Syntax error insert to complete block - Исправление ошибок и поиск оптимальных решений проблем

import java.util.*;

public class Programming {

    public static void main(String[] args) {
        //Scanner scan = new Scanner( System.in );

        int l=0;
        StringBuilder password = new StringBuilder();

        public static boolean matchCharAt(StringBuilder password, int l){
            l = password.length();
            if (l < 0 || l > 100){
                return false;
            }

            for (int i = 0; i < password.length();i++){
                if (!Character.isLetter(password.charAt(l)))
                    return false;
            }
            return true;

        }
    }

It says I have an error on the line with { for (l=0; l < 100; l++); }, but i’m not sure if thats where the Curly brace error is. It might not be a curly brace error, i’m unsure, but I was hoping I could get some help to not have this error.

Mahm00d

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asked Apr 21, 2012 at 17:23

You never close the main() method block:

public static void main(String[] args) {
    //Scanner scan = new Scanner( System.in );

    int l=0;
    StringBuilder password = new StringBuilder();

    {
        for (l = 0; l < 100; l++);
    }
}  //HERE!

Besides this loop:

for (l = 0; l < 100; l++);

is not doing anything except changing the value of l to 100. Also the loop is surrounded with a block that has no practical sense. I can only guess this is what you wanted:

for (l = 0; l < 100; l++) {
    matchCharAt(password, l);
    //...
}

answered Apr 21, 2012 at 17:27

Tomasz NurkiewiczTomasz Nurkiewicz

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This is corollary to your main problem, but you are also changing an argument in this method

public static boolean matchCharAt(StringBuilder password, int l){
        l = password.length();
        if (l < 0 || l > 100){
            return false;
        }

If you’re passing in l, then you’re going to be changing its value with l = password.length().

answered Apr 21, 2012 at 17:31

David BDavid B

2,68818 silver badges25 bronze badges

I’m not sure exactly what you want. This should at least compile:

public class SomeClass {

  public static void main(String[] args) {
      //Scanner scan = new Scanner( System.in );

      int l=0;
      StringBuilder password = new StringBuilder();

      for (l = 0; l < 100; l++) {
        ; // Does nothing...
      }
  } // end of "main()"

  public static boolean matchCharAt(StringBuilder password, int l){
    l = password.length();
    if (l < 0 || l > 100){
        return false;
    }

    for (int i = 0; i < password.length();i++){
        if (!Character.isLetter(password.charAt(l)))
            return false;
    }

    return true;
  } // end of "matchCharAt()"

 } // end of class

assylias

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answered Apr 21, 2012 at 17:30

paulsm4paulsm4

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I’m keep getting an error with my code. I’m producing an app to produce quotes. Can anyone help me with this? No matter what I try I get «Syntax Error: Insert «}» to complete block.» When I insert «}» it gives me an error saying that my code is «unreachable» and when I add a bracket to make it reachable it takes me back to the first error and it just loops. It’s driving me crazy! Can anyone help? Thanks! Here is my code:

   {

    vbjokes = (Button) findViewById(R.id.bjokes);
    vbabout = (Button) findViewById(R.id.babout);
    vtvdisplay = (TextView) findViewById(R.id.tvdisplay);
    vbjokes.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub


        }
    });
    vbabout.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub
            vtvdisplay.setText("                                                                 Thank you for downloading Punny Jokes! 
            vtvdisplay.setTextColor(Color.BLACK);
            vtvdisplay.setTextSize((float) 20d);
            vtvdisplay.setBackgroundColor(Color.GRAY);

        }
    });


    final View controlsView = findViewById(R.id.fullscreen_content_controls);
    final View contentView = findViewById(R.id.tvdisplay);


    mSystemUiHider = SystemUiHider.getInstance(this, contentView,
            HIDER_FLAGS);
    mSystemUiHider.setup();
    mSystemUiHider
            .setOnVisibilityChangeListener(new SystemUiHider.OnVisibilityChangeListener() {
                int mControlsHeight;
                int mShortAnimTime;

