I’m trying to implement a TCP connection, everything works fine from the server’s side but when I run the client program (from client computer) I get the following error:
java.net.ConnectException: Connection refused
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:351)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:213)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:200)
at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:432)
at java.net.Socket.connect(Socket.java:529)
at java.net.Socket.connect(Socket.java:478)
at java.net.Socket.<init>(Socket.java:375)
at java.net.Socket.<init>(Socket.java:189)
at TCPClient.main(TCPClient.java:13)
I tried changing the socket number in case it was in use but to no avail, does anyone know what is causing this error & how to fix it.
The Server Code:
//TCPServer.java
import java.io.*;
import java.net.*;
class TCPServer {
public static void main(String argv[]) throws Exception {
String fromclient;
String toclient;
ServerSocket Server = new ServerSocket(5000);
System.out.println("TCPServer Waiting for client on port 5000");
while (true) {
Socket connected = Server.accept();
System.out.println(" THE CLIENT" + " " + connected.getInetAddress()
+ ":" + connected.getPort() + " IS CONNECTED ");
BufferedReader inFromUser = new BufferedReader(
new InputStreamReader(System.in));
BufferedReader inFromClient = new BufferedReader(
new InputStreamReader(connected.getInputStream()));
PrintWriter outToClient = new PrintWriter(
connected.getOutputStream(), true);
while (true) {
System.out.println("SEND(Type Q or q to Quit):");
toclient = inFromUser.readLine();
if (toclient.equals("q") || toclient.equals("Q")) {
outToClient.println(toclient);
connected.close();
break;
} else {
outToClient.println(toclient);
}
fromclient = inFromClient.readLine();
if (fromclient.equals("q") || fromclient.equals("Q")) {
connected.close();
break;
} else {
System.out.println("RECIEVED:" + fromclient);
}
}
}
}
}
The Client Code:
//TCPClient.java
import java.io.*;
import java.net.*;
class TCPClient {
public static void main(String argv[]) throws Exception {
String FromServer;
String ToServer;
Socket clientSocket = new Socket("localhost", 5000);
BufferedReader inFromUser = new BufferedReader(new InputStreamReader(
System.in));
PrintWriter outToServer = new PrintWriter(
clientSocket.getOutputStream(), true);
BufferedReader inFromServer = new BufferedReader(new InputStreamReader(
clientSocket.getInputStream()));
while (true) {
FromServer = inFromServer.readLine();
if (FromServer.equals("q") || FromServer.equals("Q")) {
clientSocket.close();
break;
} else {
System.out.println("RECIEVED:" + FromServer);
System.out.println("SEND(Type Q or q to Quit):");
ToServer = inFromUser.readLine();
if (ToServer.equals("Q") || ToServer.equals("q")) {
outToServer.println(ToServer);
clientSocket.close();
break;
} else {
outToServer.println(ToServer);
}
}
}
}
}
asked Jul 29, 2011 at 16:37
Samantha CataniaSamantha Catania
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8
This exception means that there is no service listening on the IP/port you are trying to connect to:
- You are trying to connect to the wrong IP/Host or port.
- You have not started your server.
- Your server is not listening for connections.
- On Windows servers, the listen backlog queue is full.
tk_
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answered Jul 29, 2011 at 16:41
Collin PriceCollin Price
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9
I would check:
- Host name and port you’re trying to connect to
- The server side has managed to start listening correctly
- There’s no firewall blocking the connection
The simplest starting point is probably to try to connect manually from the client machine using telnet or Putty. If that succeeds, then the problem is in your client code. If it doesn’t, you need to work out why it hasn’t. Wireshark may help you on this front.
answered Jul 29, 2011 at 16:39
Jon SkeetJon Skeet
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4
You have to connect your client socket to the remote ServerSocket. Instead of
Socket clientSocket = new Socket("localhost", 5000);
do
Socket clientSocket = new Socket(serverName, 5000);
The client must connect to serverName which should match the name or IP of the box on which your ServerSocket
was instantiated (the name must be reachable from the client machine). BTW: It’s not the name that is important, it’s all about IP addresses…
answered Jul 29, 2011 at 17:21
6
I had the same problem, but running the Server before running the Client fixed it.
answered Jul 25, 2012 at 18:09
Dao LamDao Lam
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3
One point that I would like to add to the answers above is my experience—
«I hosted on my server on localhost and was trying to connect to it through an android emulator by specifying proper URL like http://localhost/my_api/login.php
. And I was getting connection refused error«
Point to note — When I just went to browser on the PC and use the same URL (http://localhost/my_api/login.php
) I was getting correct response
so the Problem in my case was the term localhost
which I replaced with the IP for my server (as your server is hosted on your machine) which made it reachable from my emulator on the same PC.
