System indexoutofrangeexception как исправить

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C# supports the creation and manipulation of arrays, as a data structure. The index of an array is an integer value that has value in the interval [0, n-1], where n is the size of the array. If a request for a negative or an index greater than or equal to the size of the array is made, then the C# throws an System.IndexOutOfRange Exception. This is unlike C/C++ where no index of the bound check is done. The IndexOutOfRangeException is a Runtime Exception thrown only at runtime. The C# Compiler does not check for this error during the compilation of a program.

Example:

Runtime Error:

Unhandled Exception:
System.IndexOutOfRangeException: Index was outside the bounds of the array.
at GFG.Main (System.String[] args) <0x40bdbd50 + 0x00067> in :0
[ERROR] FATAL UNHANDLED EXCEPTION: System.IndexOutOfRangeException: Index was outside the bounds of the array.
at GFG.Main (System.String[] args) <0x40bdbd50 + 0x00067> in :0

Output:

1
2
3
4
5

Here if you carefully see, the array is of size 5. Therefore while accessing its element using for loop, the maximum value of index can be 4 but in our program, it is going till 5 and thus the exception.

Let’s see another example using ArrayList:

Runtime Error: Here error is a bit more informative than the previous one as follows:

Unhandled Exception:
System.ArgumentOutOfRangeException: Index was out of range. Must be non-negative and less than the size of the collection.
Parameter name: index
at System.Collections.ArrayList.get_Item (Int32 index) <0x7f2d36b2ff40 + 0x00082> in :0
at GFG.Main (System.String[] args) <0x41b9fd50 + 0x0008b> in :0
[ERROR] FATAL UNHANDLED EXCEPTION: System.ArgumentOutOfRangeException: Index was out of range. Must be non-negative and less than the size of the collection.
Parameter name: index
at System.Collections.ArrayList.get_Item (Int32 index) <0x7f2d36b2ff40 + 0x00082> in :0
at GFG.Main (System.String[] args) <0x41b9fd50 + 0x0008b> in :0

Lets understand it in a bit of detail:

• Index here defines the index we are trying to access.
• The size gives us information of the size of the list.
• Since size is 2, the last index we can access is (2-1)=1, and thus the exception

The correct way to access array is :

for (int i = 0; i < ar.Length; i++) 
{
}

Handling the Exception:

• Use for-each loop: This automatically handles indices while accessing the elements of an array.
  • Syntax:

    for(int variable_name in array_variable)
    {
         // loop body
    }
    
    

• Use Try-Catch: Consider enclosing your code inside a try-catch statement and manipulate the exception accordingly. As mentioned, C# won’t let you access an invalid index and will definitely throw an IndexOutOfRangeException. However, we should be careful inside the block of the catch statement, because if we don’t handle the exception appropriately, we may conceal it and thus, create a bug in your application.

In this article, we are going to learn about one of the most common exceptions in C# – IndexOutOfRangeException.

To download the source code for this article, you can visit our GitHub repository.

We’re going to learn about various situations where this exception gets raised and about the preventive measures we can take to make our applications more robust.

IndexOutOfRangeException gets thrown when we try to access a member of an array or a collection using an invalid index.

An invalid index means either the index is lower than the collection’s lower bound or greater than/equal to the number of elements in the collection.

We are going to cover some common examples of where IndexOutOfRangeException is raised.

Another exception you’re familiar with is NullReferenceException. If you want to learn more, we have an article about NullReferenceException as well.

Array – Upper Bound

The upper bound of a zero-based array – should be one less than the array length.

Let’s create an integer array and run a for loop on it to demonstrate the exception:

var numbersArray = new int[] { 1, 2, 3, 4, 5 };

for (var i = 0; i <= numbersArray.Length; i++)
{
    Console.WriteLine(numbersArray[i]);
}

The for loop runs perfectly fine when i < 5, but it fails for i == 5 because there is no element at the position 6 (index 5 – {0, 1, 2, 3, 4 , 5}):

1
2
3
4
5
Unhandled exception. System.IndexOutOfRangeException: Index was outside the bounds of the array.

How to Fix IndexOutOfRangeException?

Now, let’s see how we can fix IndexOutOfRangeException in this case.