                @Override
                @TargetApi(Build.VERSION_CODES.HONEYCOMB_MR2)
                public void onVisibilityChange(boolean visible) {
                    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB_MR2) {

                        if (mControlsHeight == 0) {
                            mControlsHeight = controlsView.getHeight();
                        }
                        if (mShortAnimTime == 0) {
                            mShortAnimTime = getResources().getInteger(
                                    android.R.integer.config_shortAnimTime);
                        }
                        controlsView
                                .animate()
                                .translationY(visible ? 0 : mControlsHeight)
                                .setDuration(mShortAnimTime);
                    } else {

                        controlsView.setVisibility(visible ? View.VISIBLE
                                : View.GONE);
                    }

                    if (visible && AUTO_HIDE) {
                        delayedHide(AUTO_HIDE_DELAY_MILLIS);
                    }
                }
            });

    contentView.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            if (TOGGLE_ON_CLICK) {
                mSystemUiHider.toggle();
            } else {
                mSystemUiHider.show();
            }
        }
    });


    findViewById(R.id.babout).setOnTouchListener(
            mDelayHideTouchListener);

        }

asked Aug 6, 2013 at 23:38

vtvdisplay.setText(" Thank you for downloading Punny Jokes!

It looks like you’re missing a "); at the end or you copied and pasted it wrong.

answered Aug 6, 2013 at 23:43

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Содержание

Top 8 Common Java Errors for Beginners — and How to Solve Them
Tue Jun 8 2021 by Matthew Wallace
Syntax Errors
Working with semicolons (;)
Braces or parentheses [(), <>]
Double Quotes or Quotation Marks (“ ”)
Other Miscellaneous Errors
Accessing the “Un-Initialized” Variables
Accessing the “Out of Scope” Variables
Modifying the “CONSTANT” Values
Misinterpretted Use of Operators ( == vs .equals())
Accessing a non-static resource from a static method
Conclusion
Syntax Error Insert To Complete Blockstatements
Syntax error, insert «;» to complete BlockStatements .
Syntax error, insert «Finally» to complete BlockStatements .
Syntax Error, Insert Finally To Complete BlockStatements .
Compilation error: «Syntax error, insert «; » to complete .
fix java8 compilation broblems in Inputs · Issue #2904 .
How to detect an entity the player is looking at .
Eclipse Community Forums: Newcomers » Syntax error, insert .
Eclipse Community Forums: Java Development Tools (JDT .
«Syntax Error insert enumbody to complete blockstatements .
Syntax Error Insert To Complete Blockstatements Fixes & Solutions
Syntax error insert finally to complete blockstatements

Top 8 Common Java Errors for Beginners — and How to Solve Them

Tue Jun 8 2021 by Matthew Wallace

Did you know that in Java’s standard library, there are a total of more than 500 different exceptions! There lots of ways for programmers to make mistakes — each of them unique and complex. Luckily we’ve taken the time to unwrap the meaning behind many of these errors, so you can spend less time debugging and more time coding. To begin with, let’s have a look at the syntax errors!

Syntax Errors

If you just started programming in Java, then syntax errors are the first problems you’ll meet! You can think of syntax as grammer in English. No joke, syntax errors might look minimal or simple to bust, but you need a lot of practice and consistency to learn to write error-free code. It doesn’t require a lot of math to fix these, syntax just defines the language rules. For further pertinent information, you may refer to java syntax articles.

Working with semicolons (;)

Think of semi-colons (;) in Java as you think of a full-stop (.) in English. A full stop tells readers the message a sentence is trying to convey is over. A semi-colon in code indicates the instruction for that line is over. Forgetting to add semi-colons (;) at the end of code is a common mistake beginners make. Let’s look at a basic example.

This snippet will produce the following error:

You can resolve this error by adding a ; at the end of line 3.

