I have a file called «result.csv», from that file i want to read certain data and display them. I have that file in my eclipse project folder itself. Still i’m unable to read the file.
public static void main(String [] args) {
int i=0;
String filename="result.csv";
Path pathToFile = Paths.get(filename);
try (BufferedReader br = Files.newBufferedReader(pathToFile, StandardCharsets.US_ASCII)) {
// read the first line from the text file
String line = br.readLine();
// loop until all lines are read
while (i<10) {
// use string.split to load a string array with the values from
// each line of
// the file, using a comma as the delimiter
String[] attributes = line.split(",");
double x=Double.parseDouble(attributes[8]);
double y=Double.parseDouble(attributes[9]);
System.out.println(GeoHash.withCharacterPrecision(x, y, 10));
// read next line before looping
// if end of file reached, line would be null
line = br.readLine();
i++;
}
} catch (IOException ioe) {
ioe.printStackTrace();
}
}
OUTPUT:
java.nio.file.NoSuchFileException: result.csv
at sun.nio.fs.WindowsException.translateToIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsFileSystemProvider.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.spi.FileSystemProvider.newInputStream(Unknown Source)
at java.nio.file.Files.newInputStream(Unknown Source)
at java.nio.file.Files.newBufferedReader(Unknown Source)
at com.uvce.cse.searchiot.geohash.TestGeoHash.main(TestGeoHash.java:19)
Can anyone point where exactly i missed? and how can i overcome this or any alternate methods for this method?
asked Jan 3, 2018 at 11:02
SnkiniSnkini
5511 gold badge5 silver badges15 bronze badges
2
The problem is that your default directory at application startup is not what you think it is. Try adding the following line to your code, just after you create the path:
public static void main(String [] args) {
int i=0;
String filename="result.csv";
Path pathToFile = Paths.get(filename);
System.out.println(pathToFile.toAbsolutePath());
That way, you’ll see exactly where it is looking for the file.
How to fix it is your decision. You can use a full path spec instead of just a filename, or put the filename in a special «Resources» directory and reference it using a relative path, or move the file to wherever your default directory is.
answered Jan 3, 2018 at 11:25
2
If your file("result.csv") in the src directory, you should use the «src/result.csv» instead of «result.csv».
answered Sep 22, 2018 at 6:02
何明扬何明扬
831 silver badge3 bronze badges
1
The problem there is that java isn’t able to find the «result.csv» file in the project folder. Thus, try to use the fully qualified path to the file, e.g. C:your_folderprojectresult.csv in the Path variable. Also I think It would be better to use bufferedreader like this: BufferedReader br = new BufferedReader(new FileReader(insert here the String in which is defined the path to the file)); Check the uses of BufferedReader here
answered Jan 3, 2018 at 11:26
If you’re a MacOSX user please type the file path manually instead of copying it from «Get Info».
You’ll get something like this if you copied it from «Get Info»:
/Users/username<200e><2068><2068>/Desktop<2069>/source.txt
answered Nov 15, 2018 at 23:20
1
I had the same error caused by escaped characters on windows file path. For example, my application was looking for «C:Usersdavidmy%20folder%20namesource.txt» meanwhile the real path was «C:Usersdavidmy folder namesource.txt«.
answered Sep 28, 2021 at 15:15
Not discarding all possible solutions here, this error also occurs when your running Android Studio on Windows environment and using a project directory on an external hard drive formatted with other than NFTS. ]
If this is the case, simply move your project into the main HDD (NTFS) and reload the project again , this time from the main HDD folder path.
answered Nov 28, 2021 at 10:50
Miguel TomásMiguel Tomás
1,5941 gold badge10 silver badges21 bronze badges
I have a file called «result.csv», from that file i want to read certain data and display them. I have that file in my eclipse project folder itself. Still i’m unable to read the file.
