Float object cannot be interpreted as an integer как исправить

In Python, we have two data types to represent numeric values

float

and

int

. Float data represent the real numbers, and int data type represents the integer number. There are many operations and functions in Python that only support integer numbers, for example, in list indexing, we can not use float numbers there we always need to pass an int value as an index number.

Similarly, there is a

range()

function in Python that only accepts int values, and if we try to pass a float value to the range() function, we will receive the

TypeError: 'float' object cannot be interpreted as an integer

error.

In this Python guide, we will discuss what this error is and how to debug it. We will also walk through a common example of when many people encounter this error. So without further ado, let’s get started with the error statement.

The Error statement

TypeError: 'float' object cannot be interpreted as an integer

has two parts separated with a colon

:

.

1. TypeError
2. ‘float’ object cannot be interpreted as an integer

1. TypeError

TypeError is a standard Python exception. It is raised in a Python program when we try to perform an invalid operation or pass an invalid data type value to a function.

2. ‘float’ object cannot be interpreted as an integer


'float' object cannot be interpreted as an integer

is the error message. This error message tells us that the float variable can not be interpreted as an integer, which simply means the Python interpreter is not able to compute the value of float for the function where it was expecting an integer number. You will encounter this error message in your Python program when you try to pass a floating-point number to the

range()

function.

Example

# float number
num = 6.0

# a list from 0 to 5
my_list = list(range(num))

print(my_list)

Output

Traceback (most recent call last):
    File "main.py", line 5, in <module>
      my_list = list(range(num))
TypeError: 'float' object cannot be interpreted as an integer

The

range()

function accepts an integer value

n

and returns an iterable object from range 0 to

n-1

. In our example, the value of

num

is

6.0

, which is a floating-point number. That’s why the

range(num)

statement returns the Error

TypeError: 'float' object cannot be interpreted as an integer

because it was not able to interpret the 6.0 value as 6.

Solution

To solve the above problem, we can need to convert the 6.0 num value to a 6 num value using

int()

function.

# float number
num = 6.0

# int num
num = int(num)
# a list from 0 to 5
my_list = list(range(num))

print(my_list)

Output

[0,1,2,3,4,5]

Common Example Scenario

Often when we take input from the user using the

input()

function, and if we are expecting a numerical value, we convert that input string value to float using the float function.

Example

students = [{'Rank':1,'Name':'Rahul', "Marks":894},
            {'Rank':2,'Name':'Jay', "Marks":874},
            {'Rank':3,'Name':'Ali', "Marks":870},
            {'Rank':4,'Name':'Rohan', "Marks":869},
            {'Rank':5,'Name':'Kher', "Marks":856},
            {'Rank':5,'Name':'Sofi', "Marks":850},
            ]

# convert the input number to float (error)
top_n = float(input("How many students details do you want to see?: "))

for i in range(top_n):
    print("Rank: ",students[i]['Rank'],"Name: ", students[i]['Name'], "Marks: ", students[i]['Marks'] )

Output

How many students details do you want to see?: 3
Traceback (most recent call last):
   File " main.py", line 12, in <module>
      for i in range(top_n):
TypeError: 'float' object cannot be interpreted as an integer

Error Reason

In the above example in line 10, we are trying to convert the user input value to a floating-point number. And in line 12, we are passing that same floating-point number to the

range()

function, which leading this error.

Solution

If you ever encounter this situation where you need to ask a numeric value from the user using the

input()

function for the

range()

function. There you should always use the

int()

function and convert the user-entered number to an integer value. Because the range() function only accepts integer numbers.

students = [{'Rank':1,'Name':'Rahul', "Marks":894},
            {'Rank':2,'Name':'Jay', "Marks":874},
            {'Rank':3,'Name':'Ali', "Marks":870},
            {'Rank':4,'Name':'Rohan', "Marks":869},
            {'Rank':5,'Name':'Kher', "Marks":856},
            {'Rank':5,'Name':'Sofi', "Marks":850},
            ]

# convert the input number to integer solved
top_n = int(input("How many students details do you want to see?: "))

for i in range(top_n):
    print("Rank: ",students[i]['Rank'],"Name: ", students[i]['Name'], "Marks: ", students[i]['Marks'] )

Output

How many students details do you want to see?: 3
Rank: 1 Name: Rahul Marks: 894
Rank: 2 Name: Jay Marks: 874
Rank: 3 Name: Ali Marks: 870

Conclusion

In this Python tutorial, we learned what

TypeError: 'float' object cannot be interpreted as an integer

error is in Python and how to debug it. The Error is raised when we try to pass a floating-point number to the range() function.

To debug this problem, all we need to do is convert the floating-point number to an integer before we pass it as an argument to the range() function.

If you are still getting this error in your Python program, please share your code in the comment section. We will try to help you in debugging.

People are also reading:

• Python typeerror: ‘str’ object is not callable Solution

• Python Iterators

• Python TypeError: ‘method’ object is not subscriptable Solution

• Python Generators

• Python TypeError: ‘function’ object is not subscriptable Solution

• Python Decorators

• Python Error: TypeError: ‘tuple’ object is not callable Solution

• Python ValueError: invalid literal for int() with base 10: Solution

• Python Closures

• Python TypeError: ‘NoneType’ object is not callable Solution