Sql syntax error near declare - Исправление ошибок и поиск оптимальных решений проблем

If you’re experiencing a mysql-declare syntax error on your PC, this user guide can help. “Syntax error” means that the entire parser cannot understand what is requested because it is an invalid language command: in other words, your command breaks the grammar of the underlying programming language.

“Syntax error” means that the parser cannot understand what is being done because it does not represent the corresponding command in the language: otherwise the command violates the grammar of the programming language.

Report a syntax error in MySQL Workbench? The DECLARE syntax must be between BEGIN and END. The syntax always used is: BEGIN DECLARE data type yourVariableName1, DECLARE data type yourVariableName2, . , . . END Call the stored operation with the CALL command.

Syntax. The syntax for declaring an element in MySQL is: DECLARE variable_name data type [ DEFAULT initial_value ]

#1064 — fatal error in SQL validation syntax; production information of your MySQL server to > use the correct syntax to start using a number ofm with » in line 3

According to the MySQL labs, DECLARE is only allowed in the ideal BEGIN END block and must be at the beginning. Also, we forget the semicolon at the end of each line.

But everything seems fine to me. I have no idea! who can help?

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mysql procedure syntax error

I get an error by sending the following query (MYSQL 5.0):

This produces the following error:

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘LIMIT 1 OFFSET ac); innerloop: WHILE (kc Follow

5 Answers 5

Try to remove the while labels:

MySQL has connection-specific user-defined variables of the form @varname and declared procedure variables of the type you are using in your code sample. In my experience with procedures, sometimes only one of the types is allowed, and if I recall correctly, one of those situations may be when SELECTing INTO. You might try using user-defined variables here, as follows:

One problem may be the SET acticleid = (SELECT. ). Try with SELECT .. INTO :

Variable LIMIT in stored procedures is only supported in new MySQL versions. Note that since you dont have an ORDER BY you will get a random row. It looks like you want to use a CURSOR instead. See docs.

At the risk of seeming over-critical, I believe you should rewrite this procedure to use cursors for traversing your databases, instead of individual selects with LIMIT.

Thank for your help so far. The idea of Tom Haws proved to be correct. The variables for a SELECT INTO statement have to be user-defined. I edited my code to use cursors, and user-defined variables as followed:

And now I get an other error that I really can’t explain:

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE; OPEN articlecursor; W’ at line 6

This error confuses me because it can’t have a problem with the handler. The handler is declared as in the example of the mysql-documentation. Could the problem be that I can’t create two cursors like this?

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MySQL stored procedure syntax error after BEGIN

I am attempting to recreate a stored procedure (since I can’t edit the body). I called SHOW CREATE PROCEDURE to use the same format as the original stored procedure but when I attempt to recreate it I get the following errors:

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near » at line 11

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘DECLARE organization_id BIGINT(20) UNSIGNED’ at line 1

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘DECLARE lobby_pod_id BIGINT(20) UNSIGNED’ at line 1

I pasted into SQL Fiddle and got the same result, although pasting into MySQL Syntax Check gave me the thumbs-up. I’m sure it’s a simple miss but it isn’t that obvious to me.

1 Answer 1

You are missing the delimiter definition before and after the stored proc definition:

If you use the mysql client program to define a stored program containing semicolon characters, a problem arises. By default, mysql itself recognizes the semicolon as a statement delimiter, so you must redefine the delimiter temporarily to cause mysql to pass the entire stored program definition to the server.

To redefine the mysql delimiter, use the delimiter command. [. ] The delimiter is changed to // to enable the entire definition to be passed to the server as a single statement, and then restored to ; before invoking the procedure. This enables the ; delimiter used in the procedure body to be passed through to the server rather than being interpreted by mysql itself.

Since the stored proc definition and body was ok, syntax chack gave you the thumbs up, but the code would not run properly in your client.

Use the following skeleton for defining a stored procedure:

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Syntax issues with MySQL procedure

I have this procedure created from I could find on stack overflow. I want to get rows from all tables that have a certain column in them, for a specific value. So:

get all tables with the column

get all rows from the tables that have column value of x

I am getting this

[Code: 1064, SQL State: 42000] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘DECLARE i CURSOR FOR SELECT DISTINCT TABLE_NAME from INFORMATION_SCHEMA.COLUMNS ‘ at line 1 when running this from DBVisualizer Pro 9.5.7

The select works.