To get IP for your local machine, you can use ipconfig
command on cmd
you will get IPv4 something like 192.68.xx.yy
Voila ..that’s your machine’s IP where you have your server hosted.
use it then instead of localhost
http://192.168.72.66/my_api/login.php
Note — you won’t be able to reach this private IP from any node outside this computer. (In case you need ,you can use Ngnix for that)
answered Feb 26, 2018 at 16:50
eRaisedToXeRaisedToX
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0
I had the same problem with Mqtt broker called vernemq.but solved it by adding the following.
$ sudo vmq-admin listener show
to show the list o allowed ips and ports for vernemq
$ sudo vmq-admin listener start port=1885 -a 0.0.0.0 --mountpoint /appname --nr_of_acceptors=10 --max_connections=20000
to add any ip and your new port. now u should be able to connect without any problem.
Hope it solves your problem.
answered Apr 5, 2016 at 7:58
MrOnyanchaMrOnyancha
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1
Hope my experience may be useful to someone. I faced the problem with the same exception stack trace and I couldn’t understand what the issue was. The Database server which I was trying to connect was running and the port was open and was accepting connections.
The issue was with internet connection. The internet connection that I was using was not allowed to connect to the corresponding server. When I changed the connection details, the issue got resolved.
answered Nov 17, 2014 at 12:01
phoenixphoenix
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In my case, I gave the socket the name of the server (in my case «raspberrypi»), and instead an IPv4 address made it, or to specify, IPv6 was broken (the name resolved to an IPv6)
answered Dec 21, 2016 at 18:20
ZhyanoZhyano
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In my case, I had to put a check mark near Expose daemon on tcp://localhost:2375 without TLS
in docker
setting (on the right side of the task bar, right click on docker
, select setting
)
answered Aug 23, 2017 at 13:42
user1419243user1419243
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i got this error because I closed ServerSocket
inside a for loop that try to accept number of clients inside it (I did not finished accepting all clints)
so be careful where to close your Socket
answered May 21, 2016 at 21:07
I had same problem and the problem was that I was not closing socket object.After using socket.close(); problem solved.
This code works for me.
ClientDemo.java
public class ClientDemo {
public static void main(String[] args) throws UnknownHostException,
IOException {
Socket socket = new Socket("127.0.0.1", 55286);
OutputStreamWriter os = new OutputStreamWriter(socket.getOutputStream());
os.write("Santosh Karna");
os.flush();
socket.close();
}
}
and
ServerDemo.java
public class ServerDemo {
public static void main(String[] args) throws IOException {
System.out.println("server is started");
ServerSocket serverSocket= new ServerSocket(55286);
System.out.println("server is waiting");
Socket socket=serverSocket.accept();
System.out.println("Client connected");
BufferedReader reader=new BufferedReader(new InputStreamReader(socket.getInputStream()));
String str=reader.readLine();
System.out.println("Client data: "+str);
socket.close();
serverSocket.close();
}
}
answered May 14, 2017 at 17:13
Santosh KarnaSantosh Karna
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1
I changed my DNS network and it fixed the problem
answered Nov 23, 2019 at 9:51
You probably didn’t initialize the server or client is trying to connect to wrong ip/port.
answered Aug 10, 2020 at 16:21
Change local host to your ip address
localhost
//to you local ip
192.168.xxxx
answered Apr 28, 2021 at 10:46
Gabriel RogathGabriel Rogath
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I saw the same error message «»java.net.ConnectException: Connection refused» in SQuirreLSQL when it was trying to connect to a postgresql database through an ssh tunnel.
Example of opening tunel:
Example of error in Squirrel with Postgresql:
It was trying to connect to the wrong port. After entering the correct port, the process execution was successful.
See more options to fix this error at: https://stackoverflow.com/a/6876306/5857023
answered Jan 6, 2022 at 19:57
GenivanGenivan
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In my case, with server written in c# and client written in Java, I resolved it by specifying hostname as ‘localhost‘ in the server, and ‘[::1]‘ in the client. I don’t know why that is, but specifying ‘localhost’ in the client did not work.
