Invalid qualifier vba excel ошибка

I use this technique when I get confused about the type of object I have created by stringing properties.

Within Excel’s Visual Basic Editor, create a new module if you do not have an existing one that you wish to use in this way. If you select the module in Project Explorer and click F4, you can change the module’s name to «Experiments» say.

Type or copy:

Option Explicit
Sub TestA()

End Sub

I always start my modules with Option Explicit. Look Option Explicit up in VBA Help and it will tell you why this is a good idea.

I have also created an empty sub-routine into which I will type some statements.

Start typing a new statement so you have:

Sub TestA()

  Debug.Print Range("B:B").

End Sub

When you type the period at the end of this new line, a pop-up window will show you the available methods and properties. This list will show, as expected, all the methods and properties of a Range. Type «Address» or select Address from the list to get:

Sub TestA()

  Debug.Print Range("B:B").Address

End Sub

Click F5 to run this macro and the following will appear in the Immediate Window:

$B:$B

This is the address of all rows in column B which is what you would expect.

Now add two further statements to the macro:

  Debug.Print Range("F:F").Address
  Debug.Print Union(Range("B:B"), Range("F:F")).Address

Run this macro again and you will get:

$B:$B
$F:$F
$B:$B,$F:$F

Again this is what was expected.

Now add:

  Debug.Print Union(Range("B:B"), Range("F:F")).Rows.

The pop-up window that appears will be unchanged because Range.Rows is still a range.

Complete the statement by adding or selecting «Address» and run the macro again to get:

$B:$B
$F:$F
$B:$B,$F:$F
$B:$B,$F:$F

This may not be what you expected but think about it. $B:$B,$F:$F is all rows in columns B and F so adding the property Rows does not change the address.

Now add the following statements to the macro:

  Debug.Print Union(Range("B:B"), Range("F:F")).Count
  Debug.Print Union(Range("B:B"), Range("F:F")).Rows.Count

Run the macro and these statements will each output an integer. I am using Excel 2003 so I get:

 131072 
 65536 

If you are using a later version of Excel, you will get larger integers. The second integer is the number of rows in a worksheet for your version of Excel. The first integer is the number of cells in two columns of a worksheet for your version of Excel.

Now add:

  Debug.Print Union(Range("B:B"), Range("F:F")).Rows.Count.

When you type the final period, no pop-up window will appear because an integer has no method or property that you can select in this way. Method .End(xlUp) operates on a range; it is not a property of Count which is why you get «Invalid qualifier».

It is very easy to get oneself confused when stringing properties together. Personally I avoid stringing properties because even if it is faster to run, it takes longer for me to understand and debug. There are situations in which minimising runtime is the top priority but is this one of those cases? How many hours have you wasted with this approach?

Consider:

  Dim Rng1 As Range
  Dim Rng2 As Range
  Dim Rng3 As Range
  Dim RowMax As Long

  Set Rng1 = Range("B:B")
  Set Rng2 = Range("F:F")
  Set Rng3 = Union(Rng1, Rng2)
  RowMax = Rng3.Count

  Debug.Print RowMax

  Debug.Print Rng3.Find("*", Range("B1"), xlValues, xlWhole, xlByRows, xlPrevious).Row

You do not need RowMax but I have included it so you are absolutely clear what Rng3.Count returns. I have also gone OTT with the ranges. I would be happy to type: Set Rng3 = Union(Range("B:B"), Range("F:F")) because I find it easy to understand.

Method .End(xlUp) operates on a cell. MultiCellRange.End(xlUp).Row is valid syntax but I cannot get it to return useful information. If you want to use .End(xlUp) consider:

  Dim RowMaxColB As Long
  Dim RowMaxColF As Long

  RowMaxColB = Cells(Rows.Count, "B").End(xlUp).Row
  RowMaxColF = Cells(Rows.Count, "F").End(xlUp).Row

I agree with Siddharth, Find appears to be the best approach in this situation. However, you should look at this answer of mine, https://stackoverflow.com/a/20849875/973283, to a different question. It includes a macro that demonstrates a selection of methods of finding last rows and columns and shows the situations in which they fail.

You may have encountered an error code indicating an invalid qualifier for a Microsoft Visual Basic compilation error. There are several steps you can take to fix this problem. Let’s discuss it now.