UPDATE: FROM the comments bellow I changed the code to:

I am getting the same error.

NOTE: Running

Does actually provide the correct SQL statements that would get me what I want.

UPDATE: Running it in dbForge Studio Express:

I get some other error, but the cursor part passes.

1 Answer 1

OK, so answering my own question.

Thank you @Solarflare for the very useful links.

By following this answer here, I was able to get to the last Update in the question above. Seems that the errors were caused by the fact that the PREPARE statement cannot refer to a local variable, as explained in the answer here

A statement prepared in stored program context cannot refer to stored procedure or function parameters or local variables because they go out of scope when the program ends and would be unavailable were the statement to be executed later outside the program. As a workaround, refer instead to user-defined variables, which also have session scope;

THUS, the final code is this:

Notice how I am still fetching the cursor into the varchar , but then I am also setting the variable sys_var to have the same value, before passing it to PREPARE I have also switched to a WHILE DO because it’s easier for me to use, no other reason.

Note: I have also added a parameter, but it isn’t relevant for the question.

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How can I fix MySQL error #1064?

When issuing a command to MySQL, I’m getting error #1064 «syntax error».

What does it mean?

How can I fix it?

3 Answers 3

Error #1064 means that MySQL can’t understand your command. To fix it:

Read the error message. It tells you exactly where in your command MySQL got confused.

Examine your command. If you use a programming language to create your command, use echo , console.log() , or its equivalent to show the entire command so you can see it.

Check the manual. By comparing against what MySQL expected at that point, the problem is often obvious.

Check for reserved words. If the error occurred on an object identifier, check that it isn’t a reserved word (and, if it is, ensure that it’s properly quoted).

Aaaagh!! What does #1064 mean?

Error messages may look like gobbledygook, but they’re (often) incredibly informative and provide sufficient detail to pinpoint what went wrong. By understanding exactly what MySQL is telling you, you can arm yourself to fix any problem of this sort in the future.

As in many programs, MySQL errors are coded according to the type of problem that occurred. Error #1064 is a syntax error.

What is this «syntax» of which you speak? Is it witchcraft?

Whilst «syntax» is a word that many programmers only encounter in the context of computers, it is in fact borrowed from wider linguistics. It refers to sentence structure: i.e. the rules of grammar; or, in other words, the rules that define what constitutes a valid sentence within the language.

For example, the following English sentence contains a syntax error (because the indefinite article «a» must always precede a noun):

This sentence contains syntax error a.

What does that have to do with MySQL?

Whenever one issues a command to a computer, one of the very first things that it must do is «parse» that command in order to make sense of it. A «syntax error» means that the parser is unable to understand what is being asked because it does not constitute a valid command within the language: in other words, the command violates the grammar of the programming language.

It’s important to note that the computer must understand the command before it can do anything with it. Because there is a syntax error, MySQL has no idea what one is after and therefore gives up before it even looks at the database and therefore the schema or table contents are not relevant.

How do I fix it?

Obviously, one needs to determine how it is that the command violates MySQL’s grammar. This may sound pretty impenetrable, but MySQL is trying really hard to help us here. All we need to do is…

Read the message!

MySQL not only tells us exactly where the parser encountered the syntax error, but also makes a suggestion for fixing it. For example, consider the following SQL command:

That command yields the following error message:

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘WHERE SET name=’foo» at line 1

MySQL is telling us that everything seemed fine up to the word WHERE , but then a problem was encountered. In other words, it wasn’t expecting to encounter WHERE at that point.

Messages that say . near » at line. simply mean that the end of command was encountered unexpectedly: that is, something else should appear before the command ends.

Examine the actual text of your command!

Programmers often create SQL commands using a programming language. For example a php program might have a (wrong) line like this:

If you write this this in two lines

then you can add echo $query; or var_dump($query) to see that the query actually says

Often you’ll see your error immediately and be able to fix it.

Obey orders!

MySQL is also recommending that we «check the manual that corresponds to our MySQL version for the right syntax to use«. Let’s do that.

I’m using MySQL v5.6, so I’ll turn to that version’s manual entry for an UPDATE command. The very first thing on the page is the command’s grammar (this is true for every command):

The manual explains how to interpret this syntax under Typographical and Syntax Conventions, but for our purposes it’s enough to recognise that: clauses contained within square brackets [ and ] are optional; vertical bars | indicate alternatives; and ellipses . denote either an omission for brevity, or that the preceding clause may be repeated.

