Sql error 42p01 error missing from clause entry for table

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  4. Fix “ERROR: missing FROM-clause entry for table” in PostgreSQL when using UNION, EXCEPT, or INTERSECT
  5. Example of Error
  6. Solution 1
  7. Solution 2
  8. Missing FROM-clause entry for table « », что делать?
  9. Missing FROM-clause entry for table « », что делать?
  10. findAndCount, error: missing FROM-clause entry for table #7367
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  17. Custom Column «ERROR: missing FROM-clause entry for table» Postgres #12304
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Fix “ERROR: missing FROM-clause entry for table” in PostgreSQL when using UNION, EXCEPT, or INTERSECT

If you’re getting “ERROR: missing FROM-clause entry for table” in PostgreSQL when using an operator such as UNION , INTERSECT , or EXCEPT , it could be because you’re qualifying a column name with its table name.

To fix this, either remove the table name or use a column alias.

Example of Error

Here’s an example of code that produces the error:

In this case I tried to order the results by the TeacherName column, but I qualified that column with the table name (I used Teachers.TeacherName to reference the column name).

Referencing tables like this doesn’t work when ordering the results of UNION , EXCEPT , or INTERSECT .

Solution 1

One way to fix this issue is to remove the table name from the ORDER BY clause:

Solution 2

Another way to fix it is to use an alias for the column:

With this option, we assign an alias to the column, and then reference that alias in the ORDER BY clause.

Источник

Missing FROM-clause entry for table « », что делать?

  • Вопрос задан более двух лет назад
  • 3618 просмотров

Простой 4 комментария

В FROM нужно указать таблицу teterika.users и условие связи с таблицей teterika.lessons.
если условие не указать, то свяжется каждая строка одной таблицы с каждой строкой другой таблицы, получится декартово произведение таблиц.

Кстати, ваш запрос не имеет смысла, потому что из teterika.users.role у вас извлечется только запись ‘tutor’ в соответствии с условием. Т.е. ваш запрос можно заменить на:

Разве что вам действительно нужно получить декартово произведение всех уроков со всеми учителями.

А как это называется,когда после запятой в select указывается условие ‘tutor’ ,этому есть название?

И кстати,мне и нужно извлечь только записи с ‘tutor’ , у меня их определённое количество

И ещё ,если моя команда находится долго в процессе обработки и не выводит мой запрос на экран,о чём это может говорить?

gowwa123, когда в SELECT указывается не имя поля, а конкретное значение, строковое или числовое, это называется константа. И это приводит к тому, что в выборку добавиться колонка, в которой, по каждой строке будет это значение.

И ещё ,если моя команда находится долго в процессе обработки и не выводит мой запрос на экран, о чём это может говорить?

Это может говорить о том, что выборка получается очень большая.

Давайте мы с вами поступим иначе. Вы опишите здесь, структуру ваших таблиц. И объясните, какую конкретно выборку надо получить. А я попробую посоветовать вам правильный запрос.

Источник

Missing FROM-clause entry for table « », что делать?

  • Вопрос задан более двух лет назад
  • 3618 просмотров

Простой 4 комментария

В FROM нужно указать таблицу teterika.users и условие связи с таблицей teterika.lessons.
если условие не указать, то свяжется каждая строка одной таблицы с каждой строкой другой таблицы, получится декартово произведение таблиц.

Кстати, ваш запрос не имеет смысла, потому что из teterika.users.role у вас извлечется только запись ‘tutor’ в соответствии с условием. Т.е. ваш запрос можно заменить на:

Разве что вам действительно нужно получить декартово произведение всех уроков со всеми учителями.

А как это называется,когда после запятой в select указывается условие ‘tutor’ ,этому есть название?

И кстати,мне и нужно извлечь только записи с ‘tutor’ , у меня их определённое количество

И ещё ,если моя команда находится долго в процессе обработки и не выводит мой запрос на экран,о чём это может говорить?

gowwa123, когда в SELECT указывается не имя поля, а конкретное значение, строковое или числовое, это называется константа. И это приводит к тому, что в выборку добавиться колонка, в которой, по каждой строке будет это значение.

И ещё ,если моя команда находится долго в процессе обработки и не выводит мой запрос на экран, о чём это может говорить?