Braces or parentheses [(), <>]

Initially, it can be hard keeping a track of the starting / closing parenthesis or braces. Luckily IDEs are here to help. IDE stands for integrated development environment, and it’s a place you can write and run code. Replit for example, is an IDE. Most IDEs have IntelliSense, which is auto-complete for programmers, and will add closing brackets and parentheses for you. Despite the assistance, mistakes happen. Here’s a quick example of how you can put an extra closing bracket or miss the ending brace to mess up your code.

If you try to execute this, you’ll get the following error.

You can resolve this exception by removing the extra ) on line 9.

Double Quotes or Quotation Marks (“ ”)

Another pit fall is forgetting quotation marks not escaping them propperly. The IntelliSense can rescue you if you forget the remaining double quotes. If you try including quotation marks inside strings, Java will get confused. Strings are indicated using quotation marks, so having quotation marks in a string will make Java think the string ended early. To fix this, add a backslash () before quotation marks in strings. The backslash tells Java that this string should not be included in the syntax.

In order for you avoid such exceptions, you can add backslahes to the quotes in the string on line 4.

Here’s your required output, nicely put with double quotes! 🙂

Other Miscellaneous Errors

Accessing the “Un-Initialized” Variables

If you’re learning Java and have experience with other programming languages (like C++) then you might have a habit of using un-initialized variables (esp integers). Un-initialized variables are declared variables without a value. Java regulates this and doesn’t allow using a variable that has not been initialized yet.

If you attempt to access an uninitialized variable then you’ll get the following exception.

You can initialize the variable “contactNumber” to resolve this exception.

Accessing the “Out of Scope” Variables

If you define a variable in a certain method you’re only allowed to access that in the defined scope of it. Like each state has their legitimate currency, and that cannot be used in another state. You cannot use GBP in place of USD in America. Similarly, a variable defined in one method has restricted scope to it. You cannot access a local variable defined in some function in the main method. For further detailed illustration let’s look at an example.

As soon as you run this snippet, you’ll get the exception

You can not access the variable “country” outside the method getPersonalDetails since its scope is local.

Modifying the “CONSTANT” Values

Java and other programming languages don’t allow you to update or modify constant variables. You can use the keyword “final” before a variable to make it constant in Java. Apart from that, it’s a convention to write a constant in ALL CAPS for distinction purposes, As a constant resource is often used cross methods across a program.

Remove line 4 for the perfectly functional code.

Misinterpretted Use of Operators ( == vs .equals())

A lot of beginners start working with integers while learning the basics of a programming language. So it can be a challenge to remember that for string comparisons we use the “.equals()” method provided by Java and not == operator like in integers.

The output is contradictory because “today” and “thirdWeekDay” are referred to 2 different objects in the memory. However, the method “.equals()” compares the content stored in both arrays and returns true if it’s equal, false otherwise.

Accessing a non-static resource from a static method

If you want to access a non-static variable from a static method [let’s say the main method] then you need to create an instance of that object first. But if you fail to do that, java will get angry.

You can fix it, just by replacing line 9.

Conclusion

Programming errors are a part of the learning curve. Frequent errors might slow you down. But as a new programmer, it’s okay to learn things slowly. Now you’re familiar with some of the most common issues. Make sure you practise enough to get ahead of them. Happy coding and keep practising! 🙂

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Syntax Error Insert To Complete Blockstatements

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Syntax error, insert «;» to complete BlockStatements .

https://stackoverflow.com/questions/12144206/syntax-error-insert-to-complete-blockstatements-greendroid

Syntax error, insert вЂњ;вЂќ to complete BlockStatements GreenDroid. Ask Question Asked 8 years, 4 months ago. Active 8 years, 4 months ago. Viewed 19k times 2. 1. When I try to make a make an Android app with GreenDroid, so I put the code in there but it asks for a ; while there already is one.

Syntax error, insert «Finally» to complete BlockStatements .

https://stackoverflow.com/questions/32803435/syntax-error-insert-finally-to-complete-blockstatements-cant-fix

How do i get rid of «Syntax error, insert «Finally» to complete BlockStatements» on line 100 public class Afp < . /** * Initialize the contents of the frame.

