Syntax error unexpected eof while parsing python

В Python простой, но строгий синтаксис. Если забыть закрыть блок кода, то возникнет ошибка «SyntaxError: unexpected EOF while parsing». Это происходит часто, например, когда вы забыли добавить как минимум одну строку в цикл for.

В этом материале разберемся с этой ошибкой, и по каким еще причинам она возникает. Разберем несколько примеров, чтобы понять, как с ней справляться.

Ошибка «SyntaxError: unexpected EOF while parsing» возникает в том случае, когда программа добирается до конца файла, но не весь код еще выполнен. Это может быть вызвано ошибкой в структуре или синтаксисе кода.

EOF значит End of File. Представляет собой последний символ в Python-программе.

Python достигает конца файла до выполнения всех блоков в таких случаях:

• Если забыть заключить код в специальную инструкцию, такую как, циклы for или while, или функцию.
• Не закрыть все скобки на строке.

Разберем эти ошибки на примерах построчно.

Пример №1: незавершенные блоки кода

Циклы for и while, инструкции if и функции требуют как минимум одной строки кода в теле. Если их не добавить, результатом будет ошибка EOF.

Рассмотрим такой пример цикла for, который выводит все элементы рецепта:

ingredients = ["325г муки", "200г охлажденного сливочного масла", "125г сахара", "2 ч. л. ванили", "2 яичных желтка"]

for i in ingredients:

Определяем переменную ingredients, которая хранит список ингредиентов для ванильного песочного печенья. Используем цикл for для перебора по каждому из элементов в списке. Запустим код и посмотрим, что произойдет:

File "main.py", line 4
    
                     	^
SyntaxError: unexpected EOF while parsing

Внутри цикла for нет кода, что приводит к ошибке. То же самое произойдет, если не заполнить цикл while, инструкцию if или функцию.

Для решения проблемы требуется добавить хотя бы какой-нибудь код. Это может быть, например, инструкция print() для вывода отдельных ингредиентов в консоль:

for i in ingredients:
	print(i)

Запустим код:

325г муки
200г охлажденного сливочного масла
125г сахара
2 ч. л. ванили
2 яичных желтка

Код выводит каждый ингредиент из списка, что говорит о том, что он выполнен успешно.

Если же кода для такого блока у вас нет, используйте оператор pass как заполнитель. Выглядит это вот так:

for i in ingredients:
	pass

Такой код ничего не возвращает. Инструкция pass говорит о том, что ничего делать не нужно. Такое ключевое слово используется в процессе разработке, когда разработчики намечают будущую структуру программы. Позже pass заменяются на реальный код.

Пример №2: незакрытые скобки

Ошибка «SyntaxError: unexpected EOF while parsing» также возникает, если не закрыть скобки в конце строки с кодом.

Напишем программу, которая выводит информацию о рецепте в консоль. Для начала определим несколько переменных:

name = "Капитанская дочка"
author = "Александр Пушкин"
genre = "роман"

Отформатируем строку с помощью метода .format():

print('Книга "{}" - это {}, автор {}'.format(name, genre, author)

Значения {} заменяются на реальные из .format(). Это значит, что строка будет выглядеть вот так:

Книга "НАЗВАНИЕ" - это ЖАНР, автор АВТОР

Запустим код:

File "main.py", line 7

              ^
SyntaxError: unexpected EOF while parsing

На строке кода с функцией print() мы закрываем только один набор скобок, хотя открытыми были двое. В этом и причина ошибки.

Решаем проблему, добавляя вторую закрывающую скобку («)») в конце строки с print().

print('Книга "{}" - это {}, автор {}'.format(name, genre, author))

Теперь на этой строке закрываются две скобки. И все из них теперь закрыты. Попробуем запустить код снова:

Книга "Капитанская дочка" это роман. Александр Пушкин

Теперь он работает. То же самое произойдет, если забыть закрыть скобки словаря {} или списка [].

Выводы

Ошибка «SyntaxError: unexpected EOF while parsing» возникает, если интерпретатор Python добирается до конца программы до выполнения всех строк.

