1)$ but be nonzero inside, $f$ must be non-analytic — maybe this is somehow important?

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