Syntax Error, Insert Finally To Complete BlockStatements .

https://www.dreamincode.net/forums/topic/206870-syntax-error-insert-finally-to-complete-blockstatements/

Dec 24, 2010 · syntax error, insert finally to complete BlockStatements Posted 24 December 2010 — 11:26 AM what do i do when i get this error? syntax error, insert finally to complete BlockStatements

Compilation error: «Syntax error, insert «; » to complete .

http://drools-moved.46999.n3.nabble.com/Compilation-error-quot-Syntax-error-insert-quot-quot-to-complete-BlockStatements-quot-td55980.html

Re: Compilation error: «Syntax error, insert «; » to complete BlockStatements » They are only needed on the RHS (Right Hand Side) of the rules where the syntax is Java like. Scott Burrows

fix java8 compilation broblems in Inputs · Issue #2904 .

https://github.com/checkstyle/checkstyle/issues/2904

base on #2881 The following files had their comment about compilable by java 8 removed until we fix them: InputFinalLocalVariableNameLambda .

How to detect an entity the player is looking at .

https://www.spigotmc.org/threads/how-to-detect-an-entity-the-player-is-looking-at.139310/

Apr 11, 2016 · — Syntax error, insert «;» to complete BlockStatements — Syntax error, insert «>» to complete ClassBody #11 TheGamerPlayz, Apr 11, 2016. Pannkaka. You cannot make a method inside another method. Use the method that @camden posted instead.

https://www.eclipse.org/forums/index.php/t/1080194/

Aug 17, 2016 · Home » Newcomers » Newcomers » Syntax error, insert «;» to complete BlockStatements line 7 (Eclipse and Java for Total Beginners — Lesson 4, Syntax error, . Syntax error, insert «;» to complete BlockStatements line 7 [message #1740732 is a reply to message #1740731] Wed, 17 August 2016 20:29 Nitin Dahyabhai Messages: 3955

https://www.eclipse.org/forums/index.php/t/848893/

Exception in thread «main» java.lang.Error: Unresolved compilation problems: The method For(Class ) is undefined for the type Application Syntax error, insert «. class» to complete Expression Syntax error, insert «)» to complete MethodInvocation Syntax error, insert «;» to complete BlockStatements i cannot be resolved to a variable

«Syntax Error insert enumbody to complete blockstatements .

https://www.spigotmc.org/threads/syntax-error-insert-enumbody-to-complete-blockstatements.245598/

Jun 05, 2017 · Search titles only; Posted by Member: Separate names with a comma. Newer Than: Search this thread only; Search this forum only. Display results as threads

Syntax Error Insert To Complete Blockstatements Fixes & Solutions

We are confident that the above descriptions of Syntax Error Insert To Complete Blockstatements and how to fix it will be useful to you. If you have another solution to Syntax Error Insert To Complete Blockstatements or some notes on the existing ways to solve it, then please drop us an email.

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Syntax error insert finally to complete blockstatements

les erreurs (classe : Error ),

Les exceptions non vГ©rifiГ©es par le compilateur (unchecked exceptions) sont les exceptions de type Throwable , de type (ou sous type de) Error , ou de type (ou sous type de) RuntimeException .

RГ©sultat d’exГ©cution du code :
NOTE : L’exception ArithmeticException est une sous-classe de la classe RuntimeException (unchecked exception), et donc le compilateur ne se plaindra pas si on ne gГЁre pas cette exception par un bloc try/catch :

RГ©sultat d’exГ©cution du code :
Cette fois ci, lorsque la JVM a rencontrГ© l’exception, le programme a terminГ© son exГ©cution.

NOTE : La gestion des exceptions permet d’arrГЄter la propagation des exceptions dans la pile d’exГ©cution (appels de mГ©thodes).
En absence de la gestion des exceptions, elles peuvent ГЄtre propagГ©es jusqu’Г la mГ©thode principale (main) ; ce qui signifie l’arrГЄt du programme s’elles ne sont pas gГЁrer par cette mГ©thode.