Для решения этой проблемы сперва нужно убедиться, что все инструкции, включая while, for, if и функции содержат код. Также нужно проверить, закрыты ли все скобки.

Have you seen the syntax error “unexpected EOF while parsing” when you run a Python program? Are you looking for a fix? You are in the right place.

The error “unexpected EOF while parsing” occurs when the interpreter reaches the end of a Python file before every code block is complete. This can happen, for example, if any of the following is not present: the body of a loop (for / while), the code inside an if else statement, the body of a function.

We will go through few examples that show when the “unexpected EOF while parsing” error occurs and what code you have to add to fix it.

Let’s get started!

How Do You Fix the EOF While Parsing Error in Python?

If the unexpected EOF error occurs when running a Python program, this is usually a sign that some code is missing.

This is a syntax error that shows that a specific Python statement doesn’t follow the syntax expected by the Python interpreter.

For example, when you use a for loop you have to specify one or more lines of code inside the loop.

The same applies to an if statement or to a Python function.

To fix the EOF while parsing error in Python you have to identify the construct that is not following the correct syntax and add any missing lines to make the syntax correct.

The exception raised by the Python interpreter will give you an idea about the line of code where the error has been encountered.

Once you know the line of code you can identify the potential code missing and add it in the right place (remember that in Python indentation is also important).

SyntaxError: Unexpected EOF While Parsing with a For Loop

Let’s see the syntax error that occurs when you write a for loop to go through the elements of a list but you don’t complete the body of the loop.

In a Python file called eof_for.py define the following list:

animals = ['lion', 'tiger', 'elephant']

Then write the line below:

for animal in animals:

This is what happens when you execute this code…

$ python eof_for.py
  File "eof_for.py", line 4
    
                          ^
SyntaxError: unexpected EOF while parsing

ASyntaxError is raised by the Python interpreter.

The exception “SyntaxError: unexpected EOF while parsing” is raised by the Python interpreter when using a for loop if the body of the for loop is missing.

The end of file is unexpected because the interpreter expects to find the body of the for loop before encountering the end of the Python code.

To get rid of theunexpected EOF while parsing error you have to add a body to the for loop. For example a single line that prints the elements of the list:

for animal in animals:
    print(animal)

Update the Python program, execute it and confirm that the error doesn’t appear anymore.

Unexpected EOF While Parsing When Using an If Statement

Let’s start with the following Python list:

animals = ['lion', 'tiger', 'elephant']

Then write the first line of a if statement that verifies if the size of the animals list is great than 2:

if len(animals) > 2:

At this point we don’t add any other line to our code and we try to run this code.

$ python eof_if.py 
  File "eof_if.py", line 4
    
                        ^
SyntaxError: unexpected EOF while parsing

We get back the error “unexpected EOF while parsing”.

The Python interpreter raises the unexpected EOF while parsing exception when using an if statement if the code inside the if condition is not present.

Now let’s do the following:

• Add a print statement inside the if condition.
• Specify an else condition immediately after that.
• Don’t write any code inside the else condition.

animals = ['lion', 'tiger', 'elephant']

if len(animals) > 2:
    print("The animals list has more than two elements")
else:

When you run this code you get the following output.

$ python eof_if.py 
  File "eof_if.py", line 6
    
         ^
SyntaxError: unexpected EOF while parsing

This time the error is at line 6 that is the line immediately after the else statement.

The Python interpreter doesn’t like the fact that the Python file ends before the else block is complete.

That’s why to fix this error we add another print statement inside the else statement.

if len(animals) > 2:
    print("The animals list has more than two elements")
else:
    print("The animals list has less than two elements")

$ python eof_if.py 
The animals list has more than two elements

The error doesn’t appear anymore and the execution of the Python program is correct.

Note: we are adding the print statements just as examples. You could add any lines you want inside the if and else statements to complete the expected structure for the if else statement.

Unexpected EOF While Parsing With Python Function

The error “unexpected EOF while parsing” occurs with Python functions when the body of the function is not provided.