We already know that the parser believed everything in our command was okay prior to the WHERE keyword, or in other words up to and including the table reference. Looking at the grammar, we see that table_reference must be followed by the SET keyword: whereas in our command it was actually followed by the WHERE keyword. This explains why the parser reports that a problem was encountered at that point.

A note of reservation

Of course, this was a simple example. However, by following the two steps outlined above (i.e. observing exactly where in the command the parser found the grammar to be violated and comparing against the manual’s description of what was expected at that point), virtually every syntax error can be readily identified.

I say «virtually all», because there’s a small class of problems that aren’t quite so easy to spot—and that is where the parser believes that the language element encountered means one thing whereas you intend it to mean another. Take the following example:

Again, the parser does not expect to encounter WHERE at this point and so will raise a similar syntax error—but you hadn’t intended for that where to be an SQL keyword: you had intended for it to identify a column for updating! However, as documented under Schema Object Names:

If an identifier contains special characters or is a reserved word, you must quote it whenever you refer to it. (Exception: A reserved word that follows a period in a qualified name must be an identifier, so it need not be quoted.) Reserved words are listed at Section 9.3, “Keywords and Reserved Words”.

The identifier quote character is the backtick (“ ` ”):

If the ANSI_QUOTES SQL mode is enabled, it is also permissible to quote identifiers within double quotation marks:

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Remove From My Forums

Question

Hello Guys,

I’m getting the following error from the code below:

Msg 156, Level 15, State 1, Procedure RemoveContainer, Line 38
Incorrect syntax near the keyword ‘DECLARE’.
Msg 156, Level 15, State 1, Procedure RemoveContainer, Line 50
Incorrect syntax near the keyword ‘OPEN’.

The declare instruction causing the problem is the following

DECLARE container_cursor CURSOR FOR

Can somebody help me spot the problem please?

Here the full script

CREATE PROCEDURE [dbo].RemoveContainer
(
  @containerId bigint
)
AS

DECLARE @fileId bigint;
DECLARE @fileName nvarchar(50);
DECLARE @lastModified datetime;
DECLARE @parentId bigint;
DECLARE @folderId bigint;
DECLARE @blockId bigint;
DECLARE @isFile bit;

with cte (ID ,Name , LastModified ,  ParentID, FolderID )
AS
 (
	 SELECT
  	 ID
		 ,Name 
		 ,GETDATE ()
		 ,ParentID
		 ,ID as FolderID
	 FROM 
	  sqlfolder 
	 WHERE id = @containerId
	 UNION ALL
	 SELECT c.ID, c.Name ,GETDATE () , c.ParentID, c.ID as FolderID
	 FROM cte p
	 INNER JOIN SqlFolder c ON p.ID = c.ParentID
)

DECLARE container_cursor CURSOR FOR 
SELECT f.ID , f.Name, f.LastModified, cte.ParentID , f.FolderID , 1 as IsfFile
FROM (      
			SELECT *, 0 AS BlockID , 0 AS IsFile
			FROM cte
			UNION ALL
			SELECT f.ID , f.Name, f.LastModified, cte.ParentID , f.FolderID , SqlFileBlock.BlockID , 1 as IsfFile 
			FROM SqlFile f 
			INNER JOIN SqlFileBlock ON SqlFileBlock.FileID = f.ID
			INNER JOIN cte ON f.FolderID = cte.ID     
   )

OPEN container_cursor;
FETCH NEXT FROM container_cursor 
INTO @fileId, @fileName, @lastModified, @parentId, @folderId, @blockId, @isFile;
  
DECLARE @blockRefCount bigint
  
WHILE @@FETCH_STATUS = 0
BEGIN
   
   SELECT @blockRefCount = COUNT(*)
   FROM SqlFileBlock
   WHERE SqlFileBlock.BlockID = @blockId
   
   IF ( @blockRefCount = 1)
   BEGIN
    DELETE
    FROM SqlBlock 
    WHERE SqlBlock.ID = @blockId
   END
   
   DELETE
   FROM SqlFileBlock
   WHERE SqlFileBlock.FileID = @fileId
     
   FETCH NEXT FROM container_cursor 
   INTO @fileId, @fileName, @lastModified, @parentId, @folderId, @blockId, @isFile
END
  
CLOSE container_cursor;
DEALLOCATE container_cursor;

THanks for any help.