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This error has the above cause and solution: the qualifier should not define an ideal design, module, object, or UDT variable within a valid range. Check the spelling of certain qualifiers. Make sure the corresponding ID is indeed in the current range.

Used qualifiers continue to serve to clarify terms. This error identifies the cause and solution:

• The qualifier does not define a project , module , object or huge variable user-defined type in the most recent range .

  Check the spelling of the qualifier. Make sure the corresponding id it contains is the current scope. For example, a UDT type variable in a private module will probably not be visible only in that module.

For more care, select the appropriate item and press F1 (Windows or Windows) HELP (current Macintosh).

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• Article
• 2 minutes to read.

I use this method when I don’t understand how to get the type of the object that I collected by combining properties.

If someone doesn’t have an existing module that you want to use this way, create a new module in the Excel Visual Basic Editor. If you select a module in the project explorer and press F4, you can pronounce the name of the module in Experiments.

  Explicit parameterSubtest A ()Still under 

I am launching my modules with Option Explicit . Search for Option Explicit in the VBA help and it will show you why it fits any idea.

I also created an empty subroutine into which I will insert some instructions.

  SubtestA ()  Debug.Print Range ("B: B").The end of the submarine 

If you keep typing period at the end of this awesome line, a popup will show you the available methods and properties. As expected, this listing showsall our methods and properties are ranked. Enter “address” or select an address from this list to get:

  SubtestA ()  Debug.Print Range ("B: B"). The addressThe end of the submarine 

Press F5 to run this macro. The next window displays the following:

  $ B: $ B 

This is the address of all expected series in column B.

  Debug.Print Range ("F: F"). The address  Debug.Print Union (Range ("B: B"), Range ("F: F")). 

  $ B: $ B$ F: $ F$ B: $ B, $ F: $ F 

  Debug.Print Union (Range ("B: B"), Range ("F: F")). Rows. 

The popup remains unchanged because Range.Rows is still a range.

Complete the statement by adding or selecting Address and calling the macro again to get:

  $ B: $ B$ F: $ F$ B: $ B, $ F: $ F$ B: $ B, $ F: $ F 

This may be less than expected, but it is related. $ b: $ b, $ f: $ f – all rows in columns B and F only, so adding a new property to n ‘rows does not include the change address part.

  Debug.Print Union (Range ("B: B"), Range ("F: F")).  Debug.Print Union (Range ("B: B"), Range ("F: F")). Rows.Count 

Run a macro and each of theseX instructions will also be the output integer. When I have an Excel 2003 application I get:

  131072 65536 

If you are using a newer version of Excel, these are large integers. The second became an integer, the number of rows on a specific sheet for your version of Excel. The first integer is the number of cells in two columns of the worksheet in your version of Excel.

  Debug.Print Union (Range ("B: B"), Range ("F: F")). Rows.Count. 

If you enter the last period, the popup will not appear because the integer does not have a method or property that your organization can select this way. The .End (xlUp) method works with a zone; it’s not just a Count property, so you’ll definitely get an Invalid Qualifier.

Every time you chain objects together, it’s incredibly easy to get lost. Personally, I stick with string properties because while it is faster it takes me longer to understand and debug. There are situations where reducing runtime is a top priority, but is this one such case? How many hours did you spend on this papproach?

  Dim Rng1 As Range  Dim Rng2 like a zone  Dim Rng3 like a zone  Dim RowMax until then  Set Rng1 = Range ("B: B")  Define Rng2 means range ("f: f") Set Rng3 = Union (Rng1, Rng2)  RowMax = Rng3.Count  Debug Print RowMax  Debug.Print Rng3.Range ("B1"), find ("*", xlValues, xlWhole, xlByRows, xlPrevious) .Row 

You don’t actually need RowMax , but I’ve included it so you can see exactly what Rng3.Count returns. I could even go to OTT with zones. I would like to enter: Set equals rng3 Union (Range ("B: B"), Range ("F: F")) because I find the game easy to understand.

The .End (xlUp) method works with a huge cell. MultiCellRange.End (xlUp) .Row is valid syntax, except I can’t get to very important information. If you want to draw on .End (xlUp) , please note:

  Dim As rowmaxcolb Long  Dim RowMaxColF until  RowMaxColB = Cells (Rows.Count, "B"). End (xlUp) .Row  RowMaxColF = Cells (Rows.Count, "F"). End (xlUp) .Row 

I agree with Siddhart, Find seems to be the best approach under the circumstances. However, you should check out such an answer from me, https://stackoverflow.com/a/20849875/973283, for a completely different question. It containsa macro that demonstrates various methods of getting the last rows and columns and shows in which situations they do not work.