Remarque : Bien que la gestion des exceptions est possible pour toutes les exceptions de type (ou sous type de) Throwable , elle n’a cependant un vrai intГ©rГЄt que pour les exceptions de type (ou sous type de) Exception . En fait, le programme doit gГ©rer seulement les exceptions applicatives, et rare les cas oГ№ on s’intГ©ressera Г gГ©rer les exceptions de type Error (erreurs JVM par exemple).

try

finally : permet de faire des actions spГ©cifiques suite Г l’exГ©cution du bloc du code de la clause try et, si c’est le cas, de la clause catch.

Les rГЁgles d’utilisation des clauses try, catch, finally sont :

La clause try doit ГЄtre utilisГ©e avec la clause catch et/ou finally. Si la clause try n’est pas suivie par au moins une des deux clauses catch et finally, le compilateur gГ©nГ©rera une erreur de compilation.
Chaque gestion d’exception peut avoir autant de clauses catch si nГ©cessaire.

Le type de l’exception d’une clause catch doit avoir un type d’exception diffГ©rents des autres clauses catch.
Sinon le compilateur va gГ©nГ©rer une erreur de compilation :

Le type de l’exception d’une clause doit ГЄtre un sous type ou un type diffГ©rent des types des autres clauses dГ©finies au dessous de cette clause.
Sinon le compilateur va gГ©nГ©rer une erreur de compilation :

Lorsque le bloc d’une clause est exГ©cutГ©, les autres clauses ne seront pas exГ©cutГ©es, et cela mГЄme si le code de cette clause dГ©clenche lui aussi une exception.
La nouvelle exception doit ГЄtre gГ©rer Г l’intГ©rieur d’un autre bloc try catch.

RГ©sultat d’exГ©cution du code :

La clause finally peut ГЄtre utilisГ©e avec ou sans des clauses catch.
Une clause finally sans les clauses catch peut ГЄtre utile dans les cas oГ№ on veut faire un traitement spГ©cial sans pour autant arrГЄter la propagation de l’exception.

RГ©sultat d’exГ©cution du code :

Le code de la clause finally va toujours ГЄtre exГ©cutГ© peu importe s’il y a des clauses catch ou pas.
Il va ГЄtre exГ©cutГ© mГЄme si le code d’une clause est exГ©cutГ© et que celui-ci lance une nouvelle exception.

RГ©sultat d’exГ©cution du code :

Une mГ©thode qui lancent des exceptions (ou qui fait appel Г des mГ©thodes qui sont susceptibles de lancer eux mГЄme des exceptions) peut dГ©clarer ces exceptions et ainsi les autres mГ©thodes qui font appels Г cette mГ©thode pourront savoir qu’elle lance des exceptions et ainsi les gГ©rer ou les dГ©clarer Г leurs tours.

Bien que la dГ©claration peut inclure tous les types des exceptions (Throwable, Error, Exception, RuntimeException), le compilateur ne fait la vГ©rification que pour les exceptions de type Exception.
C’est la mГЄme rГЁgle qu’on a vu ci-dessus pour la gestion des exceptions vГ©rifiables par le compilateur.
En fait on vient de la gГ©nГ©raliser, puisque la rГЁgle en Java est : gГ©rer ou dГ©clarer une exception, sinon le compilateur va gГ©nГ©rer une erreur de compilation.

Pour dГ©clarer une exception on utilise le mot clГ© throws comme suit : throws Exception
Pour dГ©clarer plusieurs exceptions, on les sГ©pare par des virgules comme suit : throws ArithmeticException, Exception

RГ©sultat d’exГ©cution du code :
Une mГ©thode doit soit gГ©rer ou dГ©clarer les exceptions dГ©clarГ©es par les mГ©thodes appelГ©es par le code de cette mГ©thode (cella s’applique uniquement aux exceptions vГ©rifiables par le compilateur).
Dans l’exemple prГ©cГ©dent la mГ©thode main gГЁre l’exception lancГ©e par la mГ©thode divide, au cas contraire la mГ©thode main doit dГ©clarer elle aussi cette exception (sinon le compilateur va gГ©nГ©rer une erreur de compilation).