Answers

New code is much shorter and easier to understand. Try
```
with AllFolders (ID ,Name , LastModified , ParentID, FolderID )
		AS
	 (
			 SELECT  		 
  		 ID
				 ,Name 
				 ,GETDATE ()
				 ,ParentID
				 ,ID as FolderID				 				 
			 FROM 
				sqlfolder 
			 WHERE id = @containerId
			 UNION ALL
			 SELECT c.ID, c.Name ,GETDATE () , c.ParentID, c.ID as FolderID
			 FROM AllFolders p
			 INNER JOIN SqlFolder c ON p.ID = c.ParentID		
		) 						 		

SELECT * INTO #TempTable
FROM AllFolders

DELETE
FROM SqlFile WHERE EXISTS (select 1 from #TempTable
WHERE SqlFile.FolderID = #TempTable.ID)
```
Also, if you don’t need to use #TempTable later in your query, you can skip the second SELECT * and use CTE directly in the DELETE statement the same way as I showed but using CTE instead of #TempTable.

For every expert, there is an equal and opposite expert. — Becker’s Law

Naomi Nosonovsky, Sr. Programmer-Analyst

My blog
- Marked as answer by
  
  Monday, April 4, 2011 7:47 PM

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Remove From My Forums

Вопрос
Hi All,

I am getting below error while executing the script, please help me resolve this error…

Msg 156, Level 15, State 1, Line 4
Incorrect syntax near the keyword ‘DECLARE’.

——————

use Test

go

Create table Memory_cnts (
Cntr varchar(max),
Value varchar(max),
)
go

INSERT INTO memory_cnts (Cntr,Value)

DECLARE @pg_size INT, @Instancename varchar(50);

SELECT @pg_size = low from master..spt_values where number = 1 and type = ‘E’

— Extract perfmon counters to a temporary table
IF OBJECT_ID(‘tempdb..#perfmon_counters’) is not null DROP TABLE #perfmon_counters
SELECT * INTO #perfmon_counters FROM sys.dm_os_performance_counters;

— Get SQL Server instance name as it require for capturing Buffer Cache hit Ratio
SELECT @Instancename = LEFT([object_name], (CHARINDEX(‘:’,[object_name])))
FROM #perfmon_counters
WHERE counter_name = ‘Buffer cache hit ratio’;

SELECT * FROM (
SELECT ‘Total Server Memory (GB)’ as Cntr,
(cntr_value/1048576.0) AS Value
FROM #perfmon_counters
WHERE counter_name = ‘Total Server Memory (KB)’
UNION ALL
SELECT ‘Target Server Memory (GB)’,
(cntr_value/1048576.0)
FROM #perfmon_counters
WHERE counter_name = ‘Target Server Memory (KB)’
UNION ALL
SELECT ‘Connection Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Connection Memory (KB)’
UNION ALL
SELECT ‘Lock Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Lock Memory (KB)’
UNION ALL
SELECT ‘SQL Cache Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘SQL Cache Memory (KB)’
UNION ALL
SELECT ‘Optimizer Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Optimizer Memory (KB) ‘
UNION ALL
SELECT ‘Granted Workspace Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Granted Workspace Memory (KB) ‘
UNION ALL
SELECT ‘Cursor memory usage (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Cursor memory usage’ and instance_name = ‘_Total’
UNION ALL
SELECT ‘Total pages Size (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name= @Instancename+’Buffer Manager’
and counter_name = ‘Total pages’
UNION ALL
SELECT ‘Database pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name = @Instancename+’Buffer Manager’ and counter_name = ‘Database pages’
UNION ALL
SELECT ‘Free pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name = @Instancename+’Buffer Manager’
and counter_name = ‘Free pages’
UNION ALL
SELECT ‘Reserved pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Reserved pages’
UNION ALL
SELECT ‘Stolen pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Stolen pages’
UNION ALL
SELECT ‘Cache Pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name=@Instancename+’Plan Cache’
and counter_name = ‘Cache Pages’ and instance_name = ‘_Total’
UNION ALL
SELECT ‘Page Life Expectency in seconds’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Page life expectancy’
UNION ALL
SELECT ‘Free list stalls/sec’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Free list stalls/sec’
UNION ALL
SELECT ‘Checkpoint pages/sec’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Checkpoint pages/sec’
UNION ALL
SELECT ‘Lazy writes/sec’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Lazy writes/sec’
UNION ALL
SELECT ‘Memory Grants Pending’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Memory Manager’
and counter_name = ‘Memory Grants Pending’
UNION ALL
SELECT ‘Memory Grants Outstanding’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Memory Manager’
and counter_name = ‘Memory Grants Outstanding’
UNION ALL
SELECT ‘process_physical_memory_low’,
process_physical_memory_low
FROM sys.dm_os_process_memory WITH (NOLOCK)
UNION ALL
SELECT ‘process_virtual_memory_low’,
process_virtual_memory_low
FROM sys.dm_os_process_memory WITH (NOLOCK)
UNION ALL
SELECT ‘Max_Server_Memory (MB)’ ,
[value_in_use]
FROM sys.configurations
WHERE [name] = ‘max server memory (MB)’
UNION ALL

