Teradata 3807 error

In Teradata we can encounter an error [ Teradata Error 3807 SQLState 42s02 ] [Error 3807] [SQLState 42s02] Object ‘XYZ’ does not exists or Failed [3807: 42s02] Object ‘XYZ’ does not exists, where ‘XYZ’ is the name of the object we specified in the query . The cause of this error can be diagnosed very quickly. In this short post I will explain the reason for the error and how to solve it.

Introduction

Teradata is a company that helps organizations manage, store, and analyze large amounts of data through its range of products and services, such as its database management system. This system is capable of handling large data sets and enabling users to perform advanced queries and analysis on the data. Teradata is used in various industries to support decision making, improve business operations, and glean insights from data.

Error 3807 with SQLState 42S02 typically indicates that the object you are trying to reference in your SQL statement does not exist in the database. This could be because the object was never created, or because it was deleted at some point.

To troubleshoot this error, you will need to verify that the object you are trying to reference actually exists in the database. You can do this by checking the list of objects in the database and making sure that the object you are trying to access is listed.

If the object does not exist, you will need to create it before you can use it in your SQL statement. If the object was deleted, you will need to recreate it before you can use it again.

It is also possible that the error is being caused by a typo in the object name, or by using the wrong schema for the object. Make sure that you have spelled the object name correctly and that you are using the correct schema.

If you continue to have trouble, you may want to try accessing the object using a fully qualified name, including the schema name, to make sure that you are accessing the correct object. For example:

SELECT * FROM schema_name.object_name;

Teradata Error 3807 SQLState 42s02

The problem may occur during many DDL / DML operations run on a database. The below is the simplest example:

SELECT TOP 10 * FROM XYZ;

Cause

There are several reasons for this issue:

• you are trying to run a DML / DDL operation on a table that exists in another database
• you are trying to run a DML / DDL operation on a table that does not exist
• you are trying to run a SELECT / INSERT / UPDATE / DELETE etc. operation on a table that you do not have access to

Solution

You are trying to run a DML / DDL operation on a table that exists on a different database

If you execute operations on Teradata without specifying the database, all operations are execute on the default database for the user. Let’s check what database you are currently using:

SELECT DATABASE;

Next, let’s check in which database the table you are looking for is available:

SELECT DataBaseName, TableName, CreateTimeStamp, LastAlterTimeStamp
FROM dbc.TablesV
WHERE TableName='<your table name>';

If the table you need is available in another database, change the default database using a simple command:

DATABASE <your database name>;

or specify database in query:

SELECT TOP 10 * FROM <your database name>.XYZ;

You are trying to run a DML / DDL operation on a table that does not exist => SQLState 42s02

Please check if the table you are referring exists in your database. You can check it with the following query:

SELECT DataBaseName, TableName, CreateTimeStamp, LastAlterTimeStamp
FROM dbc.TablesV
WHERE DataBaseName='<your database name>'
AND TableName='<your table name>';

You are trying to run a SELECT / INSERT / UPDATE / DELETE etc. operation on a table that you do not have access to

In Teradata, you can quickly check which objects you have access to. To do this, use two views from the dbc database: AllRightsV and UserRightsV. The AllRightsV view stores permissions for all system users:

SELECT * 
FROM dbc.AllRightsV
WHERE UserName='<your user name>';

Whereas UserRightsV stores all the permissions granted to your user:

SELECT * 
FROM dbc.UserRightsV
WHERE UserName='<your user name>';

Summary

That’s all about: Teradata Error 3807 SQLState 42s02 Object ‘XYZ’ does not exists!

I hope this tutorial helped you to solve your problems!

Could You Please Share This Post? 
I appreciate It And Thank YOU! :)
Have A Nice Day!

БАЗА ДАННЫХ TERADATA

Я получаю больше строк, когда я делаю левое соединение. Моя базовая популяция в моей изменчивой таблице составляет 559 157 строк. И то, что я пытаюсь сделать, это вернуть только 559 157 строк из базового населения. Но после выполнения этого запроса:

SELECT distinct a.*, b.column1, b.column2, b.column3, b.column4, b.column5, b.column6, c.column3, SUM(c.column3) AS Total_Column3_Profit, AVG(c.column3) AS Column3_Profit_Average
,CASE 
WHEN b.column5 < a.column6 1
      ELSE 0
      END as column_open_flag
,CASE
WHEN a.column4 < 580 THEN 1
     WHEN a.column4 between 580 and 619 THEN 2
     WHEN a.column4 between 620 and 639 THEN 3
     WHEN a.column4 between 640 and 659 THEN 4
     WHEN a.column4 between 660 and 679 THEN 5
     WHEN a.column4 between 680 and 699 THEN 6
     WHEN a.column4 between 700 and 739 THEN 7
     WHEN a.column4 >= 740 THEN 8
     ELSE 0
     END as column4_band
FROM volatile_table1 a
LEFT JOIN database_table1 b
ON a.column1 = b.column0
LEFT JOIN volatile_table2 c
ON a.column1 = c.column2
GROUP BY a.column1
,a.column2
,a.column3
,a.column4
,a.column5
,a.column6
,b.column1
,b.column2
,b.column3
,b.column4
,b.column5
,b.column6
,c.column3

Теперь я возвращаю более 2 000 000 строк. Поэтому я хотел попробовать предложение UNION. Вот мой обновленный запрос:

SELECT a.column1, a.column2, a.column3, a.column4, a.column5, a.column6
,CASE 
WHEN b.column5 < a.column6 1
      ELSE 0
      END as column_open_flag,
CASE
WHEN a.column4 < 580 THEN 1
     WHEN a.column4 between 580 and 619 THEN 2
     WHEN a.column4 between 620 and 639 THEN 3
     WHEN a.column4 between 640 and 659 THEN 4
     WHEN a.column4 between 660 and 679 THEN 5
     WHEN a.column4 between 680 and 699 THEN 6
     WHEN a.column4 between 700 and 739 THEN 7
     WHEN a.column4 >= 740 THEN 8
     ELSE 0
     END as column4_band
FROM volatile_table1 a
UNION
SELECT b.column1, b.column2, b.column3, b.column4, b.column5, b.column6
FROM database_table1 b
UNION
SELECT c.column3, SUM(c.column3) AS Total_Column3_Profit, AVG(c.column3) AS Column3_Profit_Average
FROM volatile_table2 c
GROUP BY a.column1
,a.column2
,a.column3
,a.column4
,a.column5
,a.column6
,b.column1
,b.column2
,b.column3
,b.column4
,b.column5
,b.column6
,c.column3

Теперь я продолжаю получать ошибку 3807: Объект «а» не существует. я побежал

HELP volatile table

Запрос, и он говорит, что обе изменчивые таблицы существуют. Может ли кто-нибудь указать мне направление моей ошибки? (Я также попытался удалить первый оператор case, который ссылается на b.column5

РЕДАКТИРОВАТЬ:

Я обновил это из комментариев, и теперь я получаю сообщение об ошибке 3653. «Все списки выбора не содержат одинакового количества выражений:

SELECT distinct a.column1, a.column2, a.column3, a.column4, a.column5, a.column6, b.column1, b.column2, b.column3, b.column4, b.column5, b.column6, c.column3, SUM(column3) AS Total_Profit, AVG(column3) AS Profit_Averag
,CASE 
WHEN b.column5 < a.column6 1
      ELSE 0
      END as column_open_flag
,CASE
WHEN a.column4 < 580 THEN 1
     WHEN a.column4 between 580 and 619 THEN 2
     WHEN a.column4 between 620 and 639 THEN 3
     WHEN a.column4 between 640 and 659 THEN 4
     WHEN a.column4 between 660 and 679 THEN 5
     WHEN a.column4 between 680 and 699 THEN 6
     WHEN a.column4 between 700 and 739 THEN 7
     WHEN a.column4 >= 740 THEN 8
     ELSE 0
     END as column4_band
FROM 
(
SELECT a.column1, a.column2, a.column3, a.column4, a.column5, a.column6
FROM volatile_table1 a
UNION ALL
SELECT b.column1, b.column2, b.column3, b.column4, b.column5, b.column6
FROM database_table1 b
UNION ALL
SELECT c.column3, SUM(c.column3) AS Total_Column3_Profit, AVG(c.column3) AS Column3_Profit_Average
FROM volatile_table2 c
GROUP BY 1
) d
GROUP BY a.column1
,a.column2
,a.column3
,a.column4
,a.column5
,a.column6
,b.column1
,b.column2
,b.column3
,b.column4
,b.column5
,b.column6
,c.column3

Если вы хотите агрегировать после выполнения объединения all, используйте подзапрос или CTE. Я думаю, что запрос будет выглядеть примерно так:

select . . .
from (select column1, column2, column3, column4, column5, . . .
      union all
      select column1, column2, column3, column4, column5, . . .
      union all
      select column1, column2, column3, column4, column5, . . .
     ) abc
group by GROUP BY a_column1, column2, column3, column4, column5