Error write eof

imagemin,imagemin-jpegoptim | Error: write EOF

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The day before yesterday, there was a miraculous error in the process of the call, the error in the client side of the http request error Get "http://127.0.0.1:8800": EOF , but the server side does not have any exception all the logs are normal execution

Since the error is only on the client side, the Google search results are not caused by the actual scenario (there is no suspicion that there is a problem on the server side), so we have no choice but to capture the packets, and finally the problem is solved

Server.Server write timeout is set to 10s, so by the time the handler finishes processing the request, the connection between the server and the client is already closed.

However, since the data written on the server side is much smaller than the write buffer size (4096 byte) set in the http/net package, the Write method of bufio does not return an error

Since the test environment is too complicated, I wrote a demo to reproduce the whole process, the following is the wireshark exported svc which can be seen:

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"No.","Time","Source","Destination","Protocol","Length","Info"
"85","3.662590","127.0.0.1","127.0.0.1","TCP","68","55585  >  8800 [SYN] Seq=0 Win=65535 Len=0 MSS=16344 WS=64 TSval=465914251 TSecr=0 SACK_PERM=1"
"86","3.662666","127.0.0.1","127.0.0.1","TCP","68","8800  >  55585 [SYN, ACK] Seq=0 Ack=1 Win=65535 Len=0 MSS=16344 WS=64 TSval=465914251 TSecr=465914251 SACK_PERM=1"
"87","3.662675","127.0.0.1","127.0.0.1","TCP","56","55585  >  8800 [ACK] Seq=1 Ack=1 Win=408256 Len=0 TSval=465914251 TSecr=465914251"
"88","3.662681","127.0.0.1","127.0.0.1","TCP","56","[TCP Window Update] 8800  >  55585 [ACK] Seq=1 Ack=1 Win=408256 Len=0 TSval=465914251 TSecr=465914251"
"89","3.662802","127.0.0.1","127.0.0.1","HTTP","151","GET / HTTP/1.1 "
"90","3.662813","127.0.0.1","127.0.0.1","TCP","56","8800  >  55585 [ACK] Seq=1 Ack=96 Win=408192 Len=0 TSval=465914251 TSecr=465914251"
"160","18.792318","127.0.0.1","127.0.0.1","TCP","44","[TCP Keep-Alive] 8800  >  55585 [ACK] Seq=0 Ack=96 Win=408192 Len=0"
"161","18.792325","127.0.0.1","127.0.0.1","TCP","44","[TCP Keep-Alive] 55585  >  8800 [ACK] Seq=95 Ack=1 Win=408256 Len=0"
"162","18.792359","127.0.0.1","127.0.0.1","TCP","56","[TCP Keep-Alive ACK] 55585  >  8800 [ACK] Seq=96 Ack=1 Win=408256 Len=0 TSval=465929251 TSecr=465914251"
"163","18.792363","127.0.0.1","127.0.0.1","TCP","56","[TCP Dup ACK 90#1] 8800  >  55585 [ACK] Seq=1 Ack=96 Win=408192 Len=0 TSval=465929251 TSecr=465914251"
"283","33.925723","127.0.0.1","127.0.0.1","TCP","44","[TCP Keep-Alive] 8800  >  55585 [ACK] Seq=0 Ack=96 Win=408192 Len=0"
"284","33.925731","127.0.0.1","127.0.0.1","TCP","44","[TCP Keep-Alive] 55585  >  8800 [ACK] Seq=95 Ack=1 Win=408256 Len=0"
"285","33.925741","127.0.0.1","127.0.0.1","TCP","56","[TCP Keep-Alive ACK] 55585  >  8800 [ACK] Seq=96 Ack=1 Win=408256 Len=0 TSval=465944251 TSecr=465929251"
"286","33.925749","127.0.0.1","127.0.0.1","TCP","56","[TCP Dup ACK 90#2] 8800  >  55585 [ACK] Seq=1 Ack=96 Win=408192 Len=0 TSval=465944251 TSecr=465929251"
"345","49.031897","127.0.0.1","127.0.0.1","TCP","44","[TCP Keep-Alive] 8800  >  55585 [ACK] Seq=0 Ack=96 Win=408192 Len=0"
"346","49.031903","127.0.0.1","127.0.0.1","TCP","44","[TCP Keep-Alive] 55585  >  8800 [ACK] Seq=95 Ack=1 Win=408256 Len=0"
"347","49.031929","127.0.0.1","127.0.0.1","TCP","56","[TCP Keep-Alive ACK] 55585  >  8800 [ACK] Seq=96 Ack=1 Win=408256 Len=0 TSval=465959251 TSecr=465944251"
"348","49.031932","127.0.0.1","127.0.0.1","TCP","56","[TCP Dup ACK 90#3] 8800  >  55585 [ACK] Seq=1 Ack=96 Win=408192 Len=0 TSval=465959251 TSecr=465944251"
"469","63.667058","127.0.0.1","127.0.0.1","TCP","56","8800  >  55585 [FIN, ACK] Seq=1 Ack=96 Win=408192 Len=0 TSval=465973767 TSecr=465959251"
"470","63.667081","127.0.0.1","127.0.0.1","TCP","56","55585  >  8800 [ACK] Seq=96 Ack=2 Win=408256 Len=0 TSval=465973767 TSecr=465973767"
"471","63.667119","127.0.0.1","127.0.0.1","TCP","56","55585  >  8800 [FIN, ACK] Seq=96 Ack=2 Win=408256 Len=0 TSval=465973767 TSecr=465973767"
"472","63.667147","127.0.0.1","127.0.0.1","TCP","56","8800  >  55585 [ACK] Seq=2 Ack=97 Win=408192 Len=0 TSval=465973767 TSecr=465973767"

