Error using matlab internal math interp1 sample points must be unique

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Internal math error when using interpolation

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JanaK

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Joined: Tue Jan 11, 2022 5:13 am

error: eprload with matlab 2021b

Hi,

while trying to use eprload for an xml-file in 2021b following bug showed itself:

eprload
Error using matlab.internal.math.interp1
Interpolation requires at least two sample points for each grid dimension.
Error in interp1 (line 188)
VqLite = matlab.internal.math.interp1(X,V,method,method,Xqcol);
Error in eprload_MagnettechXML
Error in eprload

We tried easyspin 5.2.33 as well as 6.xxx in 2021b, but none of them worked.
The script works in 2018b, 2019b and 2020b though. (5.2.33, 6.xxx)

We think the problem lies in Matlab 2021b in the script of interp1 around line 188 «VqLite».

Thanks for your help,
kind regards from Halle, Germany!

Silvio

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Posts: 10
Joined: Mon Oct 16, 2017 8:37 am

Re: error: eprload with matlab 2021b

Post

by Silvio » Wed Jan 19, 2022 7:51 am

Hi,
I experience the same problem with 2021b. However, after investigating the eprload function, I think the problem lies in the base64 decoding of the data and not in interp1.

The base64 decoding of the curves and subsequent typecasting to double returns just a scalar (line 96-98 in eprload_MagnettechXML.m), therefore interp1 (doing an interpolation) throws the error that at least two sample points are needed for each dimension.

Unfortunately, I am no expert in base64 decoding and the underlying Java functions, so I am afraid I don’t know how to fix the bug.

Best,
Silvio

Stefan Stoll

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Posts: 971
Joined: Mon Jul 21, 2014 10:11 pm
Location: University of Washington

Re: error: eprload with matlab 2021b

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by Stefan Stoll » Fri Jan 21, 2022 1:03 am

Thanks. This is an incompatibility that R2021b introduced. The cause is clear, but it’s unclear how to fix this without making the loading really slow. See the issue on GitHub.

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D F

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I have a text file that has been plotted and I need to find the x value from a known y value. However there isn’t a data point at this point so I have interpolated. This has worked for some txt files but not others.

ymax = max(y);

xmax = find(y == ymax);

xmax = x(xmax);

yhalfmax = max(y)/2;

xhalfmax = interp1(y, x, yhalfmax, ‘spline’); %interpolate to generate a point at the yhalfmax point

Error: Error using gridded Interpolant. The grid vectors must contain unique points.

I have tried using ‘unique’ but this has changed the plotting so can’t be used.

  2 个评论

Matt J

此评论的直接链接

I have tried using ‘unique’ but this has changed the plotting so can’t be used.

How can it «change the plotting», if all you’ve done is throw away duplicate points?

D F

此评论的直接链接

When the following is used to replace the interp1 line above, the curve changes shape. I’m unsure why this would change the plot curve unless it is deleting usefull data points

[x, index] = unique(y); xhalfmax = interp1(y(index), x,yhalfmax, ‘linear’);

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回答（1 个）

Star Strider

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My usual approach to the problem of non-unique independent variable values for interp1 is to add a very small, increasing value to each element.

Example —

XData = sort(randi(9, 1, 10)) % Create Data

XDataUnique = XData + linspace(0, 1, length(XData))*1E-3 % Add Increments To Each Element

I used ‘1E-3’ here to illustrate the idea. In practice, I use a much smaller multiplier, ‘1E-10’ or so.

  4 个评论

D F

此评论的直接链接

Thanks but this is unfortunately still giving the same error. I have tried to just straight forwardly multiply the interpolated data by 1.001 to make sure it doesn’t duplicate the normal x,y data but this has still failed

Star Strider

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My pleasure.

You have to add an increasing vector of small values to the data with duplicate entries to eliminate the problem with non-unique values. Adding a single scalar value to each element changes nothing.

Run my code to see how it works.

D F

此评论的直接链接

Aaah okay that makes sense! I have run the code and it is still returning the same error.

I then exchanged the x in the interp1 line of my code for XDataUnique however the index exceeded the matrix dimension, any thoughts?

Star Strider

此评论的直接链接

Looking at your code, it seems that you need to use it to create your ‘y’ data to do your interpolation, not your ‘x’ data.

Try this:

y = sort(randi(9, 1, 10)) % Create Data

YDataUnique = y + linspace(0, 1, length(y))*1E-3 % Add Increments To Each Element

I honestly have no idea what is causing the index error. The vector size should not change with my code.

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