To replicate this error write only the first line of a Python function called calculate_sum(). The function takes two parameters, x and y.

def calculate_sum(x,y):

At this point this is the only line of code in our program. Execute the program…

$ python eof_function.py
  File "eof_function.py", line 4
    
    ^
SyntaxError: unexpected EOF while parsing

The EOF error again!

Let’s say we haven’t decided yet what the implementation of the function will be. Then we can simply specify the Python pass statement.

def calculate_sum(x,y):
    pass

Execute the program, confirm that there is no output and that the Python interpreter doesn’t raise the exception anymore.

The exception “unexpected EOF while parsing” can occur with several types of Python loops: for loops but also while loops.

On the first line of your program define an integer called index with value 10.

Then write a while condition that gets executed as long as index is bigger than zero.

index = 10

while (index > 0):

There is something missing in our code…

…we haven’t specified any logic inside the while loop.

When you execute the code the Python interpreter raises an EOF SyntaxError because the while loop is missing its body.

$ python eof_while.py 
  File "eof_while.py", line 4
    
                      ^
SyntaxError: unexpected EOF while parsing

Add two lines to the while loop. The two lines print the value of the index and then decrease the index by 1.

index = 10

while (index > 0):
    print("The value of index is " + str(index))
    index = index - 1

The output is correct and the EOF error has disappeared.

$ python eof_while.py
The value of index is 10
The value of index is 9
The value of index is 8
The value of index is 7
The value of index is 6
The value of index is 5
The value of index is 4
The value of index is 3
The value of index is 2
The value of index is 1

Unexpected EOF While Parsing Due to Missing Brackets

The error “unexpected EOF while parsing” can also occur when you miss brackets in a given line of code.

For example, let’s write a print statement:

print("Codefather"

As you can see I have forgotten the closing bracket at the end of the line.

Let’s see how the Python interpreter handles that…

$ python eof_brackets.py
  File "eof_brackets.py", line 2
    
                      ^
SyntaxError: unexpected EOF while parsing

It raises the SyntaxError that we have already seen multiple times in this tutorial.

Add the closing bracket at the end of the print statement and confirm that the code works as expected.

Unexpected EOF When Calling a Function With Incorrect Syntax

Now we will see what happens when we define a function correctly but we miss a bracket in the function call.

def print_message(message):
    print(message)


print_message(

The definition of the function is correct but the function call was supposed to be like below:

print_message()

Instead we have missed the closing bracket of the function call and here is the result.

$ python eof_brackets.py
  File "eof_brackets.py", line 6
    
                  ^
SyntaxError: unexpected EOF while parsing

Add the closing bracket to the function call and confirm that the EOF error disappears.

Unexpected EOF While Parsing With Try Except

A scenario in which the unexpected EOF while parsing error can occur is when you use a try statement and you forget to add the except or finally statement.

Let’s call a function inside a try block without adding an except block and see what happens…

def print_message(message):
    print(message)


try:
    print_message()

When you execute this code the Python interpreter finds the end of the file before the end of the exception handling block (considering that except is missing).

$ python eof_try_except.py 
  File "eof_try_except.py", line 7
    
                    ^
SyntaxError: unexpected EOF while parsing

The Python interpreter finds the error on line 7 that is the line immediately after the last one.

That’s because it expects to find a statement that completes the try block and instead it finds the end of the file.

To fix this error you can add an except or finally block.

try:
    print_message()
except:
    print("An exception occurred while running the function print_message()")

When you run this code you get the exception message because we haven’t passed an argument to the function. Theprint_message() function requires one argument to be passed.

Modify the function call as shown below and confirm that the code runs correctly:

print_message("Hello")

Conclusion

After going through this tutorial you have all you need to understand why the “unexpected EOF while parsing” error occurs in Python.

You have also learned how to find at which line the error occurs and what you have to do to fix it.

Aim:

In this article, we will discuss how to fix SyntaxError: unexpected EOF while parsing in Python?

This article dissects our problem with examples and helps you get a firm grip on the minute details, which ultimately leads to our problem.

◈ What Is A Syntax Error In Python?