Supposedly these are synonyms in many ways, but apparently, not not a 100% match. Hope it helps someone avoid a headache.
answered Aug 12, 2022 at 15:07
AlexeiOstAlexeiOst
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For those who are experiencing the same problem and use Spring
framework, I would suggest to check an http connection provider configuration. I mean RestTemplate
, WebClient
, etc.
In my case there was a problem with configured RestTemplate (it’s just an example):
public RestTemplate localRestTemplate() {
Proxy proxy = new Proxy(Proxy.Type.HTTP, new InetSocketAddress("localhost", <some port>));
SimpleClientHttpRequestFactory clientHttpReq = new SimpleClientHttpRequestFactory();
clientHttpReq.setProxy(proxy);
return new RestTemplate(clientHttpReq);
}
I just simplified configuration to:
public RestTemplate restTemplate() {
return new RestTemplate(new SimpleClientHttpRequestFactory());
}
And it started to work properly.
answered Jan 24 at 17:45
There is a service called MySQL80 that should be running to connect to the database
for windows you can access it by searching for services than look for MySQL80 service and make sure it is running
answered Jul 16, 2021 at 19:50
It could be that there is a previous instance of the client still running and listening on port 5000.
answered Jan 10, 2013 at 18:27
Michael MunseyMichael Munsey
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2
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java.net.ConnectException: Connection refused: connect is the most frequent kind of occurring networking exception in Java whenever the software is in client-server architecture and trying to make a TCP connection from the client to the server. We need to handle the exception carefully in order to fulfill the communication problem. First, let us see the possible reasons for the occurrence of java.net.ConnectException: Connection refused.
- As client and server involved, both should be in a network like LAN or internet. If it is not present, it will throw an exception on the client-side.
- If the server is not running. Usually ports like 8080, (for tomcat), 3000 or 4200 (for react/angular), 3306(MySQL), 27017(MongoDB) or occupied by some other agents or totally down i.e. instance not started.
- Sometimes a server may be running but not listening on port because of some overridden settings etc.
- Usually, for security reasons, the Firewall will be there, and if it is disallowing the communication.
- By mistake, the wrong port is mentioned in the port or the random port generation number given.
- Connection string information wrong. For example:
Connection conn = DriverManager.getConnection(“jdbc:mysql://localhost/:3306<dbname>?” + “user=<username>&password=<password>”);
Implementation: Here we are using MySQL database connectivity and connection info should be of this format. Now let us see the ways to fixing the ways of java.net.ConnectException: Connection refused. Ping the destination host by using the commands as shown below:
ping <hostname> - to test ipconfig(for windows)/ifconfig(linux) - to get network configuration netstat - statistical report
nslookup - DNS lookup name
There are tools like “Putty” are available to communicate, and it is a free implementation of Telnet and SSH for Windows and Unix.
Example 1:
Java
import
java.io;
import
java.net.*;
import
java.util.*;
public
class
GFG {
public
static
void
main(String[] args)
{
String hostname =
"127.0.0.1"
;
int
port =
80
;
try
(Socket socket =
new
Socket(hostname, port)) {
InputStream inputStream
= socket.getInputStream();
InputStreamReader inputStreamReader
=
new
InputStreamReader(inputStream);
int
data;
StringBuilder outputString
=
new
StringBuilder();
while
((data = inputStreamReader.read())
!= -
1
) {
outputString.append((
char
)data);
}
}
catch
(IOException ex) {
System.out.println(
"Connection Refused Exception as the given hostname and port are invalid : "
+ ex.getMessage());
}
}
}
Output:
Example 2: MySQL connectivity Check
Java
import
java.io.*;
import
java.util.*;
import
java.sql.*;
try
{
Connection con =
null
;
String driver =
"com.mysql.jdbc.Driver"
;
String IPADDRESS =
"localhost"
String url1
String db =
"<your dbname>"
;
String dbUser =
"<username>"
;
String dbPasswd =
"<password>"
;
Class.forName(driver).newInstance();
con = DriverManager.getConnection(url1 + db, dbUser,
dbPasswd);
System.out.println(
"Database Connection Established"
);
}
catch
(IOException ex) {
System.out.println(
"Connection Refused Exception as the given hostname and port are invalid : "
+ ex.getMessage());
}
Similarly, for other DB, we need to specify the correct port number i.e. 27017 for MongoDB be it in case of SSL (Secure socket layer) is there, prior checks of Firewall need to be checked and hence via coding we can suggest the solutions to overcome the exception
Conclusion: As readymade commands like ping, telnet, etc are available and tools like putty are available, we can check the connectivity information and overcome the exception.