public static void main(String [] args) {
int i=0;
String filename="result.csv";
Path pathToFile = Paths.get(filename);
try (BufferedReader br = Files.newBufferedReader(pathToFile, StandardCharsets.US_ASCII)) {
// read the first line from the text file
String line = br.readLine();
// loop until all lines are read
while (i<10) {
// use string.split to load a string array with the values from
// each line of
// the file, using a comma as the delimiter
String[] attributes = line.split(",");
double x=Double.parseDouble(attributes[8]);
double y=Double.parseDouble(attributes[9]);
System.out.println(GeoHash.withCharacterPrecision(x, y, 10));
// read next line before looping
// if end of file reached, line would be null
line = br.readLine();
i++;
}
} catch (IOException ioe) {
ioe.printStackTrace();
}
}
OUTPUT:
java.nio.file.NoSuchFileException: result.csv
at sun.nio.fs.WindowsException.translateToIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsFileSystemProvider.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.spi.FileSystemProvider.newInputStream(Unknown Source)
at java.nio.file.Files.newInputStream(Unknown Source)
at java.nio.file.Files.newBufferedReader(Unknown Source)
at com.uvce.cse.searchiot.geohash.TestGeoHash.main(TestGeoHash.java:19)
Can anyone point where exactly i missed? and how can i overcome this or any alternate methods for this method?
asked Jan 3, 2018 at 11:02
SnkiniSnkini
5511 gold badge5 silver badges15 bronze badges
2
The problem is that your default directory at application startup is not what you think it is. Try adding the following line to your code, just after you create the path:
public static void main(String [] args) {
int i=0;
String filename="result.csv";
Path pathToFile = Paths.get(filename);
System.out.println(pathToFile.toAbsolutePath());
That way, you’ll see exactly where it is looking for the file.
How to fix it is your decision. You can use a full path spec instead of just a filename, or put the filename in a special «Resources» directory and reference it using a relative path, or move the file to wherever your default directory is.
answered Jan 3, 2018 at 11:25
2
If your file("result.csv") in the src directory, you should use the «src/result.csv» instead of «result.csv».
answered Sep 22, 2018 at 6:02
何明扬何明扬
831 silver badge3 bronze badges
1
The problem there is that java isn’t able to find the «result.csv» file in the project folder. Thus, try to use the fully qualified path to the file, e.g. C:your_folderprojectresult.csv in the Path variable. Also I think It would be better to use bufferedreader like this: BufferedReader br = new BufferedReader(new FileReader(insert here the String in which is defined the path to the file)); Check the uses of BufferedReader here
answered Jan 3, 2018 at 11:26
If you’re a MacOSX user please type the file path manually instead of copying it from «Get Info».
You’ll get something like this if you copied it from «Get Info»:
/Users/username<200e><2068><2068>/Desktop<2069>/source.txt
answered Nov 15, 2018 at 23:20
1
I had the same error caused by escaped characters on windows file path. For example, my application was looking for «C:Usersdavidmy%20folder%20namesource.txt» meanwhile the real path was «C:Usersdavidmy folder namesource.txt«.
answered Sep 28, 2021 at 15:15
Not discarding all possible solutions here, this error also occurs when your running Android Studio on Windows environment and using a project directory on an external hard drive formatted with other than NFTS. ]
If this is the case, simply move your project into the main HDD (NTFS) and reload the project again , this time from the main HDD folder path.
answered Nov 28, 2021 at 10:50
Miguel TomásMiguel Tomás
1,5941 gold badge10 silver badges21 bronze badges
NoSuchFileException occurred when trying to attempt access a file or directory which is not exist in given location.
NoSuchFileException is sub class of FileSystemException. This exception introduced in Java 7.