SELECT ‘Min_Server_Memory (MB)’ ,
[value_in_use]
FROM sys.configurations
WHERE [name] = ‘min server memory (MB)’
UNION ALL
SELECT ‘BufferCacheHitRatio’,
(a.cntr_value * 1.0 / b.cntr_value) * 100.0
FROM sys.dm_os_performance_counters a
JOIN (SELECT cntr_value,OBJECT_NAME FROM sys.dm_os_performance_counters
WHERE counter_name = ‘Buffer cache hit ratio base’ AND
OBJECT_NAME = @Instancename+’Buffer Manager’) b ON
a.OBJECT_NAME = b.OBJECT_NAME WHERE a.counter_name = ‘Buffer cache hit ratio’
AND a.OBJECT_NAME = @Instancename+’Buffer Manager’

) AS D;

RAM

Ответы

Try the below script

use Test

—go

Create table Memory_cnts (
Cntr varchar(max),
Value sql_variant,
)
go

DECLARE @pg_size INT, @Instancename varchar(50);

SELECT @pg_size = low from master..spt_values where number = 1 and type = ‘E’

— Extract perfmon counters to a temporary table
IF OBJECT_ID(‘tempdb..#perfmon_counters’) is not null DROP TABLE #perfmon_counters
SELECT * INTO #perfmon_counters FROM sys.dm_os_performance_counters;

— Get SQL Server instance name as it require for capturing Buffer Cache hit Ratio
SELECT @Instancename = LEFT([object_name], (CHARINDEX(‘:’,[object_name])))
FROM #perfmon_counters
WHERE counter_name = ‘Buffer cache hit ratio’;