Let’s remove the equality condition and just check for i < numbersArray.Length :

var numbersArray = new int[] { 1, 2, 3, 4, 5 };

for (var i = 0; i < numbersArray.Length; i++)
{
    Console.WriteLine(numbersArray[i]);
}

And if we run the application again, there’s no exception this time:

1
2
3
4
5

Array – Custom Lower Bound

We can create an array with a custom lower bound by using the Array.CreateInstance(Type elementType, int[] lengths, int[] lowerBounds) method:

var customLowerBoundArray = Array.CreateInstance(typeof(int), new int[] { 5 }, new int[] { 1 });
var value = 2;

for (var i = 0; i < customLowerBoundArray.Length; i++)
{
    customLowerBoundArray.SetValue(value, i);
    value *= 5;
}

The code snippet throws IndexOutOfRangeException when we try to set the array element’s value at an index lower than the custom lower bound.

The lower bound is 1, but the first element is set at position 0 (i == 0).

Solution

Let’s see how we can prevent the exception in this case:

var customLowerBoundArray = Array.CreateInstance(typeof(int), new int[] { 5 }, new int[] { 1 });
var value = 2;
 
for (var i = customLowerBoundArray.GetLowerBound(0); i <= customLowerBoundArray.GetUpperBound(0); i++)
{
    customLowerBoundArray.SetValue(value, i);
    value *= 5;
}

for (var i = customLowerBoundArray.GetLowerBound(0); i <= customLowerBoundArray.GetUpperBound(0); i++)
{
    Console.WriteLine(customLowerBoundArray.GetValue(i));
}

We make use of Array.GetLowerBound() and Array.GetUpperBound() methods to determine the start and end index of the custom lower bound array:

2
10
50
250
1250

List – Incorrect Arguments

This scenario is a little bit different:

Console.WriteLine("Please enter a search argument: ");

var searchArg = Convert.ToInt32(Console.ReadLine());
var multiplesOfFive = new List<int> { 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 };

Console.WriteLine($"Let's display the multiples of 5 greater than {searchArg}");

var startIndex = multiplesOfFive.IndexOf(searchArg);

for (var i = startIndex; i < multiplesOfFive.Count; i++)
{
    Console.WriteLine(multiplesOfFive[i]);
}

We have a List<int> to which we add the first 10 multiples of 5.

We take input from the user – searchArg, and use this input to display numbers greater than the input.

An input other than the numbers present in the list results in an index of -1, which raises the ArgumentOutOfRangeException.

An input of 12 breaks the code and we get the exception:

Please enter a search argument:
12
Let's display the even numbers greater than 12
Unhandled exception. 
System.ArgumentOutOfRangeException: 
Index was out of range. Must be non-negative and less than the size of the collection.

Solution

To prevent the exception, we can add a check:

Console.WriteLine("Please enter a search argument!!!");

var searchArg = Convert.ToInt32(Console.ReadLine());
var multiplesOfFive = new List<int> { 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 };

var startIndex = multiplesOfFive.IndexOf(searchArg);
if (startIndex < 0)
{
    Console.WriteLine($"The number {searchArg} does not exist in the list.");
}
else
{
    Console.WriteLine($"Let's display the even numbers greater than {searchArg}");
    for (var i = startIndex; i < multiplesOfFive.Count; i++)
    {
        Console.WriteLine(multiplesOfFive[i]);
    }
}

An incorrect input (other than the numbers in the list) results in a user-friendly message:

Please enter a search argument:
22
The number 22 does not exist in the list.

IndexOutOfRangeException vs ArgumentOutOfRangeException

Lists raise ArgumentOutOfRangeException when an item is accessed at an invalid index, whereas arrays raise IndexOutOfRangeException for the same behavior:

IList<string> tempList = new string[] { "0" };
var foo = tempList[-1]; //ArgumentOutOfRangeException

string[] tempArray = new string[] { "0" };
var bar = tempArray[-1]; //IndexOutOfRangeException

Two Arrays – Different Lengths

The IndexOutOfRangeException is raised when we attempt to assign an array element to a different array that has fewer elements than the first array:

var array1 = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
var array2 = new int[7];

array2[array1.Length - 1] = array1[array1.Length - 1];

The array1 length is 10, while the array2 length is 7.

We are trying to assign the last element of array1 to array2, but since array2 is smaller (length is 7), we get the IndexOutOfRangeException.

Solution

Now, let’s see how we can prevent the exception:

var array1 = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
var array2 = new int[array1.Length];

array2[array1.Length - 1] = array1[array1.Length - 1];
Console.WriteLine($"The last element of array2 is: {array2[array2.Length - 1]}");

We initialize the second array as similar to the first array’s length:

The last element of array2 is: 10

Getting Confused Between an Index and the Value of That Index

Let’s see this case with an example:

var oddNumbersArray = new int[] { 1, 3, 5, 7, 9, 11, 13, 15, 17, 19 };
foreach (var number in oddNumbersArray)
{
    Console.WriteLine($"The odd number is: {oddNumbersArray[number]}");
}

We have an array of odd numbers, we run a foreach loop on the array and try to access the element using the index and not the element itself.