Example for NoSuchFileException
This example is throwing NoSuchFileException because trying to access a file student_data.json which is not exist on default location.
package com.fiot.json.jackson;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.Arrays;
import java.util.List;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fiot.json.jackson.pojo.Student;
public class ConvertJsonToArrayList {
public static void main(String[] args) {
try
{
byte[] mapData = Files.readAllBytes(Paths.get("student_data.json"));
Student[] studentArr = null;
ObjectMapper objectMapper = new ObjectMapper();
studentArr = objectMapper.readValue(mapData, Student[].class);
List studentList=Arrays.asList(studentArr);
System.out.println("Student 1 n"+studentList.get(0));
System.out.println("Student 2 n"+studentList.get(1));
}
catch(JsonMappingException ex)
{
ex.printStackTrace();
}
catch(IOException ex)
{
ex.printStackTrace();
}
}
}
Exception Stacktrace
java.nio.file.NoSuchFileException: student_data.json
at sun.nio.fs.WindowsException.translateToIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsFileSystemProvider.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.Files.readAllBytes(Unknown Source)
at com.fiot.json.jackson.ConvertJsonToArrayList.main(ConvertJsonToArrayList.java:18)
Solutions
There are couple of solutions to handle such situations:
- Use fully qualified file path such as “C:/data/student_data.json” but that will help only when your program is going to run on local machine. While working with enterprise application always use relative paths.
- If your file in source directory use path as “src/student_data.json”
- If your project is maven project, always write script to copy file which you want to access or keep in resource folder to access because maven project create different directory structure after build.
Solution depend on your project requirement. You can use below code to get qualified full path of a file
public static void main(String [] args) {
String filename="student_data.json";
//To get path of file
Path path = Paths.get(filename);
//To print absolute path of file
System.out.println(path.getAbsolutePath());
You would like to see
Follow below link to see more Java issues solutions
- JAVA Issues and Solutions
“Learn From Others Experience»
This quick coding tip explains how to resolve error java.nio.file.NoSuchFileException when using NIO API in Java.
If you are getting the following exception at runtime –
java.nio.file.NoSuchFileException: C:JavaBrahmanLEVEL11
at sun.nio.fs.WindowsException.translateToIOException(WindowsException.java:79)
at sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:97)
at sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:102)
at sun.nio.fs.WindowsFileAttributeViews$Basic.readAttributes(WindowsFileAttributeViews.java:53)
at sun.nio.fs.WindowsFileAttributeViews$Basic.readAttributes(WindowsFileAttributeViews.java:38)
at sun.nio.fs.WindowsFileSystemProvider.readAttributes(WindowsFileSystemProvider.java:193)
at java.nio.file.Files.readAttributes(Files.java:1737)
at java.nio.file.FileTreeWalker.getAttributes(FileTreeWalker.java:219)
at java.nio.file.FileTreeWalker.visit(FileTreeWalker.java:276)
at java.nio.file.FileTreeWalker.walk(FileTreeWalker.java:322)
at java.nio.file.Files.walkFileTree(Files.java:2662)
at java.nio.file.Files.walkFileTree(Files.java:2742)
at com.javabrahman.corejava.RecursiveFileVisitor.main(RecursiveFileVisitor.java:39)
...Resolution for the java.nio.file.NoSuchFileException error
- This error occurs most commonly when a file name, directory name or file path has been incorrectly specified when using the file handling classes of
java.nio.filepackage. - You need to closely check the file path you have given in the Java class written by you. This file or directory path will be printed on the top line of the error stack trace as well. Just as
C:JavaBrahmanLEVEL11is printed at the top of the above stack trace. - The errant Java class will be present in the middle of the stack trace, between the NIO package’s internal calls, along with the error causing line number. In the above stack trace the error causing file is –
(RecursiveFileVisitor.java:39). - Also note that,
java.nio.file.NoSuchFileExceptionis most likely to be thrown when creating an instance ofjava.nio.file.Pathinstance with an incorrect directory path or file name.
Copyright © 2014-2022 JavaBrahman.com, all rights reserved.
Have you ever tried reading resources (json files, htm templates, text files etc) in your Spring Boot project, but got a java.nio.file.NoSuchFileException?
The NoSuchFileException occurs if the file is not in the specified location. A similar exception that occurs is the FileNotFoundException.
1. Loading Files from a directory
A common approach developers use to add resources is to place the files in the src/main/resources/ directory, and then read the files from that path.
Although not the best practice, this approach works if the project is run locally. This is because the project directory is used as the current working directory during runtime.