INSERT INTO memory_cnts (Cntr,Value)
SELECT * FROM (
SELECT ‘Total Server Memory (GB)’ as Cntr,
(cntr_value/1048576.0) AS Value
FROM #perfmon_counters
WHERE counter_name = ‘Total Server Memory (KB)’
UNION ALL
SELECT ‘Target Server Memory (GB)’,
(cntr_value/1048576.0)
FROM #perfmon_counters
WHERE counter_name = ‘Target Server Memory (KB)’
UNION ALL
SELECT ‘Connection Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Connection Memory (KB)’
UNION ALL
SELECT ‘Lock Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Lock Memory (KB)’
UNION ALL
SELECT ‘SQL Cache Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘SQL Cache Memory (KB)’
UNION ALL
SELECT ‘Optimizer Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Optimizer Memory (KB) ‘
UNION ALL
SELECT ‘Granted Workspace Memory (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Granted Workspace Memory (KB) ‘
UNION ALL
SELECT ‘Cursor memory usage (MB)’,
(cntr_value/1024.0)
FROM #perfmon_counters
WHERE counter_name = ‘Cursor memory usage’ and instance_name = ‘_Total’
UNION ALL
SELECT ‘Total pages Size (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name= @Instancename+’Buffer Manager’
and counter_name = ‘Total pages’
UNION ALL
SELECT ‘Database pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name = @Instancename+’Buffer Manager’ and counter_name = ‘Database pages’
UNION ALL
SELECT ‘Free pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name = @Instancename+’Buffer Manager’
and counter_name = ‘Free pages’
UNION ALL
SELECT ‘Reserved pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Reserved pages’
UNION ALL
SELECT ‘Stolen pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Stolen pages’
UNION ALL
SELECT ‘Cache Pages (MB)’,
(cntr_value*@pg_size)/1048576.0
FROM #perfmon_counters
WHERE object_name=@Instancename+’Plan Cache’
and counter_name = ‘Cache Pages’ and instance_name = ‘_Total’
UNION ALL
SELECT ‘Page Life Expectency in seconds’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Page life expectancy’
UNION ALL
SELECT ‘Free list stalls/sec’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Free list stalls/sec’
UNION ALL
SELECT ‘Checkpoint pages/sec’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Checkpoint pages/sec’
UNION ALL
SELECT ‘Lazy writes/sec’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Buffer Manager’
and counter_name = ‘Lazy writes/sec’
UNION ALL
SELECT ‘Memory Grants Pending’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Memory Manager’
and counter_name = ‘Memory Grants Pending’
UNION ALL
SELECT ‘Memory Grants Outstanding’,
cntr_value
FROM #perfmon_counters
WHERE object_name=@Instancename+’Memory Manager’
and counter_name = ‘Memory Grants Outstanding’
UNION ALL
SELECT ‘process_physical_memory_low’,
process_physical_memory_low
FROM sys.dm_os_process_memory WITH (NOLOCK)
UNION ALL
SELECT ‘process_virtual_memory_low’,
process_virtual_memory_low
FROM sys.dm_os_process_memory WITH (NOLOCK)
UNION ALL
SELECT ‘Max_Server_Memory (MB)’ ,
[value_in_use]
FROM sys.configurations
WHERE [name] = ‘max server memory (MB)’
UNION ALL
SELECT ‘Min_Server_Memory (MB)’ ,
[value_in_use]
FROM sys.configurations
WHERE [name] = ‘min server memory (MB)’
UNION ALL
SELECT ‘BufferCacheHitRatio’,
(a.cntr_value * 1.0 / b.cntr_value) * 100.0
FROM sys.dm_os_performance_counters a
JOIN (SELECT cntr_value,OBJECT_NAME FROM sys.dm_os_performance_counters
WHERE counter_name = ‘Buffer cache hit ratio base’ AND
OBJECT_NAME = @Instancename+’Buffer Manager’) b ON
a.OBJECT_NAME = b.OBJECT_NAME WHERE a.counter_name = ‘Buffer cache hit ratio’
AND a.OBJECT_NAME = @Instancename+’Buffer Manager’

) AS D;

Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/

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- Помечено в качестве ответа
  
  13 августа 2017 г. 5:32

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So, you’re creating a custom SQL query to perform a task in the database. After putting the code together and running it in PHPmyAdmin it responds with a 1064 error. It may look similar to this:

The 1064 error displays any time you have an issue with your SQL syntax, and is often due to using reserved words, missing data in the database, or mistyped/obsolete commands. So follow along and learn more about what the 1064 error is, some likely causes, and general troubleshooting steps.

Note: Since syntax errors can be hard to locate in long queries, the following online tools can often save time by checking your code and locating issues:

PiliApp MySQL Syntax Check
EverSQL SQL Query Syntax Check & Validator

Causes for the 1064 error

Reserved Words
Missing Data
Mistyped Commands
Obsolete Commands

This may seem cryptic since it is a general error pointing to a syntax issue in the SQL Query statement. Since the 1064 error can have multiple causes, we will go over the most common things that will result in this error and show you how to fix them. Follow along so you can get your SQL queries updated and running successfully.

Using Reserved Words

Every version of MySQL has its own list of reserved words. These are words that are used for specific purposes or to perform specific functions within the MySQL engine. If you attempt to use one of these reserved words, you will receive the 1064 error. For example, below is a short SQL query that uses a reserved word as a table name.

CREATE TABLE alter (first_day DATE, last_day DATE);

How to fix it:

Just because the word alter is reserved does not mean it cannot be used, it just has special requirements to use it as the MySQL engine is trying to call the functionality for the alter command. To fix the issue, you will want to surround the word with backticks, this is usually the button just to the left of the “1” button on the keyboard. The code block below shows how the code will need to look in order to run properly.

CREATE TABLE `alter` (first_day DATE, last_day DATE);

Missing Data

Sometimes data can be missing from the database. This causes issues when the data is required for a query to complete. For example, if a database is built requiring an ID number for every student, it is reasonable to assume a query will be built to pull a student record by that ID number. Such a query would look like this:

SELECT * from students WHERE studentID = $id

If the $id is never properly filled in the code, the query would look like this to the server:

SELECT * from students WHERE studentID =

Since there is nothing there, the MySQL engine gets confused and complains via a 1064 error.