Syntax errors occur when the Python compiler cannot understand the source code written by you and is unable to generate the machine code. Syntax error generally appear at compile-time and are reported by the interpreter.

Example: Incomplete if statement that lacks a colon at the end.

Output:

File “D:/PycharmProjects/pythonProject1/EOL_SyntaxError.py”, line 2
if age<18
SyntaxError: invalid syntax

◈ What does unexpected EOF while parsing mean in Python?

EOF is the abbreviation for End of File.

The EOFError is raised in situations where the end of a file is reached before running every block of code in the file.

Let’s visualize the following:

Once upon a time, there was a boy who wa
……

Most of you will find a glitch because you ran into an “unexpected end of paragraph” above. Not only does the paragraph above end mid-sentence, but also it ends mid-word! Now, imagine – Python is in a similar situation. That’s when it returns SyntaxError: unexpected EOF while parsing.

The following scenarios will help you to understand the occurrence of such errors and the ways to solve them.

✨ Scenario 1: Incomplete Loop/Function/If Statement

You must include at least one line of code within a For loop, While loop, if statements or functions; otherwise, it leads to the occurrence of Unexpected EOF error.

➥ Example 1: Unexpected End Of For Loop

Output:

File “D:/PycharmProjects/pythonProject1/EOL_SyntaxError.py”, line 3
^
SyntaxError: unexpected EOF while parsing

✍️ Solution:

You can use a print statement within the for loop body if you want to print the items of the lang list. You may also opt to use the pass statement if you do not wish to print anything and also avoid the error.

Output:

Java
Python
C
C++
Golang

➥ Example 2: Unexpected End Of Function

Output:

File “D:/PycharmProjects/pythonProject1/EOL_SyntaxError.py”, line 4
^
SyntaxError: unexpected EOF while parsing

✍️ Solution:

The above error occurred because Python found an unexpected end to the function func(). Therefore you can avoid this error by using a pass statement within the function or by using a print statement to print something that meets your requirement.

Output:

I love Java2Blog!

✨ Scenario 2: Missing Parenthesis

If you forget to close all the parenthesis in a line of code within your program, then Python will raise the SyntaxError: unexpected EOF while parsing.

➥ Example 1:

Output:

SyntaxError: unexpected EOF while parsing

✍️ Solution:

The above error occurred because of a minute syntactic mistake wherein we forgot to close the print statement using a closing parenthesis ). To solve the error you simply have to close the print statement properly.

Output:

The founder of Java2Blog is Arpit and its lead author is Shubham Sayon

➥ Example 2:

Let us have a look at another case where a dictionary is incomplete and Python raises SyntaxError: unexpected EOF while parsing.

Output:

File “D:/PycharmProjects/pythonProject1/EOL_SyntaxError.py”, line 6
^
SyntaxError: unexpected EOF while parsing

✍️ Solution:

Close the dictionary using the closing parenthesis to avoid the error.

Output:

Java2Blog

✨ Scenario 3: Using try without except/finally

You will encounter the SyntaxError: unexpected EOF while parsing if you define a try block. However, you do not have an except or finally block.

➥ Example:

Output:

File “D:/PycharmProjects/pythonProject1/EOL_SyntaxError.py”, line 3
^
SyntaxError: unexpected EOF while parsing

✍️ Solution:

To overcome this error, you have to define an except or finally block corresponding to the try block.

Output:

Hello Folks!

✨ Scenario 4: Using the eval() function on str()

Python does not permit the usage of eval() function on str() and it leads to the SyntaxError: unexpected EOF while parsing.

➥ Example:

Output:

File “D:/PycharmProjects/pythonProject1/EOL_SyntaxError.py”, line 2, in
text3 = eval(str(text1))
File “”, line 1
a string
^
SyntaxError: unexpected EOF while parsing

✍️ Solution:

To avoid the above error you can replace the str() function with the repr() function.

Output:

eval() Works!

Conclusion

To summarize our discussion, “SyntaxError: unexpected EOF while parsing” error in Python occurs when Python reaches the end of execution abruptly before every line of code has finished its execution. This happens when:

• The code has an incomplete Loop/Function/If Statement.
• The code has a try block but no finally or except blocks.
• You are trying to implement eval() on str().