For example, using the code below, I can read user data from a file and save the value in a string.
application.properties
filePath=src/main/resources/filename.txt
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ReadUserDataFromFile.java
public class ReadUserDataFromFile {
@Value("${filePath}")
private String dataFilePath;
public String readDataFile() throws IOException {
String data = new String(Files.readAllBytes(Paths.get(filePath)));
return data;
}
}
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The file is successfully read if it is in the src/main/resources/ directory.
Now, if the project is packaged as a JAR file, the NoSuchFileException will be thrown when trying to read the file. This happens because filename.txt is at the root folder of the JAR and it cannot be accessed using the file path.
2. Creating a Resource object
A better approach and a solution to the NoSuchFileException is to create a org.springframework.core.io.Resource object in your class and set the value to point to the file.
Example:
ReadUserDataFromFile.java
public class ReadUserDataFromFile {
@Value("classpath:filename.txt")
private Resource dataFile;
public String readDataFile() throws IOException {
String data = new String(dataFile.getInputStream().readAllBytes());
return data;
}
}
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With this approach, the file can be read both locally and from JAR file.
У меня есть файл с именем «result.csv», из этого файла я хочу прочитать определенные данные и отобразить их. У меня есть этот файл в самой папке проекта eclipse. Я все еще не могу прочитать файл.
public static void main(String [] args) {
int i=0;
String filename="result.csv";
Path pathToFile = Paths.get(filename);
try (BufferedReader br = Files.newBufferedReader(pathToFile, StandardCharsets.US_ASCII)) {
// read the first line from the text file
String line = br.readLine();
// loop until all lines are read
while (i<10) {
// use string.split to load a string array with the values from
// each line of
// the file, using a comma as the delimiter
String[] attributes = line.split(",");
double x=Double.parseDouble(attributes[8]);
double y=Double.parseDouble(attributes[9]);
System.out.println(GeoHash.withCharacterPrecision(x, y, 10));
// read next line before looping
// if end of file reached, line would be null
line = br.readLine();
i++;
}
} catch (IOException ioe) {
ioe.printStackTrace();
}
}
< Сильный > ВЫВОД :
java.nio.file.NoSuchFileException: result.csv
at sun.nio.fs.WindowsException.translateToIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsFileSystemProvider.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.spi.FileSystemProvider.newInputStream(Unknown Source)
at java.nio.file.Files.newInputStream(Unknown Source)
at java.nio.file.Files.newBufferedReader(Unknown Source)
at com.uvce.cse.searchiot.geohash.TestGeoHash.main(TestGeoHash.java:19)
Может кто-нибудь указать, где именно я пропустил? и как я могу преодолеть этот или любые альтернативные методы для этого метода?
3 ответа
Лучший ответ
Проблема в том, что ваш каталог по умолчанию при запуске приложения не тот, который вы думаете. Попробуйте добавить следующую строку в ваш код сразу после создания пути:
public static void main(String [] args) {
int i=0;
String filename="result.csv";
Path pathToFile = Paths.get(filename);
System.out.println(pathToFile.toAbsolutePath());
Таким образом, вы увидите, где именно находится файл.
Как исправить это ваше решение. Вы можете использовать полную спецификацию пути вместо просто имени файла, или поместить имя файла в специальный каталог «Ресурсы» и ссылаться на него, используя относительный путь, или переместить файл туда, где находится каталог по умолчанию.
10
DodgyCodeException
27 Дек 2019 в 10:50
Проблема в том, что Java не может найти файл «result.csv» в папке проекта. Таким образом, попробуйте использовать полный путь к файлу, например, C:your_folderprojectresult.csv в переменной Path. Также я думаю, что было бы лучше использовать bufferedreader следующим образом: BufferedReader br = new BufferedReader(new FileReader(insert here the String in which is defined the path to the file)); Проверьте использование BufferedReader здесь
0
Alex Cuadrón
3 Янв 2018 в 11:26
Если ваш file("result.csv") в каталоге src, вы должны использовать «src / result.csv» вместо «result.csv» .
4
5377037
30 Янв 2019 в 14:51