How to fix it:

Hopefully, your application will have some sort of interface that will allow you to bring up the particular record and add the missing data. This is tricky because if the missing data is the unique identifier, it will likely need that information to bring it up, thus resulting in the same error. You can also go into the database (typically within phpMyAdmin) where you can select the particular row from the appropriate table and manually add the data.

Mistyping of Commands

One of the most common causes for the 1064 error is when a SQL statement uses a mistyped command. This is very easy to do and is easily missed when troubleshooting at first. Our example shows an UPDATE command that is accidentally misspelled.

UDPATE table1 SET id = 0;

How to fix it:

Be sure to check your commands prior to running them and ensure they are all spelled correctly.

Below is the syntax for the correct query statement.

UPDATE table1 SET id = 0;

Obsolete Commands

Some commands that were deprecated (slated for removal but still allowed for a period of time) eventually go obsolete. This means that the command is no longer valid in the SQL statement. One of the more common commands is the ‘TYPE‘ command. This has been deprecated since MySQL 4.1 but was finally removed as of version 5.1, where it now gives a syntax error. The ‘TYPE‘ command has been replaced with the ‘ENGINE‘ command. Below is an example of the old version:

CREATE TABLE t (i INT) TYPE = INNODB;

This should be replaced with the new command as below:

CREATE TABLE t (i INT) ENGINE = INNODB;

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Error 1064 Summary

As you can see there is more than one cause for the 1064 error within MySQL code. Now, you know how to correct the issues with your SQL Syntax, so your query can run successfully. This list will be updated as more specific instances are reported.

Источник

Ads were blocked — no problem. But keep in mind that developing HeidiSQL,
user support and hosting takes time and money. You may want to
send a donation instead.

Hi, I am new to HeidiSQL. I am moving my scripts from MSSQL to HeidiSQL and DECLARE is not being recognized in my version — 8.0.0.4396. Please help…

Thanks

Do you have a question regarding HeidiSQL or about migrating your SQL code from SQL Server to MariaDB?

— If your script is not valid SQL there’s nothing that HeidiSQL can do about it.

— If your script is valid and runs flawlessly from the command-line, they you’d you need to provide some info (the bare minimum: code, expected output, actual output).

Donor

If you move an SQL script from MSSQL to MariaDB and expect it to work there: good luck; the systems are very different.
(Especially true for triggers and stored routines.)

Thanks for trying to help me. I am trying to write a basic procedure to use a cursor. I am attaching a screen shot,

In the screen shot you will see that heidisql doesn’t treat declare or cursor as keywords.

BEGIN
DECLARE ‘crs’ cursor for
select itemnumber from salesorder;
END

You’ve tried to link a picture from your computer:

C:UsersDMS1Desktopcapture.png

It looks like you are talking about the syntax highlighter. That’d be a cosmetic issue but it doesn’t happen in my copy of HeidiSQL: DECLARE shows up bold and blue

Looks like I also have the same problem if I understand it correctly, on my HeidiSQL too the keywords DECLARE or CURSOR does not show up in bold and blue which results into compilation error/syntax error of the stored procedure.

@kalvaro do we have to change any default settings on HeidiSQL?

Syntax errors are triggered by MySQL Server, not HeidiSQL. If you get them, it probably means that your code is not valid. The syntax highlighting is just a cosmetic feature that doesn’t affect code parsing or execution.

If you provide further details (a code sample and instructions on what you do with it in HeidiSQL) we can determine if everything’s correct on HeidiSQL side.

Donor

MSSQL and MySQL connections activate a slightly different syntax highlighting. But in both, DECLARE is bold, only in MySQL it’s black and in MSSQL it’s blue. Same with CURSOR.

However, anil803, do you get any error when executing your procedure? If yes, please paste the error message here.