Это может говорить о том, что выборка получается очень большая.

Давайте мы с вами поступим иначе. Вы опишите здесь, структуру ваших таблиц. И объясните, какую конкретно выборку надо получить. А я попробую посоветовать вам правильный запрос.

Источник

findAndCount, error: missing FROM-clause entry for table #7367

When I add limit and offset to this query I get error: missing FROM-clause entry for table «Instruments». When limit and offset are not in this query, it works perfectly.

I expected it to work the same with or without limit or offset. There is just an error:

Dialect: postgres
Database version: 9.5
Sequelize version: 3.30.2

The text was updated successfully, but these errors were encountered:

The issue occurs only when you append limit.I’am also waiting for the fix on this.

This issue will be fixed by appending duplicating:false on include

Appending duplicating: false breaks offset for me — anyone else seeing this? Limit works fine.

With duplicating: false, it fixes the error from happening but instead of limit 10, I get a random number, like 3 or 2 and 2 total pages of results instead of the full 6 or 4 results and 1 total page.

@Mikeysax; this may or may not help you all that much but the way we’ve «worked around» this is to perform the query twice. Once to collect the IDs of the parent entities and another perform the limit and offset. Somewhat thankfully we built an abstraction layer above sequelize that allowed us the flexibility. There’s the obvious and large downside of it requiring two SELECTs on any query that includes a where clause but for us the accuracy outweights the marginal performance concerns (it’s a pretty low percentage of the whole response time).

Here’s a non-generified started for 10:

Not stale. We’re still having to perform a double query and manual count in order to get this working.

This issue contains a code snippet that shows the problem but is not entirely self-contained (i.e. I can’t just copy-paste it and run it). Can someone please provide a SSCCE (also known as MCVE/reprex)?

Same here — adding limit breaks query containing aggregate function logic.

on main query will fix this

Same here — adding limit breaks query containing aggregate function logic.

hi i solved this problem, for you who need count and data match.

if you want to get duplicating data, you must add raw: true, and duplicating: false. and now total data and count must be same. like this :

users.findAndCountAll( <
<
«raw»: true,
«where» : <
«jobid»:req.params.jobid
>,
«attributes»:
Object.keys(this.db.model(«Run»).attributes).concat([
[sequelize.fn(‘COUNT’,sequelize.col(‘messages.id’)),»msg_count»]
]),
«include»:[
<
«model»: this.db.model(«RunMessage»),
«as» : «messages»,
«attributes»:[],
«duplicating: false
>
],
«order»:[[«createdAt»,»DESC»]],
«logging»: console.log,
«limit»: 10,
«offset»: 1
>
>)

Same here — adding limit breaks query containing aggregate function logic.

Источник

Custom Column «ERROR: missing FROM-clause entry for table» Postgres #12304

Describe the bug

Metabase can’t create a custom column even without any calculations on them for some tables.
What these tables have in common is that on the DB they are named e.g. reports__us but on the UI they are shown as «reports us». This seems to break the custom column creation

Logs

Server logs do not show anything about this error. It is like it never happens

To Reproduce
Steps to reproduce the behavior:
0. Try following these on a table with a name like «prices» and a table with a name like «prices__us_today»

  1. From home page select your psql DB
  2. Choose a schema
  3. Choose a table
  4. Click on «show editor»
  5. Click on «Custom Column»
  6. On «field formula» just choose any column and pick a name for the new column
  7. Click on «Done»
  8. Click on «Visualize»

Expected behavior

Metabase should create a new custom column without any issues. For some other tables it works without any issues but for some others it does not work