To avoid this error, you should ensure that all the statements within your code are complete and have proper opening and closing parenthesis. Also, make sure that you define an except or finally block if the code has a try block.

I hope this article was helpful. Please subscribe and stay tuned for more exciting articles. Happy Learning! 📚

What is unexpected EOF while parsing error?

The SyntaxError: unexpected EOF while parsing error also is known as parsing error where the control in the program/code reaches to the end, but there are more code/program lines that are needed to be compiled. It can be due to some incomplete syntax, i.e., something missing in the code which terminated further execution of the program.

While debugging the program line by line in the console, you will notice that the error occurred because of any single wrong statement not due to block of code. 

Therefore we need to take care of these points to avoid this ‘SyntaxError: Unexpected EOF while parsing’ error.

See the following example:-

Example with Error:

dictionary={

'name':'ram',

print(dictionary['name'].upper()

Output:

SyntaxError: unexpected EOF while parsing

In the above code example, we have created a dictionary and did not close the ‘}’bracket, So when the compiler was compiling the code, it couldn’t find the ‘}’ bracket and trow the error code “unexpected EOF while parsing” as output.

Example with Solution:

dictionary={

'name':'ram',

}

print(dictionary['name'].upper())

Output:

Output: RAM

Program –1 Error 

The Python program below is a combination of the ‘Try and Except’ block. In this program, we can see the ‘Try’ block is present, but the ‘Except’ block is missing, and therefore, the control terminates itself due to incomplete syntax. And you get SyntaxError: unexpected EOF while parsing error

def chalu ():
    print ("is where the control ")  
    cont_abc ()
def Cont_abc (): 
    cont_0=raw_input("Command enter ") 
    try: 
        if cont_0 == 'right ':                            
           next_screen () 
        else:  
            print ('right.')  
            cont_abc ()  

Output:

File "Main.py", line 14

SyntaxError: unexpected EOF while parsing

Program –2 Solved Program

Now in this program, the keyword combination with key statements ‘Try and Except’ is complete, so the program execution is completed.

def chalu ():
    print ("is where the control ")  
    cont_abc ()
def Cont_abc (): 
    cont_0=raw_input("Command enter ") 
    try: 
        if cont_0 == 'right ':                            
           next_screen () 
        else:  
            print ('right.')   
            cont_abc ()
    except Exception as ex:
            print(ex)

Output

...Program finished with exit code 0

How to resolve this Error?

To avoid this error, please do the following

• You need to take care of the parameters and their syntaxes. Need to check all function and their closing statements.
• Before executing the program, please check if all the parameter of functions is defined.
• Also, check and correct the indentation of the program

Conclusion

It is an error that occurred at the time of parsing, which implies that it is a syntax error caused due to missing closing statements or incomplete argument of the function.

Therefore you need to take care of the indentation of the program, which helps you to solve this error.

SyntaxError: unexpected EOF while parsing

SyntaxError: unexpected EOF while parsing

example_list = [1, 2, 3, 4, 5]

for i, item in enumerate(example_list):
    print(f'index : {i} value : {item}'

File "<ipython-input-3-babbd3ba1063>", line 4
    print(f'index : {i} value : {item}'
                                       ^
SyntaxError: unexpected EOF while parsing

example_list = [1, 2, 3, 4, 5]

for i, item in enumerate(example_list):
    print(f'index : {i} value : {item}')

index : 0 value : 1
index : 1 value : 2
index : 2 value : 3
index : 3 value : 4
index : 4 value : 5

example_list = [1, 2, 3, 4, 5]

for item in example_list:

File "<ipython-input-5-5927dfecd199>", line 3
    for item in example_list:
                             ^
SyntaxError: unexpected EOF while parsing

example_list = [1, 2, 3, 4, 5]

for item in example_list:
    print(item)

File "<ipython-input-7-20a42a968335>", line 2
    print('hello')
                  ^
SyntaxError: unexpected EOF while parsing

try:
    print('hello')
except:
    print('failed')

try:
    print('hello')
finally:
    print('printing anyway')

hello
printing anyway

The SyntaxError: unexpected EOF while parsing occurs if the Python interpreter reaches the end of your source code before executing all the code blocks. This happens if you forget to close the parenthesis or if you have forgotten to add the code in the blocks statements such as for, if, while, etc. To solve this error check if all the parenthesis are closed properly and you have at least one line of code written after the statements such as for, if, while, and functions.