b.bufr : conn’s read buffer b.bufw : conn’s write buffer, 4096 byte in size c.readRequest(ctx) : the req request is processed, and a *response is returned ServeHTTP(w, w.req) : eventually w is passed all the way down all the way down, to our own processing function

Writer is the equivalent of calling w.w.Write(p []byte) == w.cw.Write(p []byte) w.cw : which is of type chunkWriter so if the call to w.w.Write(p []byte) == chunkWriter.Write([]byte)

cw.res.conn : According to the above code, we find that conn == w.conn == srv.newConn(rw) cw.res.conn.bufw : that is c.bufw = newBufioWriterSize(checkConnErrorWriter{c}, 4 “10), which shows that the buffer for conn write is 4096 byte

bufio : if the length of the data does not exceed len(b.buf), the data will be copied to b.buf, and not actually written to b.wr

Fix Error EOF While Parsing in Python

SyntaxError: unexpected EOF while parsing occurs when an interpreter reaches the end of a file before executing a code block.

This is often a sign that some part of the code is missing. We need to locate the syntactical error and fix it.

Modern Python interpreters such as Pycharm would often highlight the code section that needs to be fixed. More often, resolving the error involves adding the section of the code that is missing.

Using for loops often requires adding some code in the code. Failure to add some code in the body results in the unexpected EOF while parsing error.

for loops are often used to iterate over some iterable; in some scenarios, we may fail to add code to the body of the for loop. This is one of the scenarios that result in such an error.

names  = ['Tesla', 'Lucid', 'Samsung']

for company in names:

Output:

File "<string>", line 14
    
    ^
SyntaxError: unexpected EOF while parsing

According to the correct Python syntax, the compiler expects to execute some code after the indentation.

This new code in the indentation block forms part of the body of the for loop. Therefore, we need to ensure that the loop’s body has some code to avert the unexpected end of the file and conform to the correct Python syntax.

We can fix this error, as shown in the code below.

names  = ['Tesla', 'Lucid', 'Samsung']

for company in names:
    result = company.upper()
    print(result)

Output:

This error may also come up when working with if-else statements. if statements are used to execute a block of code on a given condition; the indented block in an if statement forms the body of all if statements.