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I use this technique when I get confused about the type of object I have created by stringing properties.

Within Excel’s Visual Basic Editor, create a new module if you do not have an existing one that you wish to use in this way. If you select the module in Project Explorer and click F4, you can change the module’s name to «Experiments» say.

Type or copy:

Option Explicit
Sub TestA()

End Sub

I always start my modules with Option Explicit. Look Option Explicit up in VBA Help and it will tell you why this is a good idea.

I have also created an empty sub-routine into which I will type some statements.

Start typing a new statement so you have:

Sub TestA()

  Debug.Print Range("B:B").

End Sub

When you type the period at the end of this new line, a pop-up window will show you the available methods and properties. This list will show, as expected, all the methods and properties of a Range. Type «Address» or select Address from the list to get:

Sub TestA()

  Debug.Print Range("B:B").Address

End Sub

Click F5 to run this macro and the following will appear in the Immediate Window:

$B:$B

This is the address of all rows in column B which is what you would expect.

Now add two further statements to the macro:

  Debug.Print Range("F:F").Address
  Debug.Print Union(Range("B:B"), Range("F:F")).Address

Run this macro again and you will get:

$B:$B
$F:$F
$B:$B,$F:$F

Again this is what was expected.

Now add:

  Debug.Print Union(Range("B:B"), Range("F:F")).Rows.

The pop-up window that appears will be unchanged because Range.Rows is still a range.

Complete the statement by adding or selecting «Address» and run the macro again to get:

$B:$B
$F:$F
$B:$B,$F:$F
$B:$B,$F:$F

This may not be what you expected but think about it. $B:$B,$F:$F is all rows in columns B and F so adding the property Rows does not change the address.

Now add the following statements to the macro:

  Debug.Print Union(Range("B:B"), Range("F:F")).Count
  Debug.Print Union(Range("B:B"), Range("F:F")).Rows.Count

Run the macro and these statements will each output an integer. I am using Excel 2003 so I get:

 131072 
 65536 

If you are using a later version of Excel, you will get larger integers. The second integer is the number of rows in a worksheet for your version of Excel. The first integer is the number of cells in two columns of a worksheet for your version of Excel.

Now add:

  Debug.Print Union(Range("B:B"), Range("F:F")).Rows.Count.

When you type the final period, no pop-up window will appear because an integer has no method or property that you can select in this way. Method .End(xlUp) operates on a range; it is not a property of Count which is why you get «Invalid qualifier».

It is very easy to get oneself confused when stringing properties together. Personally I avoid stringing properties because even if it is faster to run, it takes longer for me to understand and debug. There are situations in which minimising runtime is the top priority but is this one of those cases? How many hours have you wasted with this approach?

Consider:

  Dim Rng1 As Range
  Dim Rng2 As Range
  Dim Rng3 As Range
  Dim RowMax As Long

  Set Rng1 = Range("B:B")
  Set Rng2 = Range("F:F")
  Set Rng3 = Union(Rng1, Rng2)
  RowMax = Rng3.Count

  Debug.Print RowMax

  Debug.Print Rng3.Find("*", Range("B1"), xlValues, xlWhole, xlByRows, xlPrevious).Row

You do not need RowMax but I have included it so you are absolutely clear what Rng3.Count returns. I have also gone OTT with the ranges. I would be happy to type: Set Rng3 = Union(Range("B:B"), Range("F:F")) because I find it easy to understand.

Method .End(xlUp) operates on a cell. MultiCellRange.End(xlUp).Row is valid syntax but I cannot get it to return useful information. If you want to use .End(xlUp) consider:

  Dim RowMaxColB As Long
  Dim RowMaxColF As Long

  RowMaxColB = Cells(Rows.Count, "B").End(xlUp).Row
  RowMaxColF = Cells(Rows.Count, "F").End(xlUp).Row

I agree with Siddharth, Find appears to be the best approach in this situation. However, you should look at this answer of mine, https://stackoverflow.com/a/20849875/973283, to a different question. It includes a macro that demonstrates a selection of methods of finding last rows and columns and shows the situations in which they fail.