Screenshots

Information about your Metabase Installation:
<
«browser-info»: <
«language»: «en-GB»,
«platform»: «MacIntel»,
«userAgent»: «Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.132 Safari/537.36»,
«vendor»: «Google Inc.»
>,
«system-info»: <
«file.encoding»: «UTF-8»,
«java.runtime.name»: «OpenJDK Runtime Environment»,
«java.runtime.version»: «11.0.5+10»,
«java.vendor»: «AdoptOpenJDK»,
«java.vendor.url»: «https://adoptopenjdk.net/»,
«java.version»: «11.0.5»,
«java.vm.name»: «OpenJDK 64-Bit Server VM»,
«java.vm.version»: «11.0.5+10»,
«os.name»: «Linux»,
«os.version»: «4.14.171-136.231.amzn2.x86_64»,
«user.language»: «en»,
«user.timezone»: «GMT»
>,
«metabase-info»: <
«databases»: [
«postgres»
],
«hosting-env»: «unknown»,
«application-database»: «postgres»,
«application-database-details»: <
«database»: <
«name»: «PostgreSQL»,
«version»: «11.6»
>,
«jdbc-driver»: <
«name»: «PostgreSQL JDBC Driver»,
«version»: «42.2.8»
>
>,
«run-mode»: «prod»,
«version»: <
«date»: «2020-04-02»,
«tag»: «v0.35.1»,
«branch»: «release-0.35.x»,
«hash»: «e67f169»
>,
«settings»: <
«report-timezone»: «UTC»
>
>
>

Severity

It is severe since most analyst can do any transformations on this data and makes Metabase way less usable for them

Additional context
Add any other context about the problem here.

The text was updated successfully, but these errors were encountered:

Hi @rubenarevalo
I cannot reproduce your issue. Can you supply a sample table?

I noticed a new pattern. Those tables in which I receive this error have a large number of columns (30

100).
Is there a cap on the number of columns on Metabase that might be causing this issue?

@rubenarevalo No, I’ve had tables with 240 columns.

@flamber But have you tried adding an extra column from the UI for such a large size table
?

@rubenarevalo Can you please supply a sample table?

These are the DDL of two tables. The first one seems to work but the second one causes the issue that I have reported. They are both on the same schema

@rubenarevalo Which one of the tables are similar to prices ? Can you provide a full example with data as well? See #12248 (comment) for how an example could look like.
I’m pretty sure that you’re seeing errors during the sync+scan process, which is probably the root cause of this. Try doing a forced sync+scan via Admin > Databases > (db), and then check Admin > Troubleshooting > Logs for any warnings/errors during that process.

When running the async these are the errors I get this one multiple times:

Also this warn multiple times:

Also there is this info shown:

@rubenarevalo So where does the column type _text come from? I’m guessing it might have something to do with the failed sync. But it seems like the main problem relates to the failed sync, and not the double-underscore.

the double underscore is not the issue. That’s why I changed the title earlier. The only common pattern that I see it is the amount of columns. And the problem still is that when I check a table from my data source in Psql I can not create a custom column sometimes. @flamber

The fields that we complain are of unknown type _text , what are they in the actual schema? Both on the Postgres side and what you get in Admin > Data Model > Your DB > myschema.bad and check «Show original schema»

@sbelak I do not know which field Metabase complains about because it is not shown at all on the logs.
This is how the log looks like for this particular type of Warning.

I reproduced this issue on internal instance (almost 0.35.3), while working on #11519 (comment):

This is very likely fixed with #12328. Mind trying there

. it’s not 🙁 Seems to be a lazyness bug as it only crops up with big tables.

Источник

PostgreSQL error 42P01 actually makes users dumbfounded, especially the newbies.

Usually, this error occurs due to an undefined table in newly created databases.

That’s why at Bobcares, we often get requests to fix PostgreSQL errors, as a part of our Server Management Services.

Today, let’s have a look into the PostgreSQL error 42P01 and see how our Support Engineers fix it.

What is PostgreSQL error 42P01?

PostgreSQL has a well-defined error code description. This helps in identifying the reason for the error.

Today, let’s discuss in detail about PostgreSQL error 42P01. The typical error code in PostgreSQL appears as:

ERROR: relation "[Table name]" does not exist

SQL state:42P01

Here the 42P01 denotes an undefined table.

So, the code description clearly specifies the basic reason for the error.

But what does an undefined table means?

Let’s discuss it in detail.

Causes and fixes for the PostgreSQL error 42P01

Customer query on undefined tables of a database often shows up the 42P01 error.

Now let’s see a few situations when our customers get the 42P01 error. We will also see how our Support Engineers fix this error.

1. Improper database setup

Newbies to Postgres often make mistakes while creating a new database. Mostly, this improper setup ends up in a 42P01 error.

In such situations, our Support Team guides them for easy database setup.

Firstly, we create a new database. Next, we create a new schema and role. We give proper privileges to tables.