Improve Article
Save Article
Improve Article
Save Article
java.net.ConnectException: Connection refused: connect is the most frequent kind of occurring networking exception in Java whenever the software is in client-server architecture and trying to make a TCP connection from the client to the server. We need to handle the exception carefully in order to fulfill the communication problem. First, let us see the possible reasons for the occurrence of java.net.ConnectException: Connection refused.
- As client and server involved, both should be in a network like LAN or internet. If it is not present, it will throw an exception on the client-side.
- If the server is not running. Usually ports like 8080, (for tomcat), 3000 or 4200 (for react/angular), 3306(MySQL), 27017(MongoDB) or occupied by some other agents or totally down i.e. instance not started.
- Sometimes a server may be running but not listening on port because of some overridden settings etc.
- Usually, for security reasons, the Firewall will be there, and if it is disallowing the communication.
- By mistake, the wrong port is mentioned in the port or the random port generation number given.
- Connection string information wrong. For example:
Connection conn = DriverManager.getConnection(“jdbc:mysql://localhost/:3306<dbname>?” + “user=<username>&password=<password>”);
Implementation: Here we are using MySQL database connectivity and connection info should be of this format. Now let us see the ways to fixing the ways of java.net.ConnectException: Connection refused. Ping the destination host by using the commands as shown below:
ping <hostname> - to test ipconfig(for windows)/ifconfig(linux) - to get network configuration netstat - statistical report
nslookup - DNS lookup name
There are tools like “Putty” are available to communicate, and it is a free implementation of Telnet and SSH for Windows and Unix.
Example 1:
Java
import
java.io;
import
java.net.*;
import
java.util.*;
public
class
GFG {
public
static
void
main(String[] args)
{
String hostname =
"127.0.0.1"
;
int
port =
80
;
try
(Socket socket =
new
Socket(hostname, port)) {
InputStream inputStream
= socket.getInputStream();
InputStreamReader inputStreamReader
=
new
InputStreamReader(inputStream);
int
data;
StringBuilder outputString
=
new
StringBuilder();
while
((data = inputStreamReader.read())
!= -
1
) {
outputString.append((
char
)data);
}
}
catch
(IOException ex) {
System.out.println(
"Connection Refused Exception as the given hostname and port are invalid : "
+ ex.getMessage());
}
}
}
Output:
Example 2: MySQL connectivity Check
Java
import
java.io.*;
import
java.util.*;
import
java.sql.*;
try
{
Connection con =
null
;
String driver =
"com.mysql.jdbc.Driver"
;
String IPADDRESS =
"localhost"
String url1
String db =
"<your dbname>"
;
String dbUser =
"<username>"
;
String dbPasswd =
"<password>"
;
Class.forName(driver).newInstance();
con = DriverManager.getConnection(url1 + db, dbUser,
dbPasswd);
System.out.println(
"Database Connection Established"
);
}
catch
(IOException ex) {
System.out.println(
"Connection Refused Exception as the given hostname and port are invalid : "
+ ex.getMessage());
}
Similarly, for other DB, we need to specify the correct port number i.e. 27017 for MongoDB be it in case of SSL (Secure socket layer) is there, prior checks of Firewall need to be checked and hence via coding we can suggest the solutions to overcome the exception
Conclusion: As readymade commands like ping, telnet, etc are available and tools like putty are available, we can check the connectivity information and overcome the exception.
Ошибка java.net.ConnectException: Connection refused является одним из самых распространенных сетевых исключений в Java. Эта ошибка возникает, когда вы работаете с архитектурой клиент-сервер и пытаетесь установить TCP-соединение от клиента к серверу.
Соединение также происходит в случае RMI (удаленного вызова метода), потому что RMI также использует протокол TCP-IP. При написании кода клиентского сокета на Java вы всегда должны обеспечивать правильную обработку этого исключения.
В этом руководстве по Java вы узнаете, почему возникает исключение при отказе в соединении и как решить проблему.