What is an unexpected EOF while parsing error in Python?

EOF stands for End of File and SyntaxError: unexpected EOF while parsing error occurs where the control in the code reaches the end before all the code is executed. 

Generally, if you forget to complete a code block in python code, you will get an error “SyntaxError: unexpected EOF while parsing.”

Most programming languages like C, C++, and Java use curly braces { } to define a block of code. Python, on the other hand, is a “block-structured language” that uses indentation.

A Python program is constructed from code blocks. A block is a piece of Python program text that is executed as a unit. The following are blocks: a module, a function body, and a class definition. Each command typed interactively is a block.

There are several reasons why we get this error while writing the python code. Let us look into each of the scenarios and solve the issue.

Sometimes if the code is not indented properly you will get unindent does not match any outer indentation error.

Scenario 1 – Missing parenthesis or Unclosed parenthesis

One of the most common scenarios is an unclosed parenthesis (), brackets [], and curly braces {} in the Python code.

• Parenthesis is mainly used in print statements, declaring tuples, calling the built-in or user-defined methods, etc.
• Square brackets are used in declaring the Arrays, Lists, etc in Python
• Curly braces are mainly used in creating the dictionary and JSON objects.

In the below example, we have taken simple use cases to demonstrate the issue. In larger applications, the code will be more complex and we should use IDEs such as VS Code, and PyCharm which detect and highlights these common issues to developers.

# Paranthesis is not closed properly in the Print Statement
print("Hello"

# Square bracket is not closed while declaring the list
items =[1,2,3,4,5


# Curly Braces is not closed while creating the dictionary
dictionary={ 'FirstName':'Jack'

Output

SyntaxError: unexpected EOF while parsing

If you look at the above code, we have a print statement where the parenthesis has not closed, a list where the square bracket is not closed, and a dictionary where the curly braces are not closed. Python interpreter will raise unexpected EOF while parsing.

Solution :

We can fix the issue by enclosing the braces, parenthesis, and square brackets properly in the code as shown below.

# Paranthesis is now closed properly in the Print Statement
print("Hello")

# Square bracket is now closed while declaring the list
items =[1,2,3,4,5]
print(items)

# Curly Braces is now closed while creating the dictionary
dictionary={ 'FirstName':'Jack'}
print(dictionary)

Output

Hello
[1, 2, 3, 4, 5]
{'FirstName': 'Jack'}

If we try to execute the program notice the error is gone and we will get the output as expected.

Scenario 2: Incomplete functions along with statements, loops, try and except 

The other scenario is if you have forgotten to add the code after the Python statements, loops, and methods.

• if Statement / if else Statement
• try-except statement
• for loop
• while loop
• user-defined function

Python expects at least one line of code to be present right after these statements and loops. If you have forgotten or missed to add code inside these code blocks Python will raise SyntaxError: unexpected EOF while parsing

Let us look at some of these examples to demonstrate the issue. For demonstration, all the code blocks are added as a single code snippet.

# Code is missing after the for loop
fruits = ["apple","orange","grapes","pineapple"]
for i in fruits :

# Code is missing after the if statement
a=5
if (a>10):


# Code is missing after the else statement
a=15
if (a>10):
    print("Number is greater than 10")
else:


# Code is missing after the while loop
num=15
while(num<20):

# Code is missing after the method declaration
def add(a,b):

Output

SyntaxError: unexpected EOF while parsing

Solution :

We can fix the issue by addressing all the issues in each code block as mentioned below.