We start encountering  IndexOutOfRangeException when the number == 11 acts as the index.

There is no element at the 11th index:

The odd number is: 3
The odd number is: 7
The odd number is: 11
The odd number is: 15
The odd number is: 19
Unhandled exception. 
System.IndexOutOfRangeException: Index was outside the bounds of the array.

Solution

We can prevent the exception easily by using the value itself, instead of trying to access the value by index in each iteration:

var oddNumbersArray = new int[] { 1, 3, 5, 7, 9, 11, 13, 15, 17, 19 };
foreach (var number in oddNumbersArray)
{
    Console.WriteLine($"The odd number is: {number}");
}

This effectively prevents the exception:

The odd number is: 1
The odd number is: 3
The odd number is: 5
The odd number is: 7
The odd number is: 9
The odd number is: 11
The odd number is: 13
The odd number is: 15
The odd number is: 17
The odd number is: 19

DataTable – Incorrect Column Index

We create a method to render a static DataTable in a separate StaticDataRepository class:

public class StaticDataRepository
{
    public static DataTable GetGroceries()
    {
        var dataTable = new DataTable
        {
            TableName = "Groceries"
        };
        dataTable.Columns.Add("Id", typeof(int));
        dataTable.Columns.Add("Name", typeof(string));
        dataTable.Columns.Add("Description", typeof(string));

        dataTable.Rows.Add(1, "Macaroni", "Tasty Pasta");
        dataTable.Rows.Add(2, "Ramen", "Tasty Noodles");
        dataTable.Rows.Add(3, "Figaro Oil", "Olive Oil");
        dataTable.Rows.Add(4, "XYZ Lentils", "Nutritious Pulses");

        return dataTable;
    }
}

We then run a foreach loop on the data table and try to access all the rows:

var groceries = StaticDataRepository.GetGroceries();
for (var i = 0; i < groceries.Rows.Count; i++)
{
    var row = groceries.Rows[i];
    Console.WriteLine($"{row[0]}t {row[1]}t {row[2]}t {row[3]}");
}

The code raises an IndexOutOfRangeException because we are trying to access the 4th column (row[3]), which is not present in the data table:

Unhandled exception. 
System.IndexOutOfRangeException: Cannot find column 3.

It is quite possible that we might not be aware of the number of columns in the incoming data table.

We may try to access a column that does not exist and encounter the exception.

Solution

Let’s see how we can prevent the exception in this scenario:

var groceries = StaticDataRepository.GetGroceries();
 
foreach (DataRow grocery in groceries.Rows)
{
    foreach (var item in grocery.ItemArray)
    {
        Console.WriteLine($"{item}");
    }
 
    Console.WriteLine("********************");
}

We do not hardcode the indexes, rather we make use of the inbuilt properties such as ItemArray that is an array of objects:

1
Macaroni
Tasty Pasta
********************
2
Ramen
Tasty Noodles
********************
3
Figaro Oil
Olive Oil
********************
4
XYZ Lentils
Nutritious Pulses
********************

These were the most common situations where we can stumble upon the IndexOutOfRangeException.

Conclusion

We have learned about IndexOutOfRangeException in detail, the various scenarios where the exception gets raised, and the possible solutions.

int[] arr = new int[5] { 10, 30, 25, 45, 65};
Console.WriteLine(arr[0]);
Console.WriteLine(arr[1]);
Console.WriteLine(arr[2]);
Console.WriteLine(arr[3]);
Console.WriteLine(arr[4]);
Console.WriteLine(arr[5]); // throws IndexOutOfRange exception

int[] arr = new int[5] { 10, 30, 25, 45, 65};

Console.WriteLine(arr[0]);
Console.WriteLine(arr[1]);
Console.WriteLine(arr[2]);
Console.WriteLine(arr[3]);
Console.WriteLine(arr[4]);

if(arr.Length >= 6)
    Console.WriteLine(arr[5]);
}

static void Main()
{
    try
    {
        Console.WriteLine(arr[0]);
        Console.WriteLine(arr[1]);
        Console.WriteLine(arr[2]);
        Console.WriteLine(arr[3]);
        Console.WriteLine(arr[4]);
        Console.WriteLine(arr[5]); // throws IndexOutOfRange exception
    }
    catch(Exception ex)
    {
        Console.WriteLine("Error: {0}", ex.Message);
    }
}