Postgres also allows users to ALTER DEFAULT PRIVILEGES.

2. Unquoted identifiers

Some customers create tables with mixed-case letters.

Usually, the unquoted identifiers are folded into lowercase. So, when the customer queries the table name with the mixed case it shows 42P01 error.

The happens as the PostgreSQL has saved the table name in lower case.

To resolve this error, our Support Engineers give mixed case table name in quotes. Also, we highly recommend to NOT use quotes in database names. Thus it would make PostgreSQL behave non-case sensitive.

3. Database query on a non-public schema

Similarly, the PostgreSQL 42P01 error occurs when a user queries a non-public schema.

Usually, this error occurs if the user is unaware of the proper Postgres database query.

For instance, the customer query on table name ‘pgtable‘ was:

SELECT * FROM  pgtable

This query is totally correct in case of a public schema. But, for a non-public schema ‘xx’ the query must be:

SELECT * FROM  "xx"."pgtable"

Hence, our Support Engineers ensure that the query uses the correct schema name.

[Still having trouble in fixing PostgreSQL errors? – We’ll fix it for you.]

Conclusion

In short, PostgreSQL error 42P01 denotes the database query is on an undefined table. This error occurs due to improper database setup, unidentified table name, and so on. Today, we saw how our Support Engineers fix the undefined table error in Postgres.

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var google_conversion_label = «owonCMyG5nEQ0aD71QM»;

Hi!

When I use a <properties> element to do a multi-column unique constraint, I get the error «missing FROM-clause entry for table» if I try to access one of my association:

Code:

<hibernate-mapping>

<properties name=»dataset_contents_dataset_id_key» unique=»true»>
  <many-to-one name=»dataset» class=»Dataset» fetch=»select»>
    <column name=»dataset_id» not-null=»true» />
  </many-to-one>
  <many-to-one name=»usrDatatype» class=»UsrDatatype» fetch=»select»>
    <column name=»type_id» not-null=»true» />
  </many-to-one>
</properties>

</hibernate-mapping>

The result is:

Code:

select
        this_.id as id3_0_,
        this_.version as version3_0_,
        this_.dataset_id as dataset3_3_0_,
        this_.type_id as type4_3_0_,
        this_.tag_lo as tag5_3_0_,
        this_.tag_hi as tag6_3_0_
    from
        cmd.dataset_contents this_
    where
        this_.dataset_id=?
        and usrdatatyp1_.type_name=?

SQL Error: 0, SQLState: 42P01
ERROR: missing FROM-clause entry for table «usrdatatyp1_»

As you can see there is no «inner join» statement added after the from!

But without <properties> I get:

Code:

select
        this_.id as id3_1_,
        this_.version as version3_1_,
        this_.dataset_id as dataset3_3_1_,
        this_.type_id as type4_3_1_,
        this_.tag_lo as tag5_3_1_,
        this_.tag_hi as tag6_3_1_,
        usrdatatyp1_.id as id30_0_,
        usrdatatyp1_.version as version30_0_,
        usrdatatyp1_.type_name as type3_30_0_
    from
        cmd.dataset_contents this_
    inner join
        cmd.usr_datatype usrdatatyp1_
            on this_.type_id=usrdatatyp1_.id
    where
        this_.dataset_id=?
        and usrdatatyp1_.type_name=?

Is this a bug or an error in the mapping?

I also tried changing the fetch option of «usrDatatype» to «join» instead of «select» to force the inner join but the alias generated by hibernate was different and I got the same error:

Code:

select
        this_.id as id3_1_,
        this_.version as version3_1_,
        this_.dataset_id as dataset3_3_1_,
        this_.type_id as type4_3_1_,
        this_.tag_lo as tag5_3_1_,
        this_.tag_hi as tag6_3_1_,
        usrdatatyp3_.id as id30_0_,
        usrdatatyp3_.version as version30_0_,
        usrdatatyp3_.type_name as type3_30_0_
    from
        cmd.dataset_contents this_
    inner join
        cmd.usr_datatype usrdatatyp3_
            on this_.type_id=usrdatatyp3_.id
    where
        this_.dataset_id=?
        and usrdatatyp1_.type_name=?

I’m using the latest hibernate version (3.2.5 GA) with PostgreSQL…

Thanks

Christian

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