• for loop: We have added the print statement after the for loop.
• if else statement: After the conditional check we have added the print statement which fixes the issue.
• while loop: We have added a print statement and also incremented the counter until the loop satisfies the condition.
• method: The method definition cannot be empty we have added the print statement to fix the issue.

# For loop fixed
fruits = ["apple", "orange", "grapes", "pineapple"]
for i in fruits:
    print(i)

# if statement fixed
a = 5
if a > 10:
    print("number is greated than 10")
else:
    print("number is lesser than 10")

# if else statement fixed
a = 15
if a > 10:
    print("Number is greater than 10")
else:
    print("number is lesser than 10")


# while loop fixed
num = 15
while num < 20:
    print("Current Number is", num)
    num = num + 1


# Method fix
def add(a, b):
    print("Hello Python")


add(4, 5)

Output

apple
orange
grapes
pineapple
number is lesser than 10
Number is greater than 10
Current Number is 15
Current Number is 16
Current Number is 17
Current Number is 18
Current Number is 19
Hello Python

Conclusion

The SyntaxError: unexpected EOF while parsing occurs if the Python interpreter reaches the end of your source code before executing all the code blocks. To resolve the SyntaxError: unexpected EOF while parsing in Python, make sure that you follow the below steps.

1. Check for Proper Indentation in the code.
2. Make sure all the parenthesis, brackets, and curly braces are opened and closed correctly.
3. At least one statement of code exists in loops, statements, and functions.
4. Verify the syntax, parameters, and the closing statements

In this Python tutorial, we will discuss what is Syntax Error- Unexpected EOF while parsing in python, also we will see EOL while scanning string literal and how to resolve these error.

In python, Unexpected EOF while parsing python where the control of the program reaches to the end. This error arises due to some incomplete syntax or something missing in the code.

Example:

my_list = [ 2, 4, 52, 7, 88, 99, 10]
value = min(my_list)
print(value

After writing the above code (unexpected EOF while parsing python), Ones you will print “ value” then the error will appear as a “ SyntaxError: unexpected EOF while parsing ”. Here, this error arises because we have created a list, and while printing value closing parenthesis ” ) ” is missing and it cannot find the closing bracket, due to which it throws an error.

You can refer to the below screenshot unexpected EOF while parsing python

This is SyntaxError: Unexpected EOF while parsing python.

To solve this, we need to take care of parameters and their syntaxes, also we need to check all functions and their closing statements.

Example:

my_list = [ 2, 4, 52, 7, 88, 99, 10]
value = min(my_list)
print(value)

After writing the above code the unexpected EOF while parsing python is resolved by giving the closing parenthesis ” ) ” in the value then the output will appear as a “ 2 ” and the error is resolved. So, the SyntaxError is resolved unexpected EOF while parsing python.

You can refer to the below screenshot how to solve the unexpected EOF while parsing python

Python EOL while scanning string literal

EOL stands for “end of line” this error occurs when the python interpreter reaches the end of the line while searching for a string literal or a character within the line. This error is experienced by every python developer. This is due to the missing quotation in a string or you close a string using the wrong symbol.

Example:

class info :
    def method_s (self):
        print("This is method_s of info class.)
obj = info()
obj.method_s()

After writing the above code (python EOL while scanning string literal), Ones you will print then the error will appear as a “ SyntaxError: EOL while scanning string literal ”. Here, this error arises because it reaches the end of a string literal and finds that the quotation mark is missing.

You can refer to the below screenshot python EOL while scanning string literal.

To solve this “end of line” error while scanning string literal we have to check whether the string is closed or not, and also you have to check that you closed the string using the right symbol. Here, the error is due to a missing quotation in the string.

Example:

class info :
    def method_s (self):
        print("This is method_s of info class.")
obj = info()
obj.method_s()

After writing the above code python end of the line while scanning string literal is fixed by giving the double quotes at the end and then the output will appear as “ This is method_s of info class. ”, and the error is resolved. So, in this way, SyntaxError end of the line is resolved.

You can refer to the below screenshot how to solve the end of the line while scanning string literal

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This is how we can solve the SyntaxError: unexpected EOF while parsing python and Python EOL while scanning string literal.