Here my MSSQL script

DECLARE @Cursor2 CURSOR 
DECLARE @itemNum varchar(50)
SET @Cursor2 = CURSOR FAST_FORWARD 
FOR 
Select ItemNumber 
From @Result 
OPEN @Cursor2 
FETCH NEXT FROM @Cursor2 
INTO @itemNum
WHILE @@FETCH_STATUS = 0 
BEGIN 
FETCH NEXT FROM @Cursor2 
INTO @itemNum
END 
CLOSE @Cursor2 
DEALLOCATE @Cursor2

I am trying to convert this into MariaDB, so I tried as shown below

DECLARE tempCursor2 CURSOR 
FOR 
Select ItemNumber 
From tt_Result; 
OPEN tempCursor2 
FETCH NEXT FROM tempCursor2 
INTO itemNum
WHILE @@FETCH_STATUS = 0 
BEGIN 
FETCH NEXT FROM tempCursor2 
INTO itemNum
END 
CLOSE tempCursor2 
DEALLOCATE tempCursor2

however, my stored procedure does not save, it throws me the below error

SQL Error (1064): You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ‘DECLARE tempCursor2 CURSOR
FOR
Select ItemNumber
From tt_Result;

Thanks for help

Alright, I believe I mistakenly typed DECLARE into a SQL Server query tab. It’s actually bold and black as Anse says.

Whatever, I understand you’re using the «Create new/ Stored routine» feature. When you open the store route editor you get a default body that contains this:

BEGIN
END

You’re expected to type your code inside. Otherwise, it isn’t a valid procedure body.

I too have the same problem. I am copying the examples out of the MariaDB Crash Course book and am getting this error.

QL Error (1064): You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near » at line 12.
(FYI: Line 12 is the line where the first DECLARE statement is)

I have looked SQL Keywords dropdown in Heidi, and DECLARE is not in that list. It goes from DEC to DEFAULT.

I am using the same version as above. My code is below:

#Name : ordertotal
#Parameters: onumber = order number
#taxable = 0 if not taxable, 1 if taxable
#ototal = order total variable
CREATE PROCEDURE ordertotal(
IN onumber INT,
IN taxable BOOLEAN,
OUT ototal DECIMAL(8,2)
) COMMENT ‘Obtain order total, optionally adding tax’
BEGIN
# Declare variable for total
DECLARE total DECIMAL(8,2);
# Declare tax percentage
DECLARE taxrate INT DEFAULT 6;
# Get the order total
SELECT Sum(item_price*quantity)
FROM orderitems
WHERE order_num = onumber
INTO total;
#
# Is THIS TAXABLE?
IF taxable THEN
# Yes, so add taxrate to the total
SELECT total+(total/100*taxrate) INTO total;
END IF;
#
# And finally, save to out variable
SELECT total INTO ototal;
END;

Donor

Look at line 12. There is a semicolon, which is normally used as delimiter. In HeidiSQL, you can either a) use the routine editor to create a procedure, or b) use the query tab. In the latter case, you must set a delimiter, by clicking the button on the main toolbar with the red semicolon on it, and then use that instead of semicolon in your SQL code.

Assumig you set the delimiter to //, you need the following code:

#Name : ordertotal
#Parameters: onumber = order number
#taxable = 0 if not taxable, 1 if taxable
#ototal = order total variable
CREATE PROCEDURE ordertotal(
IN onumber INT,
IN taxable BOOLEAN,
OUT ototal DECIMAL(8,2)
) COMMENT 'Obtain order total, optionally adding tax'
BEGIN
# Declare variable for total
DECLARE total DECIMAL(8,2)//
# Declare tax percentage
DECLARE taxrate INT DEFAULT 6//
# Get the order total
SELECT Sum(item_price*quantity)
FROM orderitems
WHERE order_num = onumber
INTO total//
#
# Is THIS TAXABLE?
IF taxable THEN
# Yes, so add taxrate to the total
SELECT total+(total/100*taxrate) INTO total//
END IF//
#
# And finally, save to out variable
SELECT total INTO ototal//
END;

Thank you for your quick reply. Works like a charm.

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Источник

mysql procedure syntax error

5 Answers 5

MySQL stored procedure syntax error after BEGIN

1 Answer 1

Syntax issues with MySQL procedure

1 Answer 1

How can I fix MySQL error #1064?

3 Answers 3

Aaaagh!! What does #1064 mean?

What is this «syntax» of which you speak? Is it witchcraft?

What does that have to do with MySQL?

How do I fix it?

Read the message!

Examine the actual text of your command!

Obey orders!

A note of reservation

Question

Answers

Вопрос

Ответы

Causes for the 1064 error

Using Reserved Words

Missing Data

Mistyping of Commands

Obsolete Commands

Error 1064 Summary