RГ©sultat d’exГ©cution du code :
Notez que le code n’a pas terminГ© son exГ©cution Г cause que l’exception n’a pas Г©tГ© gГ©rer par un bloc try catch et comme la mГ©thode main et la derniГЁre mГ©thode de la pile d’exГ©cution, la JVM arrГЄte donc la propagation de l’exception et met fin Г l’exГ©cution du programme.

La crГ©ation d’une nouvelle exception est utile lorsqu’on veut gГ©rer un type particulier d’exception et ainsi la distinguer des autres exceptions.

La classe de la nouvelle exception doit Г©tendre une des classes Throwable, Error, ou Exception ou n’import quelle autre classe qui hГ©rite de ces classes.

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Синтаксическая ошибка: вставьте «}» для завершения блока [закрыто]

Я продолжаю получать сообщение об ошибке с моим кодом. Я создаю приложение для создания котировок. Кто-нибудь может мне с этим помочь? Что бы я ни пытался, я получаю «Синтаксическая ошибка: вставьте «}», чтобы завершить блок». Когда я вставляю «}», это дает мне сообщение об ошибке, говорящее, что мой код «недостижим», и когда я добавляю скобку, чтобы сделать его доступным, он возвращает меня к первой ошибке, и он просто зацикливается. Это сводит меня с ума! Кто-нибудь может помочь? Спасибо! Вот мой код:

   {

    vbjokes = (Button) findViewById(R.id.bjokes);
    vbabout = (Button) findViewById(R.id.babout);
    vtvdisplay = (TextView) findViewById(R.id.tvdisplay);
    vbjokes.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub


        }
    });
    vbabout.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub
            vtvdisplay.setText("                                                                 Thank you for downloading Punny Jokes! 
            vtvdisplay.setTextColor(Color.BLACK);
            vtvdisplay.setTextSize((float) 20d);
            vtvdisplay.setBackgroundColor(Color.GRAY);

        }
    });


    final View controlsView = findViewById(R.id.fullscreen_content_controls);
    final View contentView = findViewById(R.id.tvdisplay);


    mSystemUiHider = SystemUiHider.getInstance(this, contentView,
            HIDER_FLAGS);
    mSystemUiHider.setup();
    mSystemUiHider
            .setOnVisibilityChangeListener(new SystemUiHider.OnVisibilityChangeListener() {
                int mControlsHeight;
                int mShortAnimTime;

                @Override
                @TargetApi(Build.VERSION_CODES.HONEYCOMB_MR2)
                public void onVisibilityChange(boolean visible) {
                    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB_MR2) {

                        if (mControlsHeight == 0) {
                            mControlsHeight = controlsView.getHeight();
                        }
                        if (mShortAnimTime == 0) {
                            mShortAnimTime = getResources().getInteger(
                                    android.R.integer.config_shortAnimTime);
                        }
                        controlsView
                                .animate()
                                .translationY(visible ? 0 : mControlsHeight)
                                .setDuration(mShortAnimTime);
                    } else {

                        controlsView.setVisibility(visible ? View.VISIBLE
                                : View.GONE);
                    }

                    if (visible && AUTO_HIDE) {
                        delayedHide(AUTO_HIDE_DELAY_MILLIS);
                    }
                }
            });

    contentView.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            if (TOGGLE_ON_CLICK) {
                mSystemUiHider.toggle();
            } else {
                mSystemUiHider.show();
            }
        }
    });


    findViewById(R.id.babout).setOnTouchListener(
            mDelayHideTouchListener);

        }

1 ответы

vtvdisplay.setText(" Thank you for downloading Punny Jokes!

Похоже, тебе не хватает "); в конце или вы скопировали и вставили это неправильно.

ответ дан 04 мая ’19, 14:05

Не тот ответ, который вы ищете? Просмотрите другие вопросы с метками

java
android

or задайте свой вопрос.

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