Apart from being used as a delimiter and defining functions, a full colon signifies the beginning of code blocks in if statements. Failure to write any code in the block preceding the full colon would result in an EOF file while parsing errors.

Below is an example demonstrating how this error comes about.

company_name = "tesla"

if company_name.upper() == True:

Output:

File "<string>", line 4
    
    ^
SyntaxError: unexpected EOF while parsing

This error can be fixed by ensuring that the if statement has some code in its body, as shown below.

company_name = "tesla"

if company_name.isupper() == True:
   print(company_name.lower())
else:
    print(company_name.upper())

Output:

The interpreter will equally raise the error EOF while parsing if no code is written in the body of the else statement that immediately follows an if statement. This error will be thrown even though there is a valid code in the if statement block.

Therefore, both code blocks should be complete to write a successful if-else statement. Otherwise, we will get the error EOF while parsing.

number = input("Please Enter a number: ")

if number%2 == 0:
    print("This is an even number:")
else:

Output:

File "<string>", line 7
    
    ^
SyntaxError: unexpected EOF while parsing

We need to ensure that the other part has a complete body to fix this error. Some if statements do not require else statements; in such a case, we don’t need to have any else statements at all.

number = int(input("Please Enter a number: "))

if number%2 == 0:
    print("This is a even number")
else:
    print("This is not an even number")

Output:

Please Enter a number: 23
This is not an even number

This error also occurs if the body of the while loop is too defined. Similarly, the error can be fixed by ensuring that the body of the while loop is provided.

Output:

File "<string>", line 3
    
    ^
SyntaxError: unexpected EOF while parsing

The error can also arise when working with functions if the function’s body is not provided.

In large programs with several functions, we may want to implement a function in the future. Thus, it would not be unnecessary to define the function’s body right away.

It may also be the case when one has yet to decide its functionality. The function below is supposed to calculate the sum of two numbers.

However, the body containing the statements that state what the function should do is not declared. This results in an error, as shown below.

def add_numbers(num1, num2):

Output:

File "<string>", line 3
    
    ^
SyntaxError: unexpected EOF while parsing

This error can be fixed by writing the statements that define the function, as shown in the example below.

def add_numbers(num1, num2):
    result = num1 + num2
    print(result)
    
add_numbers(23, 45)

Output:

If we do not want to specify what the function implements, we can also use the keyword pass. The interpreter ignores the pass statement, so nothing is executed.

We can also use this statement to avoid executing functions that we don’t want to implement immediately. The keyword pass can be used to avert the error EOF while parsing, as shown in the example below.

def add_numbers(num1, num2):
    pass

Output:

Unexpected EOF While Parsing may also result from missing parentheses in functions or statements that make use of parentheses.

The print function and many other built-in Python functions are executed using parentheses. When writing code in a hurry, such small syntax errors can often be made unknowingly; this results in the error EOF while parsing as shown in the example below.

def say_hello():
    print("Hello user welcome on board"

Output:

File "<string>", line 2
    
    ^
SyntaxError: unexpected EOF while parsing

This error can only be resolved by ensuring that there are no parentheses left open.

Modern interpreters would often inform you that there is an error before proceeding to the next line. This error also extends to self-defined functions.

Improperly calling functions would also result in this error. The code below shows that an improper way of calling a self-defined function constitutes a failure to use both parentheses.

def add_sum(num1, num2):
    print(num1 + num2)
 
add_sum(23, 78

Output:

  File "e:CodeBerryeoferroinpython.py", line 8
    
    ^
SyntaxError: unexpected EOF while parsing

The Python try and except tests for the presence of errors in our code that could make our programs stop and handle them, respectively.

The try block cannot function as a standalone method and should always accompany an except block. Using the try block to test a piece without specifying any code in the except block results in the SyntaxError: unexpected EOF while parsing as shown below.

number = int(input("Please enter a number:"))

def add_numbers(number):
    try:
        print(number + 2)
        
    except ValueError:

Output:

File "<string>", line 7
    
    ^
SyntaxError: unexpected EOF while parsing

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