Причины
Отказ в соединении – это явный случай, когда клиент пытается подключиться через порт TCP, но не может это сделать. Вот некоторые из возможных причин, почему это происходит:
- Клиент и Сервер, один или оба из них не находятся в сети.
Да, возможно, что они не подключены к локальной сети, Интернету или любой другой сети.
- Сервер не работает.
Вторая наиболее распространенная причина – сервер не работает. Вы можете использовать следующие сетевые команды, например, ping, чтобы проверить, работает ли сервер.
- Сервер работает, но не видит порт, к которому клиент пытается подключиться.
Это еще одна распространенная причина возникновения «java.net.ConnectException: соединение отклонено», когда сервер работает, но видит другой порт. Трудно разобраться в этом случае, пока вы не проверите конфигурацию.
- Брандмауэр запрещает комбинацию хост-порт.
Почти каждая корпоративная сеть защищена. Если вы подключаетесь к сети других компаний, вам нужно убедиться, что они разрешают друг другу IP-адрес и номер порта.
- Неверная комбинация хост-портов.
Проверьте последнюю конфигурацию на стороне клиента и сервера, чтобы избежать исключения отказа в соединении.
- Неверный протокол в строке подключения.
TCP является базовым протоколом для многих высокоуровневых протоколов, включая HTTP, RMI и другие. Нужно убедиться, что вы передаете правильный протокол, какой сервер ожидает.
Если вам интересно узнать больше об этом, то изучите книгу по сетевым технологиям, такую как Java Network Programming (4-е дополнение), написанную Гарольдом Эллиоттом Расти.
Простое решение состоит в том, чтобы сначала выяснить фактическую причину исключения. Здесь важнее всего подход к поиску правильной причины и решения. Как только вы узнаете реальную причину, вам, возможно, даже не потребуется вносить какие-либо существенные изменения.
Вот несколько советов, которые могут помочь исправить ошибку java.net.ConnectException: Connection refused:
- Сначала попытайтесь пропинговать целевой хост, если хост способен пинговать, это означает, что клиент и сервер находятся в сети.
- Попробуйте подключиться к хосту и порту сервера, используя telnet. Если вы можете подключиться, значит что-то не так с вашим клиентским кодом. Кроме того, наблюдая за выводом telnet, вы узнаете, работает ли сервер или нет, или сервер отключает соединение.
I have a problem with URL in Java.
here is my program which i found in the Java Tutorial on Networking basics:
import java.io.*;
import java.net.*;
public class UrlRead
{
public static void main(String[] args) throws Exception
{
URL aURL = new URL(«http:/www.yahoo.com/»);
BufferedReader in = new BufferedReader(new InputStreamReader(aURL.openStream()));
String str;
while((str=in.readLine())!= null)
System.out.println(str);
in.close();
}
}
It compiles fine, but when i run it it gives me the following error:
Exception in thread «main» java.net.ConnectException: Connection refused: connec
t
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:305)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:171)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:158)
at java.net.Socket.connect(Socket.java:426)
at java.net.Socket.connect(Socket.java:376)
at sun.net.NetworkClient.doConnect(NetworkClient.java:139)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:386)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:602)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:303)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:264)
at sun.net.www.http.HttpClient.New(HttpClient.java:336)
at sun.net.www.http.HttpClient.New(HttpClient.java:317)
at sun.net.www.http.HttpClient.New(HttpClient.java:312)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConne
ction.java:481)
at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection
.java:472)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLCon
nection.java:574)
at java.net.URL.openStream(URL.java:960)
at UrlRead.main(UrlRead.java:14)
In the tutorial it sez:
Platform-Specific Details: Setting the Proxy Host
You can set the proxy host through the command line. Depending on your network configuration, you might also need to set the proxy port. If necessary, ask your system administrator for the name of the proxy host on your network.
UNIX
java -Dhttp.proxyHost=proxyhost
[-Dhttp.proxyPort=portNumber] URLReader
DOS shell (Windows 95/NT)
java -Dhttp.proxyHost=proxyhost
[-Dhttp.proxyPort=portNumber] URLReader
so, i tried the following :
java -Dhttp.proxyHost=10.236.133.78 UrlRead
but it didnt work ; I also tried using portnumber =80….
still the same error…..
Can anyone , please help me out here?